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Easy Seralization Using Extension Methods

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23 May 2014 1  
Easy seralization by adding extension methods to generic class

Introduction

Binary serialization is very common in some scenarios, so, this tip adds this functionality as extension methods in order to provide an easy and comfortable way to use it.

Background

You must know C#, serialization concept and extension methods.

Using the Code

The extension methods are as given below:

public static class Extensions
{
    public static void Serialize<T>(this T obj, string filePath=null)
    {
        filePath = filePath ?? (filePath ?? (obj.GetType().GenericTypeArguments[0].FullName + ".bin"));

        using (Stream stream = File.Open(filePath, FileMode.Create))
        {
            BinaryFormatter bin = new BinaryFormatter();
            bin.Serialize(stream, obj);
        }
    }

    public static T DeSerialize<T>(this T obj, string filePath=null)
    {
        T result;
        filePath = filePath ?? (filePath ?? (obj.GetType().GenericTypeArguments[0].FullName + ".bin"));

        if (!File.Exists(filePath)){
            return (obj);
        }

        using (Stream stream = File.Open(filePath, FileMode.Open)){
            BinaryFormatter bin = new BinaryFormatter();
            result = (T)bin.Deserialize(stream);
        }

        return (result);
    }
} 

Sample of use is as follows:

[Serializable()]
public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

private void testSerialization()
{
    //Instance a new list and get it from file (if exists)
    List<Person> lstPerson = new List<Person>().DeSerialize();

    //If list is void, fill and save it (serialize)
    if (lstPerson.Count() == 0){
        lstPerson.Add(new Person() { Name = "Pepe", Age = 60 });
        lstPerson.Add(new Person() { Name = "Juan", Age = 70 });
        lstPerson.Serialize();
    }

    //check list content
    foreach (var person in lstPerson){
        Console.WriteLine("{0} {1}", person.Name, person.Age);
    }
} 

License

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