i want to display 'Acknowledgment Message like successfully inserted record.' in windows application

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Hi

I want to display 'Acknowledgment Message like successfully inserted record.' in windows application by using any control(like Memba control it's for web application).

Posted 31-Jan-12 20:00pm

nareshgundapaneni

Updated 31-Jan-12 20:07pm

Rajesh Anuhya

v2

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walterhevedeich 1-Feb-12 2:06am

Have you tried doing it?

nareshgundapaneni 1-Feb-12 2:07am

no,i need help which control i need to use for that.

Sergey Alexandrovich Kryukov 1-Feb-12 2:21am

Many. Almost anything which could carry a text. This is your idea, so put forward your design.
--SA

Sergey Alexandrovich Kryukov 1-Feb-12 2:29am

I suggested a pretty funny (but working answer) -- care to see? :-)
--SA

Rockstar_ 1-Feb-12 2:16am

Can You Mention Your Problem Clearly?

Sergey Alexandrovich Kryukov 1-Feb-12 2:29am

I think I suggested the very general answer which should work no matter what. Please see, I think it's pretty funny (but true). :-)
--SA

Sergey Alexandrovich Kryukov 1-Feb-12 2:20am

First, what is "Windows application"? WPF, Forms, what? Tag it (Tag, not just mention.)
--SA

nareshgundapaneni 1-Feb-12 2:29am

Windows application

Sergey Alexandrovich Kryukov 1-Feb-12 2:20am

What is Memba?
--SA

nareshgundapaneni 1-Feb-12 2:24am

Hi VijayChauhan123,

my problem is i am getting string from back end after inserting data like this 'successfully data inserting' i need to display that string message in windows application by using any control(not messagebox.show() or label.text).like Memba control in asp.net

nareshgundapaneni 1-Feb-12 2:26am

Hi SAKryukov,
What is Memba?:we are using in our web application Memba control for displaying Acknowledgment Message.

nareshgundapaneni 1-Feb-12 2:34am

Hi all,
i need any third party control for this,any one help please.

nareshgundapaneni 1-Feb-12 2:37am

hi all,
this one we are using in web application
http://www.codeproject.com/KB/ajax/InfoBox.aspx?display=PrintAll

like this i need in windows application.

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OriginalGriff · Answer 1 · 2012-01-31T20:20:00

Solution 1

For goodness sake! How difficult do you think it is to do?

A label.

C#

myLabel.Text = "Done";

A TextBox

C#

myTextBox.ReadOnly = true;
myTextBox.Text = "Done";

A MessageBox

C#

MessageBox.Show("Done");

If you are really desperate:

C#

myButton.AutoSize=true;
myButton.Text = "The record was inserted correctly";

Posted 31-Jan-12 20:20pm

OriginalGriff

Updated 31-Jan-12 20:31pm

v2

Comments

Sergey Alexandrovich Kryukov 1-Feb-12 2:27am

My 5. "For goodness sake" is a very appropriate expression. :-)

I happened to invent more universal answer. Do you want to see? -- I think it's pretty interesting. :-)
--SA

OriginalGriff 1-Feb-12 2:44am

:laugh: It's an alternative to a selection of Olde English words, mostly ending in "ing"!

Michel [mjbohn] 1-Feb-12 2:33am

I'd take the button ;)

Sergey Alexandrovich Kryukov · Answer 2 · 2012-01-31T20:24:00

Solution 4

Do the following: scan all available controls in the library you use. Select those having a public property named "Text", "Value", "Title" or "Header", but only those of a type System.String. Learn what each of them can basically do. Choose any of them to your liking and fitness to your design ideas.

—SA

Posted 31-Jan-12 20:24pm

Sergey Alexandrovich Kryukov

Updated 31-Jan-12 20:30pm

v3

kashif Atiq · Answer 3 · 2012-01-31T20:22:00

you can use messagebox class to display Acknowledgment Message
or if you want Acknowledgment Message to appear on form and disapear automaticaly than either you can display them in a label and hide that label after predefine time by timer control
for more detailed work have a look at this post

http://bytes.com/topic/c-sharp/answers/890234-win-forms-display-self-disappearing-notifications-popups-quick-succession[^]

ganeshbdas · Answer 4 · 2012-01-31T20:36:00

create a label lblInserted
lblInserted.text="inserted successfully";

this label should be invisible at the first time
lblInserted.visible=false;

After inserting data visible the label
lblInserted.visible=true;

else put the code in the try block.if any exception got in the catch block

catch(exception ex)
{
lblInserted.text=ex.message.tostring();
lblInserted.visible=true;
}