Need to consider age of person as 18 who is 2months less than 18

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SQL-Server-2005

select datediff(yy,'1986-12-06','2003-10-12 14:55:49.480')as years
this gives me age as 17 years now i need to consider if it is only two months remaining in completing 18 years how would i do this.Please suggest

Posted 12-Jun-13 19:38pm

shriti 3

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Sergey Alexandrovich Kryukov 13-Jun-13 1:45am

Did you try anything?
—SA

shriti 3 13-Jun-13 1:50am

yes i tried using Datepart function but not getting how exactly i consider it as 18 years

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**Zoltán Zörgő** · Answer 1 · 2013-06-12T19:56:00

Solution 2

Well, think on the age in months: who is going to be 18 in two months, is 18*12-2=214 months old.

SQL

...datediff(mm,...

Posted 12-Jun-13 19:56pm

Zoltán Zörgő

OriginalGriff · Answer 2 · 2013-06-12T20:07:00

Ages are not quite the same as dates, and the real problem is that you are accessing the number of years - which is an integer value, and only considers the year number in the calculation. So

SQL

SELECT datediff(yy,'1986-01-01','2003-12-31') AS years

And
SELECT datediff(yy,'1986-01-01','2003-01-01') AS years

SQL

Will also both return 17.

A solution is to use the number of months:

SQL

SELECT datediff(mm,'1986-01-01','2003-12-31') AS months

which is a little better - you can compare the number of months against 18 * 12, but it's still not that helpfull if you need to have an exact cut off date at 18 years:

SQL

SELECT datediff(mm,'2003-11-30','2003-12-01')AS months

returns 1 for example.

A better solution is to add the years to the start date:

SQL

SELECT DATEDIFF(dd, DATEADD(yy, 18, '1986-12-06'), '2013-10-12') as DAYS

If the result is negative they are under 18, if it's greater than zero they are over 18, and if it is zero it's their 18th birthday!