Issue with SetBitmap - C / C++ / MFC Discussion Boards

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Re: Printer Control

led mike6-Jan-07 18:55

led mike

6-Jan-07 18:55

Wow. Did you try looking at the articles under "Printing" under the "General C++" section of CodeProject?

led mike

Re: Printer Control

Rajesh R Subramanian7-Jan-07 18:34

Rajesh R Subramanian

7-Jan-07 18:34

LateNightsInNewry wrote:
With the advance from DOS3.3 to Win XP

Nobody can give you wiser advice than yourself. - Cicero
ப்ரம்மா

Automatically Startup...

M266-Jan-07 10:44

M26

6-Jan-07 10:44

Some body tell me please how to make my application a program that is automatically start up after windows starting up?
In other word what is the function or source code I have to insert to perform that.

Thanks in advance.

Re: Automatically Startup...

Mark Salsbery6-Jan-07 11:27

Mark Salsbery

6-Jan-07 11:27

For an application that runs before a user logs in you can make your app a Windows
service application[^]. These typically have no user interface.

There's also a list of startup programs in the registry for both all users and the current user:
HKEY_LOCAL_MACHINE\Software\Microsoft\Windows\CurrentVersion\Run
HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Run

Mark

Re: Automatically Startup...

Alexander ^M.,6-Jan-07 13:32

Alexander ^M.,

6-Jan-07 13:32

An alternative way is putting a shortcut into the autostart start menu folder.

Don't try it, just do it! Wink | ;-)

Re: Automatically Startup...

Bram van Kampen6-Jan-07 15:37

Bram van Kampen

6-Jan-07 15:37

Put it in the [Start][Programs][Startup] menu Option.
This is by far the safest.

LateNightsInNewry

Re: Automatically Startup...

S Douglas6-Jan-07 21:14

S Douglas

6-Jan-07 21:14

M26 wrote:
automatically start up after windows

If your talking about a normal user mode application and not creating a service, then take a look at this article, Adding your application to the Windows Startup[^]. The article isn't very well written but the class is decent and does indeed work.

Good Luck

I'd love to help, but unfortunatley I have prior commitments monitoring the length of my grass. :Andrew Bleakley:

Issue with SetBitmap

CoffeeAddict196-Jan-07 8:33

CoffeeAddict19

6-Jan-07 8:33

I'm trying to change the face of a button to a solid color bitmap, but for some reason it's just displaying the button without the bitmap on the front. Here is the code:

CGameOptionsDialog::CGameOptionsDialog(char* lpszName) : CDialog(lpszName)
{
	//initialize graphics
	Problem = mem_DC.CreateCompatibleDC(NULL);
	CBitSolidBkButton.CreateBitmap(20, 20, mem_DC.GetDeviceCaps(PLANES), mem_DC.GetDeviceCaps(BITSPIXEL), NULL);
	mem_DC.SelectObject(CBitSolidBkButton);
	NewSolidBkColor = RGB(220, 20, 60); //default
	NewSolidBkBrush.CreateSolidBrush(NewSolidBkColor);
	mem_DC.SelectObject(NewSolidBkBrush);
	mem_DC.FloodFill(0, 0, NewSolidBkColor);
}

and where SetBitmap is called...

BOOL CGameOptionsDialog::OnInitDialog()
{
	CDialog::OnInitDialog();

...

//initialize controls
	SolidColorSelectButton.Create(" ", WS_CHILD|WS_VISIBLE|BS_BITMAP, CRect(145, 55, 165, 75), this, ID_CHANGE_BK_COLOR);
	Gradient1ColorSelectButton.Create(" ", WS_CHILD|WS_VISIBLE|BS_BITMAP, CRect(145, 85, 165, 105), this, ID_CHANGE_GRADIENT1_COLOR);
	Gradient2ColorSelectButton.Create(" ", WS_CHILD|WS_VISIBLE|BS_BITMAP, CRect(175, 85, 195, 105), this, ID_CHANGE_GRADIENT2_COLOR);
	SolidColorSelectButton.SetBitmap((HBITMAP)CBitSolidBkButton);

if(Problem == FALSE)
        MessageBox("Problem", "MSG", MB_OK);

        return TRUE;
}
</code>

The "Problem" message box isn't popping up, so I'm pretty shure that the device context got initialized right (it's a class member, so scope isn't an issue). Any ideas on what is wrong? Thanks.

Re: Issue with SetBitmap

Warren Stevens6-Jan-07 10:14

Warren Stevens

6-Jan-07 10:14

1) try adding a bitmap resource, and then using that in your line:

SolidColorSelectButton.SetBitmap((HBITMAP)CBitSolidBkButton);

that way you can tell whether it's a bitmap-creation issue OR a button creation issue.

2) You have the line:
mem_DC.SelectObject(CBitSolidBkButton);
Did you select the bitmap back OUT of the device context later on???

www.IconsReview.com[^]
Huge list of stock icon collections (both free and commercial)

Re: Issue with SetBitmap

CoffeeAddict196-Jan-07 11:52

CoffeeAddict19

6-Jan-07 11:52

blah...I gave it up and did something similar:

http://www.codeproject.com/buttonctrl/colorbox.asp[^]

What is the message that occur when user press enter?

Max++6-Jan-07 6:58

Max++

6-Jan-07 6:58

I want this in my project.

