Automatic build of a treeview

Question

0.00/5 (No votes)

See more:

Hello,
I am trying to automatically build a tree view by giving it the following values.
number of levels :Nlevels
number of children in each level: NchildrenAtEachLevel

Is this doable?

Any help would be highly appreciated.

Posted 28-Oct-10 20:55pm

SuperAdministrator

Updated 28-Oct-10 22:28pm

Dalek Dave

v2

Add a Solution

Comments

Arindam Tewary 29-Oct-10 2:59am

This is achiveable/doable. :)

SuperAdministrator 29-Oct-10 3:01am

can you provide me with any help regarding an algorithm ?

Dalek Dave 29-Oct-10 4:28am

Edited for Grammar and Readability.

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

qontary · Answer 1 · 2010-10-28T23:05:00

Try this. I modify the code posted by Mr. Pawan Kiran.

C#

private void FillTreeView(TreeView Tv, int NoOfLevels, int NoOfChildsOfEachLevel)
        {
            if (NoOfLevels < 0)
                return;
            for (int i = 0; i < NoOfChildsOfEachLevel; i++)
            {
                Tv.Nodes.Add(i.ToString());
                FillTreeNode(Tv.Nodes[i], NoOfLevels - 1, NoOfChildsOfEachLevel);
            }
        }

        private void FillTreeNode(TreeNode Tn, int NoOfLevels, int NoOfChildsOfEachLevel)
        {
            if (NoOfLevels < 0)
                return;
            for (int i = 0; i < NoOfChildsOfEachLevel; i++)
            {
                Tn.Nodes.Add(i.ToString());
                FillTreeNode(Tn.Nodes[i], NoOfLevels - 1, NoOfChildsOfEachLevel);
            }
        }

Pawan Kiran · Answer 2 · 2010-10-28T21:20:00

Solution 1

Equal No of Childs For Each Parent Node

Private Void FillTreeView(Treeview Tv,int NoofParents,int NoofChilds)
{
  for(int i=0;i< NoofParents;i++)
  {
    Tv.Nodes.Add(i);
    for(int j=0;i< NoofChilds;j++)
    {
       Tv.Nodes[i].Nodes.Add(j);
    }
  }
}

Posted 28-Oct-10 21:20pm

Pawan Kiran

Comments

SuperAdministrator 29-Oct-10 3:25am

This builds a tree with two levels ex: 2 parents with 3 children each . But i need to pass the number of levels so it has to be a kind of recursive method.