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Hi guys,
I'm using XmlFormView control to display an InfoPath form inside a custom aspx page. In order to load the form I can use XmlLocation which rapresents an Url to the .xml file. Does anyone know if it could be possible to inject Xml from memory (for example from a memory stream) instead of accessing the xml file? In other words I need to have the property XmlFormView.XmlForm setted without setting the XmlLocation property.
Thank you in advance.
Stefano
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Hi
I am doing an application in which I am using a XML file to populate a datagrid.
In that XML file I have one like.....
<>
1.To generate leads efficiently and profitably.
2.To ensure that all details are collected in one call.
3.To provide email and chat support.
4.To manage Work Basket reports as required.
5.To meet targets for both quantity and quality.
<>
When I am trying to populate this column onto datagrid, all these lines or sentences are getting combine and displaying like a paragraph.
I want to know how to format this column to get them in the a new line
Thank u
Chandu
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K V S Chand wrote: populate this column onto datagrid,
What does that mean? Are you using DataBinding?
led mike
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Column means a column in XML.
Yah, I am binding XML data to a DataGrid using dataset.
Thank u
Chandu
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K V S Chand wrote: Column means a column in XML.
There is no such thing as a "column" in XML. If you plan on using text based communications for solving your programming problems don't you think it might be a good idea to learn and use the standard terms for a given technology? Otherwise how do expect to be able to communicate. XML has nodes and elements and attributes, no columns, so I have no idea what you are talking about.
led mike
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i created an xml file using xml serialization for a c# CLASS.
BUT I GOT ALL THE FIELDS FROM THAT CLASS. HOW CAN I REMOVE UN NECESSARY ATTRIBUTES.
CAN ANYBODY HELP ME PLEASE?
KSRS
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First, please don't shout.
Second if it is class that you have created simply apply the [System.Xml.Serialization.XmlIgnoreAttribute] to the properties that you don't want to show.
If it is a framework class, you need to get the data from the XMLSerializer object to an XML document object for manipulation. If this is the case and you have problems with this, please post the specifics.
topcoderjax - Remember, Google is your friend.
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hi iam new to the Xpath
could anyone help me?? i just want to pick up countryname which is element and it has a attribute for the code. i want to pick these values from the XmlDoc
the code here as follows:-
Dim CountryPropExpr As XPath.XPathExpression = Nav.Compile("./CountryName[@Code=""]")
Dim CountryPropIter As XPath.XPathNodeIterator = Nav.Select(CountryPropExpr)
If CountryPropIter IsNot Nothing AndAlso CountryPropIter.Count > 0 Then
Try
Dim CountryNameCode As String = getNodeValue(CountryPropIter.Current.SelectSingleNode("./CountryName[@Code=""]"))
For Each CountryNameCode In CountryPropIter
CountryNameCode = CountryPropIter.Current.Value
Next
Builder.AppendLine("<countryname code="" ""="">")
Catch ex As Exception
Debug.Write(ex.Message)
End Try
End If
when i compile it didn't pickup the values.
Thanks Heaps in Advance
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Please provide a document fragment. Without the XML, there is noway to test the validity of your method call.
"In quiet and silence, the truth is made clear."
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Could someone advise me on the syntax to use to get the IXMLNode whose attribute id="abc" so in the XPath expression used to SelectSinglenode you would specifiy the @id="abc" or whatever the correct syntax is so as to select the Node whose attribute id has the value == "abc".
Thanks.
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Basically, I want to locate and return any Node in the XML document which has an attribute id equal to the id I am searching for.
I have been trying with XPath's such as:
"//*[@id( 'abc' )]"
But alas so far I have not found the correct syntax. 
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I managed to get this to work thus:
"//*[@id='" + sURI + "']"
Thanks
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I have a complex XML document and the associated XSD document. But I don't have a XSL document. I want to display the XML in a HTML viewer. Is there any way to create a XSL from the XSD and XML or do you have no option but to create the XSL file to display how you want?
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Andy H wrote: I want to display the XML in a HTML viewer.
What does that mean? If you open an XML file in Firefox or Internet Explorer they will display them for you.
led mike
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In addition to what Mr. led mike said, it may be possible to create XSLT from the XML document's XSD but it won't be worth the effort. To create a HTML document that meet your needs, you must create the XSLT manually or settle with the default XSLT in IE and Firefox.
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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George L. Jackson wrote: or settle with the default XSLT in IE and Firefox.
You can get the XSLT from IE. actually it's in the MSXML3.dll I think.
led mike
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led mike wrote: You can get the XSLT from IE. actually it's in the MSXML3.dll I think.
Well Said led Mike.
Regards,
Satips.
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 Thanks Mike! I messed up. It is a resource of MSXML3.DLL and you can view IE's default XSLT via this URN: res://msxml.dll/DEFAULTSS.xsl.
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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Hi all
I have XML document and I need to add gif file.
I dont now XML and can you help me.
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david bagaturia wrote: I dont now XML and can you help me.
Did you try Google[^]
or maybe this would help more[^]
led mike
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 Hmmm, an explicit display of tough love. Someone will need a man hug after this.
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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You can use Base64 or quadrosexagesimal! Please use Google to find more information.
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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I'm trying to serialise a graph structure to XML.
Everything is working fine except for one object which is alwasy coming out as an empty element. Even if I serialise it on its own. Its the most important object as it represents the link. Any idea why it wouldn't show any attributes?
Heres the code:
<br />
[Serializable()]<br />
[System.Xml.Serialization.XmlInclude(typeof(ParticipantNode))]<br />
public class EdgeToNeighbour<br />
{<br />
#region Private Member Variables<br />
private string id;<br />
private Node neighbour;<br />
#endregion<br />
<br />
#region Constructors<br />
public EdgeToNeighbour() <br />
{<br />
}<br />
<br />
public EdgeToNeighbour(Node neighbour)<br />
{<br />
this.neighbour = neighbour;<br />
this.id = neighbour.Key;<br />
}<br />
#endregion<br />
<br />
#region Properties<br />
public Node Neighbour<br />
{<br />
get<br />
{<br />
return neighbour;<br />
}<br />
}<br />
public string ID<br />
{<br />
get{return id;}<br />
}<br />
#endregion<br />
}<br />
I've tried ignoring the complex type, i've tried adding XML text, I've tried lots of different combinations of XmlAttribute etc. but i always end up with this:
Serialised on its own:
<br />
<EdgeToNeighbour xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" /><br />
Serialised as part of the graph structure:
<br />
<anyType xsi:type="Node"><br />
<Data><br />
<ID>2</ID><br />
<TypeID>0</TypeID><br />
<Name>A Node</Name><br />
</Data><br />
<Edges><br />
<EdgeToNeighbour /><br />
<EdgeToNeighbour /><br />
</Edges><br />
</anyType><br />
All I want is for edge to neighbour object to show the attribute ID so I can see the nodes it is linked to.
Thanks in advance.
Rob.
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