Re: Determining when application is running in debug mode - C# Discussion Boards

Re: How to run a Win16 program?

1-Jul-07 9:03

Hi,

maybe there are some security issues, and .NET does not like 16-bit exe files, just like it
does not like exe files on a networked disk by default ?

You could try to run
cmd.exe /C your16bitApp.exe optionalArgs
using the Process class (with UseShellExecute=true)

Not sure this will help tho, and if it works, maybe the WaitForExit will not work properly !

Hope this helps.

Smile | :)

Luc Pattyn

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Mackster2111-Jul-07 9:10

Mackster211

1-Jul-07 9:10

Didn't work - same exception.

I appreciate the attempt, though!

Cheers,
Kevin

Re: How to run a Win16 program?

Luc Pattyn1-Jul-07 10:05

Determining when application is running in debug mode

1-Jul-07 10:05

Hi again,

does this also happen with some other 16-bit app, or just the one ?

does XP include some 16-bit app so I could try the same ?

Smile | :)

Luc Pattyn

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theFrenchHornet1-Jul-07 7:59

Re: Determining when application is running in debug mode

1-Jul-07 7:59

As far as I can tell, if the Visual Studio hosting process is enabled, then when Start Debugging is selected, no new process is added. If you look at the Task Manager Processes tab, you see xxx.vshost.exe when the IDE is open and still only see that when the application is being run (debugged). The place where you _can_ tell a difference is the Applications tab of the Task Manager. I know how to get the list of processes that show up in the task manager Processes tab. How do I get the list of applications that show up in the Applications tab?

Thanks ...

Luc Pattyn1-Jul-07 8:54

Re: Determining when application is running in debug mode

1-Jul-07 8:54

Hi,

I am not sure what you want, a debug build of your app can be running either with or without
vshosting, but both cases are "debugging".

If you want your app to know whether it is running through vshost or directly, have
it search Environment.CommandLine for ".vshost."

If you want your app to know whether it is a debug or a release build, the easiest way
is to conditionally include/exclude some code using #if DEBUG ... #endif

Hope this helps.

Smile | :)

Luc Pattyn

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theFrenchHornet1-Jul-07 10:21

Re: Determining when application is running in debug mode

1-Jul-07 10:21

Thanks for the suggestions - don't think they will solve this problem. Yes, both cases are "debugging" but I specified I was interested in the case where vshosting is enabled because I can detect what I need to know in the case where it isn't. Environment.CommandLine won't tell me because it is another instance of the application that needs to know. I do not need to determine between debug and release versions. What will tell me what I need to know sits in the Applications tab of the Task Manager - do you know how to access that info? The other way I see is if there is some property of the vshost process which indicates whether it is running the application currently or not. Seemed easier to me if I could access the Applications tab of the task manager.

Luc Pattyn1-Jul-07 10:56

Re: Determining when application is running in debug mode

1-Jul-07 10:56

Hi,

getting the list of items shown by "app" tab in Task Manager is complex; it entails
finding the right window (i.e. knowing the names of the windows in its hierarchy),
then sending some LVM_... messages to the listview. It must be similar to enumerating
the notify icons in the system tray, and the icons on the desktop. Each of these
can be found in several CodeProject articles.

I dont think reading that list is a very good idea; it is complex and the names you would
get are Window titles, which does not necessarily correlate well with the process names...

Using TaskInfo I noticed the vshost.exe process has quite different characteristics
(CPU time, working set, number of windows, ...) when comparing an idle state with
an active debug state.

So if what you want to figure out is whether something is being handled by vshost,
I suggest you get hold of its PID (using Process class), then do a P/Invoke to
either get its main window title, or to enumerate all its windows (zero when not active).

Smile | :)

Luc Pattyn

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theFrenchHornet1-Jul-07 11:04

1-Jul-07 11:04

The window title would work fine - doesn't need to correlate with the process name. I was searching for task manager before - I'll try your system tray idea - do seem to remember seeing some items on that. Will also look into your idea of vshost characteristics - thanks.

More on Task Manager

Luc Pattyn1-Jul-07 11:30

Re: Determining when application is running in debug mode

1-Jul-07 11:30

Hi,

some additional thoughts regarding Task Manager:
- it is not always running; so you cant enumerate its apps when it does not run
- when running, another tab may be visible; dont know whether it keeps updating tabs
that are not visible...

So I strongly suggest you go for the process characteristics...

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

theFrenchHornet3-Jul-07 8:19

Re: Determining when application is running in debug mode

3-Jul-07 8:19

Your idea of getting the main window helped. Thanks.

Luc Pattyn3-Jul-07 11:00

Re: Determining when application is running in debug mode

3-Jul-07 11:00

You're welcome.

