How to define the structure of a XAML in an xml file?

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I can do this in WPF

C#

string xaml = "<grid margin="0" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"><textblock text="Page one" fontsize="32" foreground="White" horizontalalignment="Center" verticalalignment="Center" /> </grid>";

C#

StringReader stringReader = new StringReader(xaml);
            XmlReader xmlReader = XmlReader.Create(stringReader);
            UIElement MyVisualTree = (UIElement)XamlReader.Load(xmlReader);
            Layout.Children.Add(MyVisualTree);

I want to define the structure of the "string xaml = ..." in an XML file as follows:

C#

<menuitem tipo="C" xaml=" <Grid> ... </Grid>" estado="E" />

but trying to process tells me that there is an error in

"<" Grid
Is there any way to tell xml try everything in ContenidoGrid = ".." , treat it as a simple text and not be posting in special characters (< , >).

Posted 10-Sep-13 4:16am

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Updated 10-Sep-13 4:24am

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Sergey Alexandrovich Kryukov · Answer 1 · 2013-09-10T05:08:00

The last line of your code sample is not XML at all. It is not well-formed and cannot be parsed.

Before working with XAML and other XML applications, you need to learn XML itself. Your problem with the syntax is very basic: you cannot add any tags in the opening tags. You only insert inner XML between opening and closing tags:

HTML

<someElement someAttribute="you cannot have XML inside the tag">
   <!-- any inner XML, should also be well-formed -->
</someElement>

Please see:
http://en.wikipedia.org/wiki/XML[^],
http://www.w3.org/TR/xml/[^],
http://www.xml.com/axml/testaxml.htm[^].

—SA