Comments by keerthi23

keerthi23 24-Apr-14 16:38pm View

Thanks for the help , i was able to finish it with your help... Really thanks very much

keerthi23 10-Jan-14 12:32pm View

Just wanna let you know , the reason i came here with the problem is i don't know , it may be easy for you but for me i am just the learner

keerthi23 21-Feb-13 13:20pm View

i managed to read the string from "123456 AL0120102090990AL01303030" i dont know how to continue further to read the rest , this is the code i am using
dim str, lngDelimiter , strFull as string
str = "AL0120102090990AL01303030CS01999998888777"
lngDelimiter = InStr(1, strFull, "CS01")
If lngDelimiter > 0 Then
'parse out everythig before the delimiter
strSubString = Strings.Left(str, lngDelimiter - 1)
the above will return this
AL0120102090990AL01303030

how to read the rest of the string value?

keerthi23 1-Feb-13 13:42pm View

the adjacent column you mentioned, is it a text box ?

keerthi23 25-Jan-13 12:30pm View

sorry i will put that now.

keerthi23 25-Jan-13 11:43am View

off course i know nobody wants to do others home work. i will put my code i did so far.
BYW thanks sergey

Comments by keerthi23 (Top 6 by date)