Luc Pattyn

[My Articles] [Forum Guidelines]

Miguel Lopes1-Jul-07 11:57

Miguel Lopes

1-Jul-07 11:57

string exePath = Application.ExecutablePath;

exePath = exePath.ToLower();

if (Application.ExecutablePath.ToLower().IndexOf("devenv.exe") > -1)//design time
{

}
else
{
}

Re: Determining when application is running in debug mode - solution

theFrenchHornet3-Jul-07 8:18

Passing cmd line arguments to registry value during install

3-Jul-07 8:18

Evidently, there is no easy way to access the same information as that in the applications tab of the task manager the way one can easily access the same information as that in the processes tab. Or, if there is, it isn't obvious to any of us. Instead, I used the method below (resulted from suggestion by Luc Pattyn) to determine whether the IDE simply had the application open or was running it.

Note - non-relevant portions of code omitted (the ...'s).

const string IDE_INDICATOR = ".vshost";
Process current = Process.GetCurrentProcess();
string IDE_Name;

...

if (current.ProcessName.Contains(IDE_INDICATOR))
{
  IDE_Name = current.ProcessName;
}
else
{
  IDE_Name = current.ProcessName + IDE_INDICATOR;
}


... (looping through all processes)

if (process.ProcessName == IDE_Name)
{
  IntPtr WindowHandle = process.MainWindowHandle;
  if (WindowHandle != IntPtr.Zero)
  {
    // then application is being run by the IDE 
  }
  else
  {
    // IDE is open with the application loaded, but not currently running it  - at least not in debug mode,
    // and non-debug mode can be detected because it has its own process
  }
}

Miguel Lopes1-Jul-07 6:27

Miguel Lopes

1-Jul-07 6:27

Hello,

I need to pass a command line argument containing a database connection string to the registry.
I pass it to a windows installer exe made with VS2005. I can obtain the string from inside the installer. But if i try to manually insert it, for example in

void ProjectInstaller_Committed(object sender, InstallEventArgs e){...}

i can read the registry but when i try to SetValue, i get an exception. Probably lack of permissions.

Is there any way to do this?

Thanks in advance!

Big Problem with WebService

Iftekhar Naim1-Jul-07 5:17

Iftekhar Naim

1-Jul-07 5:17

I need to connect to multiple servers and call their web methods of the webservice. But the problem is - the IP address of those servers will be known to me only in run time and this list may change.

The same web-service will be running in each of these servers except that- they have different IP Addresses.

I accessed web-services from clients by adding the web-services as web-reference(with specifying web url). But in this case- it doesn't seem possible.

Can anyone please give me some ideas about how i can do this?

thanks

Chayan

Re: Big Problem with WebService

Guffa1-Jul-07 6:37

Guffa

1-Jul-07 6:37

Add a reference to one of the services. Once you have created an instance of the generated class, you can change the Url property to make it connect to any of the servers.

---
single minded; short sighted; long gone;

Re: Big Problem with WebService

Iftekhar Naim1-Jul-07 14:00

Iftekhar Naim

1-Jul-07 14:00

thanks a lot man !!! this is such a simple and cool solution..thanks for the great help.

Chayan

Generic

Jeeva Jose1-Jul-07 4:34

Jeeva Jose

1-Jul-07 4:34

How can add two numbers through generic function and the type is int or double or float
anybody help me. OMG | :OMG:

Continue...

DavidNohejl1-Jul-07 7:40

DavidNohejl

1-Jul-07 7:40

I didn't test it but this should work:

T Add<T>(T x, T y) where T: int, double, float
{
   return x+y;
}

"Throughout human history, we have been dependent on machines to survive. Fate, it seems, is not without a sense of irony. " - Morpheus
"Real men use mspaint for writing code and notepad for designing graphics." - Anna-Jayne Metcalfe

Not Active1-Jul-07 11:52

Not Active

1-Jul-07 11:52

You should have tested it then

'int' is not a valid constraint. A type used as a constraint must be an interface, a non-sealed class or a type parameter.

'double' is not a valid constraint. A type used as a constraint must be an interface, a non-sealed class or a type parameter.

'float' is not a valid constraint. A type used as a constraint must be an interface, a non-sealed class or a type parameter.

Operator '+' cannot be applied to operands of type 'T' and 'T'

only two letters away from being an asset

DavidNohejl1-Jul-07 13:19

DavidNohejl

1-Jul-07 13:19

Oh, thank you. That was too cool to work Blush | :O

Ok so unless I am missing something obvious it's not as easy as it looks...

IConvertible Add<T>(T x, T y) where T : IConvertible
{
return (IConvertible)(x.ToDouble(CultureInfo.InvariantCulture)+y.ToDouble(CultureInfo.InvariantCulture));
}

Doesn't look that bad, but that's still not it. I don't want to return IConvertible but T, I want T to be only int, float or double (looks like this is impossible with where).

Whatever, why not do just

int Add(int x, int y){return x+y};
double Add(double x, double y){return x+y};
...