ERROR : Input string was not in a correct format.

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I am trying to convert a String value to a Int value using convert function in C#. Can anybody help me in this regards...

String A = dt.Rows[0]["Quno"].ToString();
Int B =Int32.Parse (A);

Posted 30-Sep-10 22:03pm

E.msk

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Hiren solanki 1-Oct-10 4:45am

can you please debug and tell us what you are getting in A ?

Hiren solanki 1-Oct-10 4:45am

furthermore, you can have debugging by putting breakpoint.

MalikRizwan 3-Oct-10 1:28am

You better debug your code. it could be because of ANYTHING.. probably your data being fetched.

4 solutions

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Suthish Nair · Answer 1 · 2010-09-30T22:34:00

Solution 4

Int32 i = (dt.Rows[0]["Quno"].ToString() == null) ? 0 : Convert.ToInt32(dt.Rows[0]["Quno"].ToString());

Posted 30-Sep-10 22:34pm

Suthish Nair

Comments

Sandeep Mewara 1-Oct-10 11:42am

If 'dt.Rows[0]["Quno"]' is NULL then? dt.Rows[0]["Quno"].ToString() would bomb!

Sunasara Imdadhusen · Answer 2 · 2010-09-30T22:17:00

Solution 3

Hi,
Please use following, if dt.Rows[0]["Quno"].ToString(); contain null value then it will automatically handle and it will not gives error

C#

if(dt != null && dt.Rows.Count > 0)
        {
        Int32 B = Convert.ToInt32(dt.Rows[0]["Quno"].ToString());
        }

Please do let me know, if you have any doubt.

Please provide "Vote" if this would be helpful, and make "Accept Answer" if this would be correct answer.:rose:

Thanks,
Imdadhusen

Posted 30-Sep-10 22:17pm

Sunasara Imdadhusen

Comments

Sandeep Mewara 1-Oct-10 11:41am

But handling just an error should not be the solution. Root cause should be handled and dealt with. What say?

MalikRizwan 3-Oct-10 1:23am

you code will throw exception IF dt==null becuase you are checking Count in same condition where you are checking null. if dt is null you can't check Row.Count

hance_micle 1-Dec-10 6:24am

Good call!!

m@dhu · Answer 3 · 2010-09-30T22:12:00

Solution 2

Use int.TryParse rather than Int32.Parse. Confirm you are entering a valid string.

Posted 30-Sep-10 22:12pm

m@dhu

Updated 30-Sep-10 22:13pm

v2

ARopo · Answer 4 · 2010-09-30T22:11:00

Solution 1

This is because the string is blank or contains characters not valid for a number

I would recommend using TryParse

int iVal;
if (int.TryParse(myString, out iVal))
   // this worked
else
   // this failed

Posted 30-Sep-10 22:11pm

ARopo

Updated 3-Oct-10 22:19pm

v2

Comments

MalikRizwan 3-Oct-10 1:25am

int.TryParse doesn't accept second parameter as reference.. it should be out paramter.

int.TryParse(myString,out iVal);