What does this cryptic bracket sequence mean? What programming language is it? Is it valid syntax? If there is even a weak chance of this syntax being valid, then what does it mean?
Alright, alright, alright.....It is C++. That would calm most people; with all their love (pun) for C++. Specifically, it is C++0x. Amongst many other features that we have been waiting for, C++0x gives us the power of lambdas.
The formal definition of a lambda in C++0x is as follows:
[capture_mode] (parameters) mutable throw() -> return_type {
body
}
So a lambda may capture one or more variables in scope by value or by reference, or it may capture none. Specifying return_type
is not necessary if the type can be inferred or is void
.
For instance, astd::for_each
's functor based code could be inlined with a lambda as follows:
std::for_each(v.begin(), v.end(), [](int x) {
cout << x << std::endl;
});
A lambda definition could be assigned to a variable and then used or invoked later.
auto lessthan = [](int left, int right) {
return left < right;
};
In the above code, lessthan
represents a function that takes two int
parameters, and returns a bool
. And it can be invoked as lessthan(2, 3)
, which returns true
. The cute thing about a lambda is that it can be invoked directly right after its definition. The following code defines a lambda (which takes two int
s and returns a bool
) and invokes it right away.
[](int left, int right) {
return left < right;
} (2, 3);
Coming back to our initial question...............you should have guessed it by now. The bracket sequence - [](){}();
- is nothing but a definition followed by a call (right away) to a lambda taking no arguments and returning nothing.
To end with a quote, C++ code is like calligraphy. In other words, it is beautiful to those who understand it, while it is cryptic to others.
P.S.: Pardon me if calligraphy is inappropriate in this context.