String within a String Count

Question

2.33/5 (2 votes)

See more:

Is there a function that counts how many times a sub-string appears within the larger string.

Example: "Recover your contacts on your phone system"

The function would need to tell me how many times "your" appears in the string; which would be 2.

Posted 10-May-13 10:47am

Runner55Code

Add a Solution

Comments

Sergey Alexandrovich Kryukov 10-May-13 16:58pm

How can this be related to database? You could better do it in your application's language.
—SA

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Runner55Code · Answer 1 · 2013-05-10T11:23:00

(Length('Find your own way in your own world') - Length(Replace('Find your own way in your own world','your',''))) / Length('your')

...which correctly returned 2.

This seemed to work better than the one suggested on the PostgreSQL web site...

Length('Find your own way in your own world') - Length(regexp_replace('Find your own way in your own world','your','','g')) / Length('Find your own way in your own world')

...which returns 35 (...this may have something to do with the 'g' in the expression but it's not explained do I just left it.)

RaisKazi · Answer 2 · 2013-05-10T10:58:00

Solution 1

Have a look at below simmilar Question-Answer thread.

http://www.postgresql.org/message-id/20091020172452.GA10593@tux

Hope it helps.

Posted 10-May-13 10:58am

RaisKazi

Comments

Maciej Los 10-May-13 17:44pm

+5

RaisKazi 10-May-13 21:21pm

Thank you Maciej, :).