How to open an exe from C# code

Question

1.00/5 (3 votes)

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I want to open an .exe file from button click.

Here is my code:

C#

Process myProcess = new Process();
myProcess.StartInfo.UseShellExecute = false;
myProcess.Start();
StartInfo.FileName = @"C:\Users\MyName\Desktop\NewFolder\Application.exe";

This is not working.
Can anyone please tell me whats wrong.

What I have tried:

Created an application to open an executable file from button click event.

Posted 19-May-16 9:53am

Member 12478311

Updated 19-May-16 18:40pm

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Comments

Kornfeld Eliyahu Peter 19-May-16 16:54pm

For first step study the compile error you got...

Patrice T 19-May-16 19:21pm

Define 'not working'

3 solutions

Solution 1

There is no such concept as "open an EXE". You can open a ".EXE" file file and read its bytes, then close it. I doubt that this is what you want (but I could explain how to do it, only if you explain the purpose of doing so :-)). Or you can simply use the file, which might be the valid application file for the given platform, to start that application. This is how: Process.Start Method (System.Diagnostics)[^].

—SA

Posted 19-May-16 11:46am

Sergey Alexandrovich Kryukov

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Karthik_Mahalingam · Accepted Answer · 2016-05-19T18:40:00

try

C#

ProcessStartInfo startInfo = new ProcessStartInfo (@"C:\Users\MyName\Desktop\NewFolder\Application.exe");
           startInfo.UseShellExecute =false;
           Process.Start(startInfo);

or

C#

ProcessStartInfo startInfo = new ProcessStartInfo(@"C:\Users\MyName\Desktop\NewFolder\Application.exe");
Process myProcess = new Process();
myProcess.StartInfo = startInfo;
myProcess.Start();

George Jonsson · Accepted Answer · 2016-05-19T13:50:00

You have the wrong order of things and also forgot the variable name in the last statement.

C#

Process myProcess = new Process();
myProcess.StartInfo.UseShellExecute = false;
myProcess.Start();
StartInfo.FileName = @"C:\Users\MyName\Desktop\NewFolder\Application.exe";

should be

C#

Process myProcess = new Process();
myProcess.StartInfo.UseShellExecute = false;
myProcess.StartInfo.FileName = @"C:\Users\MyName\Desktop\NewFolder\Application.exe";
myProcess.Start();

How to open an exe from C# code

3 solutions

Solution 3

Solution 2

Solution 1

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