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Thanks for your vital information.
Can you tell how can i check GDI resources leak?Please help me
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Take a look at your program and see what resources you are using (Fonts, Brushes, Bitmaps etc) and whether you are correctly disposing of them when finished. This is basic Windows programming that you really need to study and understand.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Was what? 
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Man who follows car will be exhausted." - Confucius
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MsmVc wrote: Application show "A required resource was" this message.
When exactly does it do this? Note: A response such as, "When the app is running." is not a useful answer.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Man who follows car will be exhausted." - Confucius
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David, I Googled that exact message and found a few hits, strangely enough. See my last response to the OP.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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I am very new to putting inheritance into practice, so please treat me gently ! I am trying to create a new class CTimeEx to provide extra functions to CTime. The problem is that from the client’s point of view, the derived class doesn’t seem to be initialised.
My derived class definition is :-
class CTimeEx : public CTime
{
public:
CTimeEx();
CTimeEx(const CTime& TimeIn) : CTime(TimeIn) {};
….
And my client invocation is :-
CTime timeCurrent(CTime::GetCurrentTime());
CTimeEx timeExTest(timeCurrent);
When I trace through the calls, I see the base class contructor being called with timeCurrent, but when initialisation of the derived class completes, the time value for the CTimeEx object is still in it’s uninitialised state.
I’m sure that I’m probably doing something very stupid, but, having struggled with it for quite some time, I now need someone elses advice !! Thanking you in advance !
Doug
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Could you please post the complete code of your class, using the 'code block' button?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Hi, I've found the reason for my original problem, but let me explain. I was originally trying to get operator= function coded, but was floundering and trying various things. For some daft reason, at some stage, I included a private variable m_time of type time in the derived class and this (of course !) was causing the initialisation problem. However, I am still left with the problem of how to deal with operator= !!
I've included my class below (hopefully in a code block - never done this before !)
<pre>// TimeEx.h: interface for the CTimeEx class.
//
//////////////////////////////////////////////////////////////////////
#if !defined(AFX_TIMEEX_H__48005666_3D56_42ED_8ADD_8F9B119E194D__INCLUDED_)
#define AFX_TIMEEX_H__48005666_3D56_42ED_8ADD_8F9B119E194D__INCLUDED_
#if _MSC_VER > 1000
#pragma once
#endif // _MSC_VER > 1000
class CTimeEx : public CTime
{
public:
CTimeEx();
CTimeEx& CTimeEx::operator=(const CTimeEx& timeSource);
CTimeEx(const CTime& TimeIn) : CTime(TimeIn) {};
virtual ~CTimeEx();
};
#endif // !defined(AFX_TIMEEX_H__48005666_3D56_42ED_8ADD_8F9B119E194D__INCLUDED_)
// TimeEx.cpp: implementation of the CTimeEx class.
//
//////////////////////////////////////////////////////////////////////
#include "stdafx.h"
#include "Test_Inhehitancy.h"
#include "TimeEx.h"
#ifdef _DEBUG
#undef THIS_FILE
static char THIS_FILE[]=__FILE__;
#define new DEBUG_NEW
#endif
//////////////////////////////////////////////////////////////////////
// Construction/Destruction
//////////////////////////////////////////////////////////////////////
CTimeEx::CTimeEx()
{
}
CTimeEx::~CTimeEx()
{
}
CTimeEx& CTimeEx::operator=(const CTimeEx& timeSource)
{
// ?????????
}
</pre>
Doug
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Are you looking for:
CTimeEx & CTimeEx::operator=(const CTimeEx & timeSource)
{
CTime::operator=(timeSource);
return *this;
}
?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Thank you so much !!
I now ask myself WHY I couldn't see this !! (It always seems obvious after someone has showed you, doesn't it !)
Thanks again !
Doug
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You are welcome.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Where do you save the time value that you send to your constructor?
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Hi Richard, As you can see from an earlier message on the thread, I had accidently tripped myself up ! I'm all sorted now - thanks anyway !
Doug
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Hi all,
i execute my application when it run for some time i found the icon of message box not display.
if i execute it again after stop its works fine.
now what can i do.
thanks in advance.
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Le@rner wrote: what can i do
either fix your bug yourself, or provide sufficient information so somebody can actually help you.
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Le@rner wrote: now what can i do.
Be a little clearer in your explanation. For example, how are you calling MessageBox()?
