popup alert box as customized

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hi friends

please help me

when give invalid details display popup and show alert

i.e if i given invalid details for login (don't match db table) then i want to dispaly popus as customized(my own popup) in that box display error measege

my code is here and give solution for this

XML

<link rel="stylesheet" href="css/jquery-ui.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
    window.$required = $('<div></div>').dialog({
        autoOpen: false,
        title: 'Required Information'
    });
});

</script>

XML

<script type="text/javascript">

function validate_login ( )
{
    valid = true;

        if ( document.login.user.value == "" )
        {
               // alert ( "Please fill the user name." );

         $required.html("Please fill the user name.").dialog('open');
                valid = false;
        }
        else if ( document.login.pass.value == "" )
                {
                           $required.html("Please fill the password.").dialog('open');
                        valid = false;
        }
        return valid;
}


</script>
</head>

XML

<td >
<form  name="login" method="post" action="login.php" onSubmit="return validate_login( );">
       <div class="webmail-bg">
         <table width="301" border="0" cellspacing="0" cellpadding="0">
           <tr>
             <td height="28" align="left" valign="top">Username :</td>
           </tr>
           <tr>
             <td><label>
               <input name="user" id="sPerson" type="text" class="email-txt-field" value="" />
             </label></td>
           </tr>
           <tr>
             <td height="38" align="left" valign="middle">Password :</td>
           </tr>
           <tr>
             <td><label>
               <input  type="password" name="pass" type="text" class="email-txt-field" value="" />
             </label></td>
           </tr>

---------->code for check for login details with DB table-------->

PHP

<?php
ob_start();
include "db.php";


$username=$_POST["user"];
$password=$_POST["pass"];

$username=strip_tags(stripslashes($username));
$password=strip_tags(stripslashes($password));

//now md5 the password

//$pass=md5($password);

$mysqlqry="select username,password from admin_login where username='".$username."' and password='".$password."'";


//echo $mysqlqry;
$result = mysql_query($mysqlqry);
$count=mysql_affected_rows();
//echo "Result is ".$result;
//echo $count;





if(!$result)
{
    echo("<P>Can't execute the query.</P>");
    echo("<P>Error performing query: " . mysql_error() . "</P>");
    include "index.php";
    exit();
}

    else
    if($count==1)
    {
            setcookie("login","User",time()+2*3600);
header('Location: adminhome.php');
        }
else        {
echo "<script> alert('invalid username or password')</script>";
//echo "Invalid Username or Password.<br>";
include "index.php";}?>

Posted 24-Feb-13 21:59pm

Member 9753773

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A. S. M. Abdur Rab · Answer 1 · 2013-02-25T18:56:00

You may use jQuery ajax to check valid username/password so that you can use the dialog box to show the error messages.

Here I have modified function validate_login() and the login.php codes:

modified function validate_login() is:

JavaScript

function validate_login ( )
{
    //valid = true;

    if ( document.login.user.value == "" )
    {
        // alert ( "Please fill the user name." );
        $required.html("Please fill the user name.").dialog('open');
        //valid = false;
    }
    else if ( document.login.pass.value == "" )
    {
        $required.html("Please fill the password.").dialog('open');
        //valid = false;
    }

    else {

        $.ajax({
            type: "POST",
            url: "login.php",
            data: "user="+$("input[name='user']").val()+"&pass="+$("input[name='pass']").val(),
            success: function(msg){

                if(msg == 'success') {
                    window.location.href= "adminhome.php";
                }
                else {
                    $required.html(msg).dialog('open');
                }
            }
        });
    }

    return false;
}

updated login.php codes:

PHP

ob_start();
include "db.php";


$username=$_POST["user"];
$password=$_POST["pass"];

$username=strip_tags(stripslashes($username));
$password=strip_tags(stripslashes($password));

//now md5 the password

//$pass=md5($password);

$mysqlqry="select username,password from admin_login where username='".$username."' and password='".$password."'";


//echo $mysqlqry;
$result = mysql_query($mysqlqry);
$count=mysql_affected_rows();
//echo "Result is ".$result;
//echo $count;


if(!$result)
{
    echo("Can't execute the query.<br />");
    echo("Error performing query: " . mysql_error() . "");
    //include "index.php";
    exit();
}
else
    if($count==1)
    {
        setcookie("login","User",time()+2*3600);
        //header('Location: adminhome.php');
        echo("success");
        exit();
    }
    else
    {
        //echo "<script> alert('invalid username or password')</script>";
        echo "Invalid Username or Password.";
        //include "index.php";
        exit();
    }
?>

Finally, I have removed the action="login.php" from the form tag:

<form name="login" method="post" onsubmit="return validate_login( );"></form>