How do I make a server control with 2 child controls, AND design support? [modified] - ASP.NET Discussion Boards

hi all..........

pls can anybody help me to display cursor wait while page is loading

my page have the code like this

thank you

Can u post all your page HTML code??? not just the frameset part

Best Regards,
Haissam Abdul Malak

>>> HOMEWORK ALERT <<<

ASP.NET 1.1

a) How Visual Studio compiles the whole ".cs" files and put them as a single assembly, <project_name>.dll, into the bin folder.
b) How can we do this compilation manually?
c) Why the ".aspx" pages are not included into it?
d) How the runtime will link the "aspx" files with this output DLL in the BIN folder?
e) Whether at runtime any classes are getting generated which pertain to each ".aspx" files? If, whats is the need for compiling only the ".aspx.cs" files?

ASP.NET 2.0

a) aspnet_compiler will compile the whole project and produce the output into a single DLL. How to do this manually?
b) Where the App_Code files got compiled?
c) Even though I put both my ".aspx" files and ".aspx.cs" files in a virtual directory instead of compiling, how things are getting worked at runtime?

Please request you to provide a clean picture on these.

Arun

Is this your homework or pre-interview questions?

Both. I have asked a lot of people whom I know to make things clear, but all gone in vague. I know the general views which were mentioned in MSDN, but I need something in "CORE".
If you can help me, thanks a lot.

Arun

There's a practice of not doing people's homework here.

Sorry.

I need to make a server control for controlling layout on my page. For various reasons, I don't want to use a master template, and the easiest approach is to make a server control which exposes two child controls. The content on my webpage will be added to these two exposed child controls, which in turn will be rendered surrounding by the layout HTML I need. Everything works fine, except I have no design-time support for it. In other words, I can compile the code, but I have no intellisense on in, which is a major inconvience. I've tried adding the standard attributes to the exposed properties, but I keep getting the "Content is not allowed between the opening and closing tags..." error. Can anyone tell me which attributes I need to add to my control class or its properties in order to get Visual Studio 2005 intellisense to work with the TopContent and BottomContent properties? Thanks!

// ######################################
// what the useage should look like :
// ######################################
<cc:LayoutTemplate runat="server">
<TopContent>

</TopContent>
<BottomContent>

</BottomContent>
</cc:LayoutTemplate>

// ######################################
// control definition :
// ######################################
public class LayoutTemplate : System.Web.UI.WebControls.WebControl, INamingContainer, IPostBackDataHandler, IPostBackEventHandler
{

#region FIELDS

private Control _topContent;
private Control _bottomContent;

#endregion

#region PROPERTIES

[PersistenceMode(PersistenceMode.InnerDefaultProperty),
DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
public Control TopContent
{
get
{
return _topContent;
}
}

[PersistenceMode(PersistenceMode.InnerDefaultProperty),
DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
public Control BottomContent;
{
get
{
return _bottomContent;
}
}

#endregion

#region CTORS

public LayoutTemplate(
)
: base(HtmlTextWriterTag.Div)
{
_toptContent = new Control();
_bottomContent = new Control();
this.Controls.Add(_topContent);
this.Controls.Add(_bottomContent);
}

#endregion

#region METHODS

protected override void RenderChildren(
HtmlTextWriter writer)
{

LiteralControl l = new LiteralControl(" ... top layout html here ... ");
l.RenderControl(writer);

this.TopContent.RenderControl(writer);

l = new LiteralControl(" ... middle layout html here ... ");
l.RenderControl(writer);

this.BottomContent.RenderControl(writer);

l = new LiteralControl(" ... bottom layout html here ... ");
l.RenderControl(writer);

// suppress child rendering
//base.RenderChildren(writer);
}

public void RaisePostDataChangedEvent(
)
{
}

void IPostBackEventHandler.RaisePostBackEvent(
string arg
)
{
}

public bool LoadPostData(
string postDataKey,
NameValueCollection postData
)
{
return true;
}

#endregion

}

-- modified at 8:45 Monday 4th December, 2006

Nvm - got a solution on the ever-helpful http://forums.asp.net - changing the exposed control type to PlaceHolder instead of Control fixed it. Good enough solution.

