As brought up in the post
https://www.reddit.com/r/cpp/comments/40lm8o/lambdas_are_dangerous/ with lambdas in inline functions you can run into ODR violations and thus undefined behavior.
There is also a stack overflow discussion at
http://stackoverflow.com/questions/34717823/does-using-lambda-in-header-file-violate-odr
While, the ultimate fix may rely with the Core Working Group, I think here is a work around.
The basis for the trick come from Paul Fultz II in a post about constexpr lambda. You can find the post at
http://pfultz2.com/blog/2014/09/02/static-lambda/
Here is some problematic code from the stackoverflow discussion. The lambda may have a different type across translation units and thus result in different specializations of for_each being called for different translation units resulting in ODR violations and thus undefined behavior.
inline void g() {
int arr[2] = {};
std::for_each(arr, arr+2, [] (int i) {std::cout << i << ' ';});
}
Here is a simple fix that will prevent the ODR violation.
template<typename T>
auto addr(T &&t)
{
return &t;
}
static const constexpr auto odr_helper = true ? nullptr : addr([](){});
template <class T = decltype(odr_helper)>
inline void g() {
int arr[2] = {};
std::for_each(arr, arr+2, [] (int i) {std::cout << i << ' ';});
}
We create a static const constexpr null pointer with the type of a lambda. If lambdas are different types across different translation units then
odr_helper
will have different types across different translation units. Because g now is a template function using the type of
odr_helper
, g will be a different specialization across different translation units and thus will not result in an odr violation.
Also note that because T is defaulted, g can be used without any changes from before.
ideone at
https://ideone.com/NdBpXN