Introduction
This article describes how to display images which are stored in a database. You can use <IMG>
tag to display images stored in the database by calling another ASP page in SRC
attribute of <IMG>
tag.
For example:
<IMG SRC="ShowPicture.asp?PhotoId=1">
where PhotoId
is the ID stored in the database.
Using the code
Following are the steps which needs to be executed:
- Create table Users in MS-Access or SQL server.
- Create ShowPicture.asp page.
- Call this page using
<IMG>
tag wherever required.
Create table with the following structure:
Table name: Users
user_id
(AutoNumber)
user_name
(Text)
user_photo
(Ole Object - For MS-Access, and Image data type for SQL server).
Code
ShowPicture.asp is used to display images. You need to pass user ID in querystring, and for that user ID, image will be displayed. Following is the code:
Dim sql
Dim rs
Dim conn
Dim userID,str
userID = Request("PhotoId")
If userID = "" Then userID = 0
Set conn = Server.CreateObject("ADODB.Connection")
Set rs = Server.CreateObject("ADODB.Recordset")
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
str = "SELECT user_photo FROM users where user_id =" & userID
rs.Open str, conn,3,3
if rs.eof then
Response.End
else
Response.ContentType = "image/gif"
Response.BinaryWrite(rs("user_photo"))
end if
rs.Close
conn.Close
set rs = Nothing
set conn = Nothing
Please note that "Response.contentType
" will depend on the type of content you would like to display. For example, to display jpg image, following will be the code:
Response.ContentType = "image/jpg"
To use above page for displaying images, following is the example:
<IMG SRC="ShowPicture.asp?PhotoId=1">
<IMG SRC="ShowPicture.asp?PhotoId=2">
Upload Image
Following example shows how to upload images in database by using ASPSmartUpload
component. More information about this component can be found here.
Following is the code to upload image:
<FORM METHOD="POST" ACTION="saveFile.asp"
ENCTYPE="multipart/form-data" NAME="UploadForm">
<center>
Employee Name : <INPUT TYPE="TEXT" NAME="USERNAME" SIZE="30"><br>
<INPUT TYPE="FILE" NAME="UPLOADFILE1" SIZE="50">
</center>
<BR>
<center><INPUT TYPE="SUBMIT" VALUE="Upload"
id=SUBMIT1 name=SUBMIT1></center>
</FORM>
Code to save the image in the database:
Dim myupload
intCount=0
Set myupload = Server.CreateObject("aspSmartUpload.SmartUpload")
myupload.Upload
Set Conn = Server.CreateObject("ADODB.Connection")
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
Set Rs = Server.CreateObject("ADODB.recordset")
Rs.Open "SELECT user_id,user_name,user_photo FROM users", Conn,3,3
For each file In myupload.Files
If not file.IsMissing Then
Rs.AddNew
file.FileToField Rs.Fields("user_photo")
Rs("user_name") = myupload.Form("USERNAME")
Rs.Update
intCount = intCount + 1
End If
Next
Response.Write(intCount & " file(s) uploaded.")
Comments
It is always better to store images in the file system rather than storing in the database. Only image path can be stored in the database. However, storing images in the database depends on requirements and needs.