Hi I have a page in which I have used another page in . In that <ifram> page there is a text box i-e named txtPO. How can i access that txtPO in that Page in which <iframe> page is used.

dear,

you can access it from javascript

document.frames['IFRAMEID'].document.getelementById('txtPO').value

where IFRAMEID is the id of your iframe

Happy Coding

Best Regards,
Haissam Abdul Malak

hi i want to display an image from datadase in a TemplateColumn, and when i click on this image an event will happend (like: another image is displayed
in another place in the same page)
plz help me Sigh | :sigh:

thanks for ur time :rose

Rania
.net programer

This isn't a complete solution but hopefully it will get you started....
This is a brief sample of a datagrid I created in v1.1 that had a "View Details" image button in the 1st column of the datagrid. This image was the same for each row with an image filepath that I hardcoded:

1) datagrid id="dgrdSample"
2) Add OnItemCommand="dgrdSample_ItemCommand" to the datagrid tag
3) First column was a "ButtonColumn":
<asp:ButtonColumn ButtonType="LinkButton" HeaderText="Sample" Text="<img src='../images/viewDetails.jpg' border='0'>" CommandName="select"></asp:ButtonColumn>

4) Add this to your codebehind:
protected void dgrdSample_ItemCommand(Object s, DataGridCommandEventArgs e)
{
//Add your code here for whatever you wish to happen
}

Hope this helps get you started.

-Goalie35

thank u Goalie35
it is so helpful
but i want to make the imagebutton fetch the image url from the database
can u tell me how
thanks

rony

How to get the display of Datagrid in runtime.(C#+Asp.net)
i m not able to view the Grid.
Regards
Shriya

Hi,
This LINK[^] may help you out.

Mubashir

Every job is a self portrait of the person who did it.

R u getting values from a database.

hi

give autogeneratecolumns=true in datagrid html form

regards
saravanan Laugh | :laugh:

Dear All
i'm using the query string to hold values between webforms but i'm facing a problem with special characters ther become something else
the % becomes / and some other code...
how can i get the query string varaibles through javascript and return them as they are?
tried the escape and unescape function but it also didn't work

here's a sample of the key i'm sending in the query string:

chvVXMSF1BzwcdoDe899FfSxnhSrmxrr219T6Uvjv7MjryZE5QSx69RqVW7LmyFVyGucC9iV%252FVFVTW830hbjoYEO0U%252BHQXDaf5txVcKGAWcr6a7Wo3ZSyFMF%252FxHXbjO5uWFScCM%252Bs8X57ihH5nanC9KeLTErLX3VopuPpNcK%252BLivM4mA9%252FVJ9aqYvuBS%252F4NsfLVZtFIsQbv0EOqkT4%252BLpv8Cej%252F%252F9zt7S3fW%252F1wLJ8gO0h%252BNdQTHiFq%252BSjXwtO9s7hcxzz1Gxr2OQV0%252BwO9zAJLLL5mkVLIXx2uaPXLhAbFLNMOxNPAlQpDFPFXJLfiYwfV7ucSPgqlU%252Fy3wjN2QKzyMVWj8%252BZ8GYuPGOndBsQ3SeCYrButJIMOMIGxWLRvs

i can't move it as is Frown | :(

Best Regards
3ala2 Smile | :)

Dear,

from javascript use the unescape(urmessage) to return your query string into a readable one.

Happy Coding
http://dotnetslackers.com/community/blogs/haissam/default.aspx

Best Regards,
Haissam Abdul Malak

hi all.....

can anybody give some idea to display an hourglass until the pages get loaded into the frames of page.

in my page i have 4 frames and m displaying each frame with an aspx page.

i want to display an hourglass until the last page get loaded.

one thing there is no order of pages loading in.

so pls give me some idea

thanks in advance

Dear,
you can use the javascript setTimeOut function which will check the frames if loaded every specific time ( you set the specific time) below is an example

window.onload = function() {setTimeout(\"if(self.parent.frames['FRAME3'].document.readyState!='complete'){document.body.style.cursor = 'Wait';}else{document.body.style.cursor = 'default'}",100)}

Repeat this for each frame you have.

Happy Coding
http://dotnetslackers.com/community/blogs/haissam/default.aspx

Best Regards,
Haissam Abdul Malak

thanks for quick reply.

m not clear can u pls explain me where should i need to write this.

thank you

Dear,
first create a function in javascript

function checkloaded(id1,id2,id3,id4)
{
setTimeout("if(self.parent.frames[id1].document.readyState!='complete' | self.parent.frames[id2].document.readyState!='complete'| self.parent.frames[id3].document.readyState!='complete' |self.parent.frames[id4].document.readyState!='complete'){document.body.style.cursor = 'Wait';}else{document.body.style.cursor = 'default'}",100)}
}

now onload in your tag, call this function and send your 4 frames id as parameters

Happy Coding
http://dotnetslackers.com/community/blogs/haissam/default.aspx

Best Regards,
Haissam Abdul Malak

thank u very much

but i dont have body tag.

thank you