cummulative frequency answer from gridview

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2.50/5 (2 votes)

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Hi,

I calculated cumulative frequency like this:
a b c
1 2 2
1 3 5
1 6 11
2 4 4
2 1 5

C#

for (int rowIndex = gdv2.Rows.Count - 2; rowIndex &amp;gt; 0; rowIndex--)
            {
                GridViewRow previousRow = gdv2.Rows[rowIndex + 1];
                int c1 = 0;
                int cv1 = 0;
                foreach (GridViewRow row1 in gdv2.Rows)
                {
                    if (row1.Cells[1].Text == previousRow.Cells[1].Text)
                    {
                        cv1 =System.Convert.ToInt32 (row1.Cells[3].Text);
                        c1 += cv1;
                        row1.Cells[4].Text = c1.ToString();
                    }
                }
                dataArray1.Add(c1);
            }

I need to store the values such as 11,5 in data array, but by using this code it store the values more times.

Can any one say me the suggestion for storing unique answer(value) in data array?

Posted 24-Feb-11 21:51pm

gowdhami

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OriginalGriff · Answer 1 · 2011-02-24T21:55:00

Solution 1

Now I KNOW you asked this one a few days ago!
calculating multiple cumulative frequency in gridview[^]
If no one answered then, (or referred to your earlier questions on the same subject) perhaps you should take the hint?

Posted 24-Feb-11 21:55pm

OriginalGriff

Comments

gowdhami 25-Feb-11 3:59am

actually that post was in deleted status. so i cant update that... so only i post this.. the answer given for that is not correct

gowdhami 25-Feb-11 4:02am

for me that post was showing as deleted status... and that answer is suitable for calculating single cf... but i wrote coding for multiple cf.. but the answer was storing many times in data array... my question is how to store the all cf value only once

OriginalGriff 25-Feb-11 4:03am

That turns out not to be the case: I just checked and neither of those posts are deleted.

gowdhami 25-Feb-11 4:06am

actually i found answer for that... that coding only i wrote in my question... now i am asking different question

Espen Harlinn 25-Feb-11 10:50am

Nice reply - seems like it's been posted several times :)