C / C++ / MFC

6-Mar-02 19:39

The ASSERT and TRACE macros are defined for DEBUG mode only. In RELEASE mode the ASSERT and TRACE macros are defined as ((void)0), so in RELESE mode the folloing line:
ASSERT(sizeof(CObject) == sizeof(void*));
Will be changed by preprocessor to:
((void)0) (sizeof(CObject) == sizeof(void*));
and the compiler will ignore that line, so even all arguments will not get valuated.
That’s why there is no assertion in RELEASE mode.

BTW, this is different from another approach when a macro gets defined for RELEASE like this:
#define ASSERT
In that case all macro arguments get valuated even in RELEASE mode.

Serge

Michael Dunn6-Mar-02 19:50

Michael Dunn

6-Mar-02 19:50

Asserts are there to catch bugs in your code. An object is being deleted or blown away before it should be. You don't give enough info to tell what you're doing wrong, but look at the stack trace when the assert fires, and see what part of MFC is doing the validation and on what object.

--Mike--
Best score on the mini-putt game: 26
My really out-of-date homepage
Sonork - 100.10414 AcidHelm
Big fan of Alyson Hannigan and Jamie Salé.

Serge Krynine6-Mar-02 20:03

6-Mar-02 20:03

Do not use CloseAllDocuments. This is why:

CDocTemplate::CloseAllDocuments
virtual void CloseAllDocuments( BOOL bEndSession );

Parameters

bEndSession

Specifies whether or not the session is being ended. It is TRUE if the session is being ended; otherwise FALSE.

Remarks

Call this member function to close all open documents. This member function is typically used as part of the File Exit command. The default implementation of this function calls the CDocument::DeleteContents member function to delete the document's data and then closes the frame windows for all the views attached to the document.

Override this function if you want to require the user to perform special cleanup processing before the document is closed. For example, if the document represents a record in a database, you may want to override this function to close the database.

Richard Everingham6-Mar-02 20:25

Richard Everingham

6-Mar-02 20:25

Welp it would apear I have found the problem. I adjusted the code to look like this:

CNewDSNDlg pDlg;
pDlg.DoModal();
pMyTemplate->CloseAllDocuments(FALSE);

This seamed to cure the problem. It was the dialog being opened within the funtion after the document closure. Having the dialog come up before the document closure has cured the problem. I have to admit I am not sure why and if anyone happens to know I wouldn't mind learning the reason.

Thx,
Richard

How to open recordset using command object

Roger Allen7-Mar-02 5:04

Roger Allen

7-Mar-02 5:04

Wouldn't it be easier to just stop the OnFileNew procedure being called?

OnUPdateFileNew(CCmdUI *pCmdUI)
{
POSITION pos ;

pos = pDocTemplate->GetFirstDocPosition() ;
pCmdUI->Enable(pos == NULL) ; //enable if there are no documents of this type
}

Of course you need the CDocTemplate pointer for this to work.

Roger Allen
Sonork 100.10016

If I'm not breathing, I'm either dead or holding my breath.
A fool jabbers, while a wise man listens. But is he so wise to listen to the fool?

6-Mar-02 18:12

I'm trying to open recorset using command object, and retreve data from Access database.

m_pRds->Open(_variant_t((IDispatch *) m_pCmd, true), Parameter2, adOpenStatic ,adLockOptimistic, adCmdStoredProc);

what should I specify as Parameter2, cause when I put current connection there I'm getting error "Cannot change the ActiveConnection propery of a Recorset object which has a Command object as its source."

Re: How to open recordset using command object

Mazdak6-Mar-02 19:26

Mazdak

6-Mar-02 19:26

I cann't remember what exactly it was but O know you can pass it as _bstr_t(L"").

Mazy

"So,so you think you can tell,
Heaven from Hell,
Blue skies from pain,...
How I wish,how I wish you were here."
Wish You Were Here-Pink Floyd-1975

(read) rand() function.

SilverShalkin6-Mar-02 16:05

SilverShalkin

6-Mar-02 16:05

why i posted (read) was because i already posted a thread just like this, and i wanted to renew it in a way. all the other responses were great, and i looked up allot of new things that helped allot. Now, the only part that i cannot seem to get to work is the rand().

If there is an artical or webpage that explains random numbers, please give me the address, or link. Thanks.

