Visual Basic

Please tell how to update data using web service

7-Sep-07 9:48

Check into the DataGridView.RowHeadersDefaultCellStyle Property[^].

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Dubey Yogendra7-Sep-07 6:15

Dubey Yogendra

7-Sep-07 6:15

Hai to all dear friends, I am developing an 2 tier windows application in vb.net . In this project i used web service to access data .
I am seeking problems in updating and adding new records in my sql database through web service .

Please help me .
also if u may suggest any other option to create 2-tier application .
I will very very thankful to u .

Yogendra Dubey
email :- mesagetoyogi@gmail.com

Re: Please tell how to update data using web service

Dave Kreskowiak7-Sep-07 8:34

7-Sep-07 8:34

I'm not sure what you're looking for here. The web service is going to have to expose a few public methods for you to call to tell it to how update the database. I'd imagine you'd have to supply a method for each of the possible SQL update methods, like UPDATE, INSERT, and DELETE.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Cash Drawer Opening

imla7-Sep-07 5:32

imla

7-Sep-07 5:32

Can anyone help me with a code to open a cash drawer in VB.Net 2003. I am stuck please assist me. I am new to hardware commands.

rgds
initial

BooleanTrue7-Sep-07 5:37

BooleanTrue

7-Sep-07 5:37

you think we all are idiots here?

colgateas900197

Luc Pattyn7-Sep-07 5:45

Luc Pattyn

7-Sep-07 5:45

imla wrote:
I am stuck

inside the cash drawer?

Luc Pattyn [Forum Guidelines] [My Articles]

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The ANZAC7-Sep-07 20:19

The ANZAC

7-Sep-07 20:19

LOL!!!

Please check out my articles:
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Dave Kreskowiak7-Sep-07 5:51

7-Sep-07 5:51

We can't answer the question because you haven't said anything about how the cash drawer is connected to the machine, nor what commands to send, or anything else we need to know to give you a useful answer. Well, other than telling you what you need to do would be covered in the manual for the cash drawer...

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Christian Graus7-Sep-07 6:25

Christian Graus

7-Sep-07 6:25

Dave Kreskowiak wrote:
Well, other than telling you what you need to do would be covered in the manual for the cash drawer...

Which is what we were bound to say anyhow....

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

Dave Kreskowiak7-Sep-07 6:53

7-Sep-07 6:53

Oh, crap!

Did I give away too much information?? Laugh | :laugh:

I don't know...It seem'd like I was over stating stating the obvious. Or was I being too dramatic? My performance wasn't too "over the top", was it? What do you think?

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Christian Graus7-Sep-07 6:57

Christian Graus

7-Sep-07 6:57

*grin*

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

imlambo8-Sep-07 4:16

imlambo

8-Sep-07 4:16

The truth is that the system should be able to open any cash drawer nommatter how they are connected(either direct to a computer or through a receipt).

I will look for the commands for all the drawers and then define them or allow the users to define the commands to open their drawer.

I need the source code that sends any commands.

I need a step by step approach here. help me.

Thanks

Fear The Lord

Dave Kreskowiak8-Sep-07 6:03

8-Sep-07 6:03

You have another problem. Not all cash drawers work on a Serial port. Some are USB, others are custom Parallel implementations, and I've seen a couple on custom interfaces.

There's n standard to follow here. You're going to have to write plugin modules to support the type of interface that the draw is using. You might want to limit your app's support to just serial and usb drawers.

imlambo wrote:
I need the source code that sends any commands.

To support Serial drawers, all you have to do is Google for "VB.NET Serial Port" and you'll find hundreds of examples.

imlambo wrote:
I need a step by step approach here.

If you're asking this question, you're in serious trouble with this project.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Re: Cash Drawer Opening [modified]

imlambo9-Sep-07 23:19

imlambo

9-Sep-07 23:19

Thanks very much for the advice.

I have decided to follow the following approach:
A) For Printer Driven Cash Drawers:
I will give an interface to define Printer settings as follows:

1)Printer Ports:Lists all Printer Ports on Computer and user selects.
2)Drawer Opening commands:to open the specific Drawer.eg.

I have googled the following code for use: To send commands to the Printer(EPSON) To Open the drawer.

