is there any way to get data like

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I have table like,

Party Name | Date
AAA              2013-12-01
BBB              2013-12-03
CCC              2013-12-05
DDD             2013-12-06

I want result using select query like

Party Name | Date
AAA              2013-12-01
-                   2013-12-02
BBB              2013-12-03
-                  2013-12-04
CCC             2013-12-05
DDD            2013-12-06

Posted 23-Jun-14 3:27am

pareshpbhayani

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2 solutions

Solution 1

A quick way could be like

SQL

SELECT COALESCE(MT.PARTYNAME, TMP.PARTYNAME), TDATE
FROM 
(
   SELECT '2013-12-01' AS TDATE, '-' as PARTYNAME
   UNION ALL
   SELECT '2013-12-02' AS TDATE 
   UNION ALL
   SELECT '2013-12-03' AS TDATE 
   UNION ALL
   SELECT '2013-12-04' AS TDATE 
   UNION ALL
   SELECT '2013-12-05' AS TDATE 
   UNION ALL
   SELECT '2013-12-06' AS TDATE 
) TMP LEFT OUTER JOIN MYTABLE MT ON TMP.TDATE = MT.DATE

Posted 23-Jun-14 3:37am

_Asif_

Comments

pareshpbhayani 23-Jun-14 9:44am

Thanks for giving me reply.
In my table there are lots of data event i don't know amount of data in that case i can't use this query.

Andrius Leonavicius 23-Jun-14 9:48am

Hi,

What is your version of SQL Server?

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Andrius Leonavicius · Accepted Answer · 2014-06-23T05:18:00

If you're using SQL Server 2005 or above, you can do it like this (I'm using CTE to generate dates between min and max dates):

SQL

DECLARE @MinDate DATE, @MaxDate DATE;

SET @MinDate = (SELECT MIN([Date]) FROM [TableName]);
SET @MaxDate = (SELECT MAX([Date]) FROM [TableName]);

;WITH Dates
     AS (SELECT [Date] = @MinDate
         UNION ALL
         SELECT [Date] = DATEADD(DAY, 1, [Date])
         FROM Dates
         WHERE [Date] < @MaxDate)
SELECT ISNULL(t.[Party Name], '-') AS [Party Name],
       d.[Date]
FROM   Dates AS d
       LEFT OUTER JOIN [TableName] AS t
                    ON t.[Date] = d.[Date]
ORDER  BY d.[Date]
OPTION (MAXRECURSION 32767);