Comments by Member 11511083

Member 11511083 9-Mar-15 17:50pm View

Thank you. What I was missing was that if a matrix X is Nx3, then it's transpose times itself (and not the other way around) results in a 3x3 matrix.

Thanks again.

Member 11511083 9-Mar-15 16:43pm View

I think I'm starting to get there, that my system of points X (3xN) times it's transpose must always be a square matrix 3x3... been a while since I've done linear algebra.

Member 11511083 9-Mar-15 16:34pm View

Thanks for your solution YvesDaoust. I'm having trouble putting together all the pieces. I follow the 3x3 Cholesky decomposition. But I don't understand where this 3x3 matrix comes from. I have read the link you've posted several times.

Considering I have N points, I see instead that I have a 3xN matrix, rather than 3x3.

How dissimilar is your solution to the one posted in Solution 2.

Thank you.

Comments by Member 11511083 (Top 3 by date)