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(C#) Determining whether the current build mode is Debug or Release

5.00/5 (1 vote)
25 Feb 2012CPOL 12.6K  
I prefer the [Conditional(DEBUG)] attribute over #if DEBUG.This is especially advised for your logging example.E.g.[System.Diagnostics.Conditional(DEBUG)]private void Validate() { /* check instance integrity */ }or[System.Diagnostics.Conditional(DEBUG)]public static...
I prefer the [Conditional("DEBUG")] attribute over #if DEBUG.
This is especially advised for your logging example.

E.g.
C#
[System.Diagnostics.Conditional("DEBUG")]
private void Validate() { /* check instance integrity */ }

or
C#
[System.Diagnostics.Conditional("DEBUG")]
public static void DebugLog(string message) { ... }


You call these methods like any other method. The compiler will not add any call code if "DEBUG" is not defined.

BTW: Your resoning of "not Debug" equals "Release" is not true in general, you might have other configurations than only the default "Debug" and "Release" configurations.

License

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