But if there is not, or you simply dont know, or dont care about giving it, or like to respond to questions. my question is... "Like the old one"

I want to generate a number in a random form. 1-10. with the number, i wanted to use if statments such as:

if (rand() == 1);
somthing
if (rand() == 2);
somthing

And so on. I dont know if that is how you declare an if statment with a rand(), just bean toying with for a long while, and that seems most correct at the moment.

on the other thread i got the response of

rand()%11 was for 1-10. But i dont think that is the end of it, what else am i suppose to add to this, or is it the end?

If that is the case, then, how do you declare a rand() to = to 0?

Thanks all.
~SilverShalkin

ps... as you can see, im at the point of hair ripping. sorry if some of this is hard to understand or unorganized. "simply tired"

Rose | [Rose]

"for life is to precious to spend in the dark wonders of a dream,
but without it, life simply becomes a dream." "some can relate Smile | :)

Serge Krynine6-Mar-02 16:36

6-Mar-02 16:36

I want to generate a number in a random form. 1-10. with the number...

That's how you do this:

#include "stdafx.h"
#include <afx.h>
#include <stdlib.h>

void main()
{
srand(0);
while (1)
{
int rnd = rand() % 10 + 1;
if (rnd < 1 || rnd > 10)
{
printf("Out of range [1-10], rnd = %d\n", rnd);
return;
}
else
{
printf("generated rnd = %d\n", rnd);
Sleep(500);
}
}
}

SilverShalkin6-Mar-02 17:05

SilverShalkin

6-Mar-02 17:05

lets see,... could you do...

Serge Krynine wrote:
#include "stdafx.h" "could this be stdlib.h?"
#include
#include

void main()
{
srand(0);
while (1) "what does this do?"
{
int rnd = rand() % 10 + 1; "Do you have to do 10 + 1, or can you do 11?"
if (rnd < 1 || rnd > 10)
{
printf("Out of range [1-10], rnd = %d\n", rnd);
return;
}
else
{
printf("generated rnd = %d\n", rnd);
Sleep(500);
}
}
}

I got most of that, thanks, Ill try it out and see what happends.

~SilverShalkin

Nish Nishant6-Mar-02 17:22

Nish Nishant

6-Mar-02 17:22

SilverShalkin wrote:

#include "stdafx.h" "could this be stdlib.h?"

Actually stdafx.h is the VC++ precompiled header file Smile | :)

SilverShalkin wrote:
while (1) "what does this do?"

that's for an endless loop

Nish

[Signature temporarily down]

Serge Krynine6-Mar-02 17:25

6-Mar-02 17:25

a) Stdafx was generated by devstudio when I build a windows console app project, but yes stdio.h should do.
b) while (1) {} means “loop forever”; The idea of the test that if a random number would be out of [1-10], the test would exit; otherwise it will run forever (what I guarantee) (until you terminate it by ctrl+c or power off your PC).
c) the expression int rnd = rand() % 10; gives you random integers in the range [0-9] (from zero to nine inclusive). If you want the [1-10] range, add 1 then: int rnd = rand() % 10 + 1; Note that expression: int rnd = rand() % 11 does not give you correct range [1-10] because it can generate zero when the rand() function returns 11, so 11 % 11 gives you null.

Enjoy,
Serge

Christian Graus6-Mar-02 21:33

Christian Graus

6-Mar-02 21:33

The two #include statements with nothing besides them are the clue - the original poster forgot to tick 'no HTML' and so the includes in < > were lost.

I think no-one has bothered to explain the % operator - it means the remainder and can be used anywhere. So rand() generates a number between 0 and rand_max(). The remainer operator says 'what's the remainder if I divide by this', so if the number divides evenly by 10 in my example, I get a 0, and a value of 10 is not possible, because the highest number that can remain if I divide by 10 is 9, as in 29/10 = 2, 9 remainder.

The point of the endless loop I think is that if you ran it, you would never see 'out of range' come up, no matter how long you waited.... Smile | :)

Christian

The tragedy of cyberspace - that so much can travel so far, and yet mean so little.

"I'm thinking of getting married for companionship and so I have someone to cook and clean." - Martin Marvinski, 6/3/2002

SilverShalkin7-Mar-02 3:01

SilverShalkin

7-Mar-02 3:01

Thats cool, while (1) is a forever loop, i just wrote:

int x=1;
do
{
}
while (x == 1)

but i gues we all can see what one is faster. Smile | :)

Christian Graus wrote:
rand() generates a number between 0 and rand_max().

rand_max, how do you set how big it is? 0-rand_max right?

Well, thanks a bunch, I'm on the tip of the breakthrough, "Even though its not much of a break through Smile | :)

"

~SilverSahlkin

Rose | [Rose]

Tragedy is Romeo and Julyet, not a syntax error on your if statement! Rose | [Rose]