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Man who follows car will be exhausted." - Confucius
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like this
MessageBox(_T("Hello"),_T("Message"),MB_ICONINFORMATION);
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There one c++ project call a web service(WAR package), the WAR package call a JNI DLL(java native code, write by c++) I want to debug this JNI dll. But I donot know how to goto the debug code.
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Hi,
I have only vc++ project file(.dsp). i want all cpp file function name in this project(.dsp) file. It is possible?
if possible please give sample code or url
Regards,
M.Mathivanan
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if you would have opened .dsp file in a notepad or something like that, probably you would have understood what all you can get from it. 
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In my case, I want to create one interface class and use it to employee the drived class implementation. The sample codes are as follows.
CInterfaceClass
{
public:
CInterfaceClass(){};
virtual ~CInterfaceClass(){};
virtual int Func1() = 0;
virtual int Func2() = 0;
virtual int Func3() = 0;
}
And the interface class will be used the DLL project and the client project.
Here the drived class in the DLL project and it will be exported and be used by the client project:
CMyDLLClass1 : public CInterfaceClass
{
public:
CMyDLLClass1 (){};
virtual ~ CMyDLLClass1 (){};
virtual int Func1();
virtual int Func2();
virtual int Func3();
private:
vector<...> ....
map<...> ....
}
And another DLL project may like this...
CMyDLLClass2 : public CInterfaceClass
{
public:
CMyDLLClass2 (){};
virtual ~ CMyDLLClass2 (){};
virtual int Func1();
virtual int Func2();
virtual int Func3();
private:
vector<...> ....
map<...> ....
}
In the client project, I want to use the exported class like this.
CInterfaceClass* pMyDllClass1 = new CMyDLLClass1();
pMyDllClass1->Func1();
pMyDllClass1->Func2();
pMyDllClass1->Func3();
CInterfaceClass* pMyDllClass2 = new CMyDLLClass2();
pMyDllClass2->Func1();
pMyDllClass2->Func2();
pMyDllClass2->Func3();
It seems that I can enter the functions. But many errors come out with STL members. I am confused on this usage of DLL.
Could you pls give your help on this ?
modified on Monday, November 22, 2010 7:57 PM
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SAMZCN wrote: But many errors come out with STL members.
Well we will have to guess what they are. It may be that you are not adding a using statement in your client project before the inclusion of the class containing the STL members. Alternatively you could add the full definitions in your headers like this:
CMyDLLClass1 : public CInterfaceClass
{
public:
CMyDLLClass1 (){};
virtual ~ CMyDLLClass1 (){};
virtual int Func1();
virtual int Func2();
virtual int Func3();
private:
std::vector<...> ....
std::map<...> ....
}
Did you notice how I also used <pre></pre> tags to make the code snippet more readable?
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Hello Richard,
Thanks for your input. I've include the headers in the DLL project
#include <map>
#include <vector>
#include <set>
#include <list>
using namespace std;
Is ther any error on my implementation on the DLL exporting? Is it a right way to make DLL proj to export derived class like what I do ? It is the first time that I do it like this.
Richard MacCutchan wrote: Well we will have to guess what they are. It may be that you are not adding a using statement in your client project before the inclusion of the class containing the STL members. Alternatively you could add the full definitions in your headers like this:
CMyDLLClass1 : public CInterfaceClass
{
public:
CMyDLLClass1 (){};
virtual ~ CMyDLLClass1 (){};
virtual int Func1();
virtual int Func2();
virtual int Func3();
private:
std::vector<...> ....
std::map<...> ....
}
Did you notice how I also used
tags to make the code snippet more readable?
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This is fine but have you include all the correct headers (and reference to std namespace) in the class that is linking to the DLL, i.e the code that will be using the DLL. Remember that classes and methods exported from a DLL are visible to the linker not the compiler.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Thanks.
Yes. In the client project linking to the DLL, the client project include the DLL interface head file like this.
#include "MyExprotDllHead.h"
Now the issue is still pending. And so many new failure report and reported in STL allocation procedure.
I'm trying my best to find out the root cause. 
Richard MacCutchan wrote: This is fine but have you include all the correct headers (and reference to std namespace) in the class that is linking to the DLL, i.e the code that will be using the DLL. Remember that classes and methods exported from a DLL are visible to the linker not the compiler.
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