|
intrepid_is wrote: I have created a sorting algorithm that is better than Quick Sort...
How so?
"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15
"Judge not by the eye but by the heart." - Native American Proverb
|
|
|
|
|
I looked at it (even though he found "better experts" ha!  ) As I understand it, he needs knowledge of the smallest and largest value, so he has a better partitioning at quicksort.
Developers, Developers, Developers, Developers, Developers, Developers, Velopers, Develprs, Developers!
We are a big screwed up dysfunctional psychotic happy family - some more screwed up, others more happy, but everybody's psychotic joint venture definition of CP
Linkify!|Fold With Us!
|
|
|
|
|
Hello,
I'm a newbie in computer programming.
I'm looking for a program help me to change file attributes(Created time,Modified time and last access) like FileDate By T.YogaRamanan.
Here is link :
http://www.codeproject.com/file/FileDate.asp[^]
But I want to ignore its user interface.(No Dialog box , No Text box)
I want to choose file as coding and change file attribute as coding too.
I have tried to read source code of FileDate above.
I still can't do.
Can you help me ? 
Thank you.
|
|
|
|
|
This is not the right forum for your question. And dont re-post same topics all over the place.
"A good programmer is someone who looks both ways before crossing a one-way street." -- Doug Linder
coolestCoder
|
|
|
|
|
Hi guys,
I 'm a student of computer science from Indonesia
and newbie in vb6 programming. please, help me to
learn the algorithm of vb6. the following is algorithm
question.
1) Present the prime number between 1 up to 10 that use
"Mod" and "Print" function. the Object is only 1 command
button.
Note: forbidden use "int" function
thank's for helping me.
your sincerely
IRWAN
i need help in vb6 algorithm
|
|
|
|
|
Which part don't you understand? Ask a specific question, otherwise people here aren't going to do your homework for you.
The evolution of the human genome is too important to be left to chance.
|
|
|
|
|
Tim Craig wrote: people here aren't going to do your homework for you.
I find it amazing how many people don't seem to get the clue 
|
|
|
|
|
PaulC1972 wrote: I find it amazing how many people don't seem to get the clue
Lately it seems like most of them come from third world countries where the powers that be want to ship US jobs. They're too lazy to even try to do their homework and they get rewarded for it.
The evolution of the human genome is too important to be left to chance.
|
|
|
|
|
Maybe so on this site... have you recently checked Rent A Coder? I see a lot of US students posting homework questions there...
|
|
|
|
|
ChandraRam wrote: I see a lot of US students posting homework questions there...
Are you sure they really are in the US? Could be somewheres else in the world and making it look like they are in the US...
|
|
|
|
|
Have you actually looked for yourself?
|
|
|
|
|
Tim Craig wrote: third world countries where the powers that be want to ship US jobs
They can go ahead and do so. Any company that feeds these people will be in for a rude awakening when they find out their IT staff is so incompetent they leech off of people like us.
|
|
|
|
|
It is sad to read this kind of statements here. Helping each other is the main purpose of these forums. Not comparing IT staffs 
|
|
|
|
|
|
well, looks like no one here will help with the homework...
try this
private sub Commad1_click()
dim i as integer
for i=2 to 10 'why 2 cos 1 is not prime number
if i mod 2 =0 then debug.print i
next i
end sub
selamat berjuang....
|
|
|
|
|
AgusBudianto wrote: well, looks like no one here will help with the homework...
Because most of us here don't do people's homework for them. Your code does not work 100%.
|
|
|
|
|
ups my mistake, the code suppose to be something like this, sorry.. sorry..
for i=2 to 10
if i mod 2<>0 then debug.print i
next i
"if we dont want to help people, then don't at least don't say something rude to them" --how sad..
-- modified at 3:36 Sunday 3rd December, 2006
|
|
|
|
|
Hi I have spent the day looking at implementing RSA on the client side with javascript and on the server side with C#.NET.
I think I am overlooking something very simple and this is my problem. To make a key of 1024 bits requires a datatype to store it in. What datatype should i use, i considered byte[] but surely byte[]*byte[] is undefined (to create the key).
Any help will be greatly appreciated
Thanks
Dan
|
|
|
|
|
You need to find a library for integers of arbitrary length or write one yourself.
Cheers,
Sebastian
--
Contra vim mortem non est medicamen in hortem.
|
|
|
|
|
Write or find the class that will handel the 1024(or biger) bit long number.
if write see some algoritms like:
1) Baret reduction
2) Montgomeri multiplay
. . . .
you will ned them in class.
[ It will better if you write class]
|
|
|
|
|
My new project, I'm working on some path-finding algorithms for little AI
people. I have a grid of terrain heights and I have a pathing algorithm. The
trouble I'm having is how to weight the movement cost from one square to the
next. If moving across level terrain from one square to another is 1, how do
I cost uphill and downhill travel? I'm kinda stumped.
Also, moving diagonally is technically 1.41 in distance, should I cost it as such or just leave it as one for simplicity's sake? What are the pros and cons?
Any thoughts?
"Go to, I’ll no more on’t; it hath made me mad." - Hamlet
|
|
|
|
|
I think you should leave it as 1.41, otherwise you'll have funny results 
Regarding height, maybe a cost formula like sqrt(deltaX^2 + deltaY^2 + (k*deltaZ)^2) might do
You could change the k coeff if climbing is more or less expensive than moving horizontally.
|
|
|
|
|
Wow. It never occured to me that the Pythagoreum thing worked in three dimensions. Thanks. That helps a lot.
My question is though, what to change the value of k to? If the target square is n higher or n lower, how do you cost it for the expense of climbing uphill, or downhill as compared to walking over level ground? I thought about giving it an arbitrary value based on the difference in terrain heights, but that seemed kinda clunky to me.
What I should do I suppose is find a chart on the internet of the amount of calories burned in walking as opposed to stair-climbing and wall-climbing. That might help.
Thanks again.
----------------------
...ten minutes later
Okay, I looked up the calorie charts and it turns out that stair-climbing is approximately double straight walking, and wall-climbing is approximate triple straight walking. So if I convert that to angles:
0 = 1
45 = 2
90 = 3
Now how do I convert that into a formula so that values in between return their appropriate costs?
I'll assume the values are the same for going down in terrain as well, though they might be slightly cheaper.
-- modified at 9:13 Thursday 9th November, 2006
cost = 1 + (angle / 45)
d'uh. I better get some coffee. Thanks all.
-- modified at 9:27 Thursday 9th November, 2006
"Go to, I’ll no more on’t; it hath made me mad." - Hamlet
|
|
|
|
|
I felt curious about the calories issue, i think it is a good idea of giving values to k I've found this link:
http://www.calorie-count.com/calories/activities/17.html
Regards
|
|
|
|
|
I figured it out. Thanks, kind sir.
k = 1 + (angle / 45)
Now to figure out how to calculate the angles... 
"Go to, I’ll no more on’t; it hath made me mad." - Hamlet
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