User key in data in Edit Control and press enter,
then program will get these data for process some job...
My question is
What is the message that occur when user press enter?
I try to use WM_CHAR and WM_KEYDOWN but no work.

Please help me to solve this problem

Re: What is the message that occur when user press enter?

Mark Salsbery6-Jan-07 7:25

Mark Salsbery

6-Jan-07 7:25

For a single line edit control pressing Enter key is the same as clicking the default button
(the button with the BS_DEFPUSHBUTTON style) - typically OK or Cancel in a dialog.

If you want to catch the Enter key press you can do it in response to a WM_KEYDOWN message sent
to the edit control but the edit control needs the ES_WANTRETURN|ES_MULTILINE styles set.

Mark

Re: What is the message that occur when user press enter?

Warren Stevens6-Jan-07 10:06

Warren Stevens

6-Jan-07 10:06

The other poster answered your question, but for future reference on other message questions, add a "PreTranslateMessage" in your dialog and you can see all the messages that come through.

Smile | :)

www.IconsReview.com[^]
Huge list of stock icon collections (both free and commercial)

unsigned int 12 bits

ikbahrian6-Jan-07 3:59

ikbahrian

6-Jan-07 3:59

Actually I want to generate random 12 bit unsigned int and random 4 bit signed int and stores in 2 bytes(unsigned int) which is as follow.

2 bytes unsigned int = 12 bit unsigned int*pow(10,4-bit signed int)

Thanks in advance-

Re: unsigned int 12 bits

CPallini6-Jan-07 4:18

CPallini

6-Jan-07 4:18

If you have NOT constraints on the ranges of both the 12-bit unsigned numbers and 4-bit signed ones, then you can generate and store directly a 16-bit unsigned random number (the result is the same).
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: unsigned int 12 bits

ikbahrian6-Jan-07 4:23

ikbahrian

6-Jan-07 4:23

no dear I have to take in to account the range and the storage.

OK. What are the ranges?

CPallini6-Jan-07 4:45

CPallini

6-Jan-07 4:45

OK. What are the constraints on the ranges? Confused | :confused:

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: OK. What are the ranges?

ikbahrian6-Jan-07 5:11

ikbahrian

6-Jan-07 5:11

unsigned int 12 bit (0 -> +4095)
the size should be 12 bit;

signed int 4 bit (-16 -> +15)
the size shoud be 4 bit;

thx.

Re: OK. What are the ranges?

Dominik Reichl6-Jan-07 6:08

Dominik Reichl

6-Jan-07 6:08

Processors can only access memory by 8-bit blocks, i.e. bytes.

If spaces is a criterion, you'll need to pack your 12-bit values into bytes yourself. You can for example store them like this:

8-bit bytes  : XXXXXXXX YYYYYYYY ZZZZZZZZ
12-bit values: JJJJJJJJ JJJJKKKK KKKKKKKK

i.e. use 3 bytes to store 2 12-bit values.

To store and extract the values, use simple bit-shifting. For mapping the 4-bit parts to signed ints, you can either use a lookup table or write a simple function that gets the MSB of the 4-bit value and map it to the MSB of the byte and adjust the rest accordingly.

Too many passwords to remember? Try KeePass Password Safe!

Re: OK. What are the ranges?

CPallini6-Jan-07 6:27

CPallini

6-Jan-07 6:27

ikbahrian wrote:
signed int 4 bit (-16 -> +15)

You're wrong, since -8->+7 is the range for a 4-bit signed number. Moreover, you're NOT imposing constraints over ranges (you want to fully exploit ranges) hence you can safely follow the suggestion posted below by Joergen Sigvardsson
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: unsigned int 12 bits [modified]

Jörgen Sigvardsson6-Jan-07 6:07

Jörgen Sigvardsson

6-Jan-07 6:07

uint16 num = uint16(rand() % 65535)

should do the trick. To get the components from the number:

uint16 n12bit = num & 4095; // 4095 = 0000111111111111b
int8 n4bit = ((num >> 12) & 7) * (((num >> 12) & 8) ? -1 : 1); // 7 = 111b, 8 = 1000b which is the sign bit

[edit]Per Mark's bug report! Wink | ;)

{/edit]

Last modified: 36mins after originally posted --

Re: unsigned int 12 bits

Mark Salsbery6-Jan-07 6:17

Mark Salsbery

6-Jan-07 6:17

Good answer! Smile | :)

I would change 1 thing - use those unused upper 4 bits instead of reusing the lower 4

int8 n4bit = ((num >> 12) & 7) * ((num & 8) ? -1 : 1); // 7 = 111b, 8 = 1000b which is the sign bit

(per the OPs spec Smile | :)

)

Cheers!
Mark

Re: unsigned int 12 bits

Jörgen Sigvardsson6-Jan-07 6:43

Jörgen Sigvardsson

6-Jan-07 6:43

int8 n4bit = ((num >> 12) & 7) * (((num >> 12) & 8) ? -1 : 1); // 7 = 111b, 8 = 1000b which is the sign bit

Good catch! I also fixed your code a little (you forgot to shift for getting the sign bit)

Re: unsigned int 12 bits

Mark Salsbery6-Jan-07 6:44

Mark Salsbery

6-Jan-07 6:44

Thanks!

Re: unsigned int 12 bits

ikbahrian7-Jan-07 3:22

ikbahrian

7-Jan-07 3:22

thanks;)

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