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CAM simulator

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19 Feb 2002 1  
This program shows how a CN machine works

Sample Image - CAM_simulator.gif

Introduction

After 6 months of work, here is finally my first MFC program release. This program is a CAM simulator. I am not a software engineer, so please forgive me for errors. If you have questions please let me know. I am sure that you will find them. The lecture of data files was a big problem to me at the beginning, so here is the implementation. I needed to read *.txt files, what the CNC machine generate. Here is an example M X25 Y23 Z25 SPEED1500. This is a block of data, needed to setup the machines. This is a kind of language that the machine use to move on the coordinates over the work space. So in this implementation you can read a full document, splitting the block in the necessary X Y Z and SPEED values. This is my first upload, I have more things to say about this program I will try to improve soon, this short commentary.

void CProgramaDoc::OnFileOpen() 
{
    CString fichero="archivo de C�digo G",temp;

    CFileDialog archivos(true,NULL,fichero,OFN_ALLOWMULTISELECT,
        "Codigo G (*.tap)|*.tap|Codigo G (*.act)|*.act||",NULL);

    if (archivos.DoModal() == FALSE) return;
    fichero=archivos.GetPathName();

    CFile cfFile (fichero, CFile::modeNoTruncate | CFile::modeRead);
    CArchive ar (&cfFile, CArchive::load); 

    if(!ar.ReadString(temp))  return;

    nl=0;
    do
    {
        if(temp.GetLength() == 0) continue;
        strcpy(linea[nl],temp);
        nl++;

    }while(ar.ReadString(temp));    

    
    // SEPARANDO COORDENADAS


    int i,j,k,d,sp;
    char aux[30];

    for ( i=0; i<5000; i++)
    {
        x[i] = y[i] = z[i] = 0;
    }    

    kn=0;
    for (i=0;i<nl;i++)
    {
        
        if (linea[i][0]=='S');
        {
            Inicio=1;
        }
        
        if (linea[i][0]=='M');
        {
        sp = 0;
        k = 0;
        d = strlen(linea[i]);

        for (j=0;j<d;j++)
        {
            if ((linea[i][j]=='-')|(isdigit(linea[i][j]))|
                                        (linea[i][j]=='.'))
            {
                aux[k] = linea[i][j];
                k++;
                continue;
            }

            if (linea[i][j]==' ')
            {
                sp++;
                if (sp==1) continue;

                aux[k]=0;

                if (sp==2)
                    if ((aux[0]=='-')|(isdigit(aux[0]))|(aux[0]=='.'))
                        x[kn] = atof(aux);
                    else
                        x[kn] = x[kn-1];

                if (sp==3) 
                    if ((aux[0]=='-')|(isdigit(aux[0]))|(aux[0]=='.')) 
                        y[kn] = atof(aux);
                    else
                        y[kn] = y[kn-1];

                if (sp==4)
                    if ((aux[0]=='-')|(isdigit(aux[0]))|(aux[0]=='.')) 
                        z[kn] = atof(aux);
                    else
                        z[kn] = z[kn-1];

                k = 0;
                continue;
            }            
        }

        kn++;
        j = d;
        }
    }
    
    presentar = 1;

    //    VERIFICANDO TORNO O FRESA


    sumz = 0;
    for (i=0; i<nl; i++)
    {
        sumz += abs(z[i]);
    }

    if (sumz == 0)
        torno = 1;
    else
        fresa = 1;

    UpdateAllViews(NULL);
    
}

License

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