How to convert a date time object to a countable variable

Question

2.50/5 (2 votes)

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JavaScript

$Jahr = date('Y');
$zahl = date('n');
if (isset($_GET['vor']))
{
   echo $datum = hallo;
   echo $zahl = $zahl ++;
}
else
{
   if (isset($_GET['zurück']))
   {
      echo $datum = hallo2;
   }
   else
   {
      echo $datum = $monate[$monat]. " ". $Jahr;
   }
}

now the $zahl is always 8 (month august). I think I have to convert it to a string for count

Posted 11-Aug-12 6:47am

Chi Ller

Updated 24-Aug-12 10:09am

fjdiewornncalwe

v4

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Mohibur Rashid · Answer 1 · 2012-08-24T16:53:00

Solution 2

if you want to do numerical operation on a number you need not to change it to string.
change your code like this:

C++

$zahl++;
echo $zahl;

other wise, it will first print and then do the incremental.

Posted 24-Aug-12 16:53pm

Mohibur Rashid

Comments

Chi Ller 5-Sep-12 15:40pm

No that´s not right. I don´t know how I finally had sucsess but I didn´t change the code like this and it works

ridoy · Answer 2 · 2012-08-11T07:34:00

Solution 1

See these..
1.http://stackoverflow.com/questions/396610/getting-a-php-datetime-object-into-a-string-representation-of-a-mysql-date[^]

2.http://af-design.com/blog/2010/03/13/microsoft-sql-server-driver-for-php-returns-datetime-object/[^]

3.http://www.sitepoint.com/forums/showthread.php?603090-Converting-object-to-string-within-a-class[^]

Hopefully these helps you..

Posted 11-Aug-12 7:34am

ridoy

Comments

Chi Ller 11-Aug-12 14:09pm

The first link I already tried before, the second doesn´t help and the code in the last one returns me an Error