Get all the employees latest document date in SQL server

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Get all the employees latest Document date in sql server

No	Employee	DocumentDateNew
1	Employee1	3/22/2018
2	Employee1	5/22/2018
3	Employee1	10/23/2017
4	Employee2	3/21/2018
5	Employee2	6/22/2018
6	Employee2	10/23/2017
7	Employee2	10/12/2017
8	Employee3	3/22/2018
9	Employee3	11/10/2017

i need result like

NO	Employee	DocumentDateNew
1	Employee1	3/22/2018
4	Employee2	3/21/2018
8	Employee3	3/22/2018

What I have tried:

Get the record all the employee based on latest documents date

Posted 22-Mar-18 18:39pm

DhananjayanP

Updated 23-Mar-18 7:26am

v3

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itsmypassion · Answer 1 · 2018-03-22T18:56:00

Solution 1

SQL

SELECT EMPLOYEE,MAX(DOCUMENTDATE) FROM EMPLOYEETABLE GROUP BY EMPLOYEE

Posted 22-Mar-18 18:56pm

itsmypassion

Comments

DhananjayanP 23-Mar-18 1:33am

thank you for your answer, but I am getting EMPLOYEE name as Duplicate

dkamble 10358990 · Answer 2 · 2018-03-22T18:59:00

Solution 2

select Employee, max(DocumentDateNew) as DocumentDateNew from emptable group by Employee

Posted 22-Mar-18 18:59pm

dkamble 10358990

Comments

DhananjayanP 23-Mar-18 2:01am

thank you for your answer, but I am getting EMPLOYEE name as Duplicate

itsmypassion 23-Mar-18 2:28am

Do not include Column "No" in Group by List.

Richard Deeming · Answer 3 · 2018-03-23T07:27:00

If you need to include the "No" column:

SQL

WITH cte As
(
    SELECT
        No,
        Employee,
        DocumentDateNew,
        ROW_NUMBER() OVER (PARTITION BY Employee ORDER BY DocumentDateNew DESC) As RN
    FROM
        YourTable
)
SELECT
    No,
    Employee,
    DocumentDateNew
FROM
    cte
WHERE
    RN = 1
;

Demo[^]
ROW_NUMBER (Transact-SQL) | Microsoft Docs[^]

NB: Your expected output is wrong. Taking Employee1 as an example, 22nd May 2018 is later than 22nd March 2018, so the output should return row 2, not row 1.