What is the problem with this program?

Question

0.00/5 (No votes)

See more:

#include <iostream>
#include <conio.h>
#include <string>
#include <cstdlib>

using namespace std;
 class Dog
{
private:
    string breed;
    string EyeColor;
public:
    Dog(string Breed="",string eyeColor="") {breed=Breed;EyeColor=eyeColor;}
     string getBreed() {return breed;}
     string setBreed(string Breed) {breed=Breed;}
     string getEyeColor() {return EyeColor;}
     string setEyeColor(string eyeColor) {EyeColor=eyeColor;}
     friend  Dog operator *(Dog d1,Dog d2);
     void display(){cout<<"Breed: "<<breed<<"; eye color: "<<EyeColor<<endl;}


};
Dog operator *(Dog d1,Dog d2)
{
    Dog newDog;
    if(d1.getBreed()==d2.getBreed())
        newDog.setBreed(d1.getBreed());
    else

        newDog.setBreed("Mixed");
        int i=rand()%2;
        if(i==0)
            newDog.setEyeColor(d1.getEyeColor());
        else
            newDog.setEyeColor(d2.getEyeColor());
        return Dog(newDog.getBreed(),newDog.getEyeColor());
}
int main()
{
    Dog d1("Labrador","Yellow"),
    d2("Labrador","Green"),
    d3("Dog","Yellow"),
    d4("Mops","Black");
    cout<<"dog #1: ";d1.display();
    cout<<"dog #2: ";d2.display();
    Dog saheb;
    saheb=d1*d2;
    cout<<"Result of pair dog: ";
    saheb.display();
    cout<<"dog #3: ";d3.display();
    cout<<"dog #4: ";d4.display();
    cout<<"Result of pair dog: ";
    (d3*d4).display();
    getch();
    return 0;

}

What I have tried:

i tried to solve this
a. Design a Dog class that includes fields for a breed (for example, “Labrador”) and eye color. Include extraction and insertion operators.

b. Overload an operator*()function for the Dog class. When you multiply two Dogs, the result is a Dog. If the two operand Dogs are the same breed, then the resulting Dog is that breed; if the two operand Dogs have different breeds, then the resulting Dog is “Mixed” breed. Obtain a random number of 0 or 1 for the resulting Dog’s eye color. (See Appendix E for instructions on creating random numbers.) When the random number chosen is 0, use the eye color from the first operand Dog for the resulting Dog’s eye color; when the random number is 1, use the eye color of the second Dog for the result Dog.

c. Write a main()function in which you declare four parent Dogs. When you execute the program, make sure you assign the same breed to two Dogs, and different breeds to each of the other two Dogs. (You will have a total of three breeds for the four Dogs.) Also assign a variety of eye colors. In a loop, multiply each pair eight times, and display the results.

Posted 24-Dec-17 11:03am

Member 13592359

Updated 24-Dec-17 19:30pm

Add a Solution

Comments

Nakhia_ind 26-Dec-17 9:40am

how can multiple two objects like saheb=d1*d2;

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2017-12-24T19:30:00

Solution 1

Read your homework question:

In a loop, multiply each pair eight times, and display the results.

For that, you will need a for loop, and to multiply d1 by d2, then d1 by d3, d1 by d4, d2 by d3, d2 by d4, and d3 by d4 inside the loop, printing the result each time.

Posted 24-Dec-17 19:30pm

OriginalGriff

Comments

Member 13592359 25-Dec-17 4:52am

// so far i have done this and everything is ok now i want to Include extraction and insertion operators for breed and eyecolor. Can you please tell me how to do it.
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
class Dog
{
string breed;
string eyeColor;
public:
void extInsrt(int i)
{
cout << "Enter the breed of "<<i+1 <<" no dog: ";
cin >> breed;
cout << "Enter eyecolor of " << i+1 << " no dog: ";
cin >> eyeColor;
}
void showData(int i, Dog obj[4])
{
cout <<i+1<< ". The breed of " << i+1 << " no dog is: " << obj[i].func_breed()<<endl;
cout << " The eyecolor of " << i+1 << " no dog is: " << obj[i].func_eyeColor()<<endl;

}
string func_breed()
{
return breed;

}
string func_eyeColor()
{
return eyeColor;
}
Dog operator* (Dog ob)
{
Dog obj;

if (this->breed == ob.breed)
{
obj.breed = breed;
return obj;
}
else
{
obj.breed = "Mixed";
return obj;
}
}

};

int main()
{
Dog obj[4];
for (int i = 0; i < 4; i++)
{
obj[i].extInsrt(i);
}
for (int i = 0; i < 4; i++)
{
obj[i].showData(i, obj);
}
for (int i = 0; i < 8; i++)
{

int opt1;
int opt2;
int random_Number = rand() % 2;
cout << "Enter the number of two dogs [Example: for 1 no dog, input 1]";
cin >> opt1;
cin >> opt2;
Dog ob;
ob = obj[opt1 - 1] * obj[opt2 - 1];
cout <<"Breed: "<< ob.func_breed() << endl;
if (random_Number == 0)
{
cout <<"Eyecolor: "<< obj[opt1 - 1].func_eyeColor() << endl;
}
else {
cout << "Eyecolor: " << obj[opt2 - 1].func_eyeColor() << endl;
}

}

return 0;

}