openfiledialog

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i have to use openfiledialog container.
& folder of selected directory should be display in datagrid

i aiso try to use files = Directory.GetFiles(stFileName) but it not work properly.

please help

Posted 27-Jun-10 19:51pm

curious_mind

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shukla dhaval · Answer 1 · 2010-06-27T19:57:00

I hope it works for you.

Dim strFilename() As String
        strFilename = System.IO.Directory.GetFiles("Path")
        Dim dt As New DataTable
        dt.Columns.Add("FileName")
        dt.Columns.Add("FilePath")
        For i As Integer = 0 To strFilename.Length - 1
            Dim dr As DataRow
            dr = dt.NewRow
            dr.Item(0) = System.IO.Path.GetFileName(dt.Rows(i).Item(0))
            dr.Item(1) = dt.Rows(i).Item(0).ToString
            dt.Rows.Add(dr)
        Next
        DataGridView1.DataSource = dt

curious_mind · Answer 2 · 2010-06-27T21:04:00

VB

Dim thing As String

       Dim folder As String

       Dim Files2Open As Array

       Dim row As Integer
       row = 0

       If OpenFileDialog1.ShowDialog = Windows.Forms.DialogResult.OK Then
           folder = OpenFileDialog1.FileName.Substring(0, _
           OpenFileDialog1.FileName.LastIndexOf("\") + 1)
           Files2Open = Directory.GetFiles(folder)
           'DataGridView1.Columns.Add("Column1", "FileName")

           For Each thing In Files2Open
               DataGridView1.Rows.Add()
               DataGridView1.Item(0, row).Value = thing
               row = row + 1

           Next

       End If

openfiledialog

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