How to grep a part of string form a string

Question

0.00/5 (No votes)

See more:

Hi.

I give below command
$ /abc/tej --version
output-
abc version = 1234R
xyz Version = P2vfs(5.1.5-1)

I want to grep the above command so that i get only 5.1 value.

I did it using /abc/tej --version | grep ^xyz | sed 's/.*(//' | head -c 3.

Can anyone help me to get a simpler command or regex to get the substring

Thanks in advance.

Posted 20-Jan-16 22:34pm

Member 12018498

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2016-01-20T23:30:00

Solution 1

As a regex it's pretty simple:

(?<=Version = .*?\()\d+\.\d+(?=\.\d+-\d+\))

Posted 20-Jan-16 23:30pm

OriginalGriff

Comments

Member 12018498 21-Jan-16 6:20am

Thank you for suggestion. and sorry, i didn't get you. I am new to regex or grep usage, Do you mean use this regex for grepping?. I did like this /abc/tej --version | grep "(?<=Version = .*?()\d+.\d+(?=.\d+-\d+))". but I didn't get any output