C / C++ / MFC

bkelly13 wrote:

That means it has two arguments

CC operator+( CC &source1 ); 

CC CC::operator+( CC &source1)
   {
    CC result = *this;
    double sum = source1.X + X;
    result.X = sum ;
//    repeat for Y
//    repeat for Z
    return result;
   };

double sum = X + source1.Get_X();
result.Set_X = sum;

class Foo
{
private:
    
    int x;

public:

    Foo(int _x)
    {
        x = _x;
    }
    
    inline int AddX(const Foo& B)
    {
        return x + B.x;
    }
};

Foo f1(10);
Foo f2(2);
int y = f1.AddX(f2);

class Foo
{
private:
    
    int x;

public:

    Foo(int _x)
    {
        x = _x;
    }
    
    inline int AddX(const Foo& B)
    {
        return x + B.x;
    }
    
    Foo& operator+(const Foo& B)
    {
        Foo a;
        a.x = x + B.x // Or a.x = this.x + B.x
    }
};

Foo& operator+(const Foo& B)
{
    x = x + B.x;
    return *this;
}

class Foo
{
public:
	
	Foo(int _x)
	{
		x = _x;
	}
	
	Foo& Add(const Foo& B)
	{
		Foo a;
		a.x = x + B.x;
		return a;
	}
	
private:
	
	int x;
};

Foo a(10);
Foo b(20);
Foo c = a.Add(b);

class Foo
{
public:
	
	Foo(int _x)
	{
		x = _x;
	}
	
	Foo& operator+(const Foo& B)
	{
		Foo a;
		a.x = x + B.x;
		return a;
	}
	
private:
	
	int x;
};

Foo a(10);
Foo b(20);
Foo c = a.opeator+(b);
Foo d = a + b;

Luc Pattyn wrote:

CC result= *this;
does not create anything; it declares a reference called result to a type CC and sets it equal
to *this, so now result and this are one and the same object.

CC result= *this;

ClassA::ClassA( const ClassA &from)
     :member1( from.member1 )
     ,member2( from.member2 )
     ,.... etc
{}

......
CC operator+( CC &source ) const;
......
CC CC::operator+( CC &source ) const   
{
     CC result = *this;
     double sum = source.Query_X() + X;
     result.Set_X( sum );
     return result;
}

int* x = new int[1000];

void foo(int i)
{
   if(i>0 && i<1000)
   {
      x[i] = 0;
   }
   else
   {
      // print error.
      // assert.
      // throw an exception.
   }
}

CPallini wrote:

Possibly documentation helps.

Luc Pattyn [Forum Guidelines] [My Articles]

---

Voting for dummies? No thanks.

---