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Dynamically menu binding

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29 Oct 2013 4  
Hi friends..... Many of guys are trying or working on menus for binding it dynamically. i've the solution for ithere , i m putting sample code to

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Hi friends.

Many of guys are trying or working on menus for binding it dynamically. I've the solution for it.

Here, I'm putting sample code to create menu dynamically.

MenuTest.aspx

<asp:Menu ID="Menu1" runat="server" Orientation="Horizontal">
</asp:Menu>  

MenuTest.aspx.cs  

static string constr = "SQLOLEDB;Data Source=ABC;Integrated Security=SSPI;Initial Catalog=XYZ";
OleDbConnection cn = new OleDbConnection(constr);  

protected void Page_Load(object sender, EventArgs e)
{
  if (!Page.IsPostBack)
    PopulateRootLevel();
}  

private void PopulateRootLevel()
{
  OleDbCommand objCommand = new OleDbCommand(@"select id,title,(select count(*) FROM SampleCategories WHERE parentid=sc.id) childnodecount FROM SampleCategories sc where parentID IS NULL", cn);
  OleDbDataAdapter da = new OleDbDataAdapter(objCommand);
  DataTable dt = new DataTable();
  da.Fill(dt);
  PopulateNodes(dt, Menu1.Items);
}

private void PopulateSubLevel(int parentid, MenuItem parentMenu)
{
  OleDbCommand objCommand = new OleDbCommand(@"select id,title,(select count(*) FROM SampleCategories WHERE parentid=sc.id) childnodecount FROM SampleCategories sc where parentID="+parentid+"", cn);
  OleDbDataAdapter da = new OleDbDataAdapter(objCommand);
  DataTable dt = new DataTable();
  da.Fill(dt);
  PopulateNodes(dt, parentMenu.ChildItems);
}

private void PopulateNodes(DataTable dt, MenuItemCollection items)
{
  foreach (DataRow dr in dt.Rows)
  {
    MenuItem mi = new MenuItem 
    {
      Text = dr["title"].ToString();  
      Value = dr["id"].ToString();
    }
    items.Add(mi);
    //If node has child nodes, then enable on-demand populating
    bool flag = ((int)(dr["childnodecount"]) > 0);
    if (flag)
    {
      menuCreate(mi);
    }
  }
}
private void menuCreate(MenuItem m)
{
  MenuEventArgs e = new MenuEventArgs(m);
  PopulateSubLevel(Int32.Parse(e.Item.Value), e.Item);
}

Here is the database script:

For schema generating:

 CREATE TABLE [dbo].[SAMPLECATEGORIES](
    [id] [int] IDENTITY(1,1) NOT NULL,
    [parentid] [int] NULL,
    [title] [nvarchar](255) COLLATE SQL_SwedishStd_Pref_CP1_CI_AS NOT NULL
)  

For testing, data samples:

INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (1, NULL, N'Category 1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (2, NULL, N'Category 2')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (3, NULL, N'Category 3')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (4, 1, N'Category 1.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (5, 1, N'Category 1.2')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (6, 2, N'Category 2.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (7, 2, N'Category 2.2')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (8, 2, N'Category 2.3')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (9, 7, N'Category 2.2.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (10, 7, N'Category 2.2.2')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (11, 10, N'Category 2.2.2.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (12, 6, N'Category 2.1.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (13, 3, N'Category 3.1')
INSERT INTO [dbo].[SAMPLECATEGORIES] ([id], [parentid], [title]) VALUES (14, 7, N'Category 2.2.3') 

I hope this article will help you.

After the day of the research I've made this code and it is very helpful to others.

Edit History: 

29-Oct-2013: Changed type to Tip/Trick and minor formatting corrections 

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