Public Sub open_cashdrawer()
Dim intFileNo As Integer = FreeFile()
FileOpen(1, "c:\escapes.txt", OpenMode.Output)
PrintLine(1, Chr(27) & "p" & Chr(0) & Chr(25) & Chr(250))
FileClose(1)
Shell("print /d:lpt1 c:\escapes.txt", vbNormalFocus)
End Sub

I will put this code before a receipt is printed.
My problem is that I do not have hardware and I am trying to design a system which should fit all Printers hence giving users to select ports and commands to open drawers.

I need to go to the client with a working solution and I need assurance whether this will work.

B)Connected Serially and Parralell.
Wish to follow when done with above.
thanks in advance

Fear The Lord

Manuel F. Hernandez7-Sep-07 6:36

Manuel F. Hernandez

7-Sep-07 6:36

Does your cash register have a large lever? I've heard that reuse helps to leverage your code.

-- modified at 12:58 Friday 7th September, 2007

Nested Datagrid Error Checking - Help

Smokeywade7-Sep-07 3:41

Smokeywade

7-Sep-07 3:41

I have One Datagrid with a dataset that calls two tables - the First table is the table the user will be editing - which edited on the grid or in a textbox - as the user edits the grid - that info is automatically updated onto the database - My problem is - when user goes to the nested table the application is still looking for parameters to update the database - which is causing errors - how will I prevent this from happening on the second table here his my code snippent - I know it has to have something to do with MyDataset.Tables(1) but I can not get the syntax down for this at all.

 'frmload<br />
  Dim command1 As New SqlCommand("Select * FROM LateOrders_Header_view", cnn1)<br />
        Dim command2 As New SqlCommand("Select * from LateOrders_Line_view", cnn1)<br />
        'Dim SqlReader As SqlDataReader<br />
        Try<br />
            cnn1.Open()<br />
<br />
            'Debug.WriteLine(cnn1.ConnectionString)<br />
            Dim dt As New DataTable("LateOrders_Header_view")<br />
            dgOrderReport.DataSource = dt<br />
            Dim DirAdapter As New SqlDataAdapter(command1)<br />
            Dim DirAdapter2 As New SqlDataAdapter(command2)<br />
            Dim dc1 As DataColumn<br />
            Dim dc3 As DataColumn<br />
            Dim datarelation As DataRelation<br />
<br />
            MyDataSet = New DataSet<br />
            MyDataSet = New DataSet<br />
            DirAdapter.TableMappings.Add("table1", "LateOrders_Header_view")<br />
            DirAdapter.TableMappings.Add("table2", "LateOrders_line_view")<br />
<br />
            DirAdapter.Fill(MyDataSet, "LateOrders_Header_view")<br />
            DirAdapter2.Fill(MyDataSet2, "LateOrders_Line_view")<br />
<br />
            dc1 = MyDataSet.Tables("LateOrders_Header_view").Columns("order_no")<br />
            dc3 = MyDataSet.Tables("LateOrders_Line_view").Columns("order_no")<br />
            datarelation = New DataRelation("Line View", dc1, dc3)<br />
            MyDataSet.Relations.Add(datarelation)<br />
            'dc3.ReadOnly = True<br />
<br />
            dgOrderReport.DataSource = MyDataSet.DefaultViewManager '.CreateDataView.Tables("LateOrders_Header_view").DefaultView<br />
            dgOrderReport.DataMember = "LateOrders_header_view"

'This controls the grid click event - This is where I believe I need to add something to let it know that this dosent apply to the second table
How do I let it know not to do this (below) for second table.

 <br />
    Private Sub dgOrderReport_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles dgOrderReport.Click<br />
        Try<br />
<br />
            txtReason.Text = dgOrderReport.Item(dgOrderReport.CurrentRowIndex, 4) & ""<br />
            txtReason.Enabled = False<br />
            chkReason.Checked = False<br />
<br />
        Catch ex As Exception<br />
            MessageBox.Show(ex.Message)<br />
        End Try<br />
       <br />
    End Sub<br />

Any Ideas....

Thank You

Re: Nested Datagrid Error Checking - Help

Dave Kreskowiak7-Sep-07 9:44

my Custom control cannot be created dynamically

7-Sep-07 9:44

This looks like a normal master/detail setup. I would suggest start by looking at some samples, like these[^].

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

BooleanTrue7-Sep-07 3:04

BooleanTrue

7-Sep-07 3:04

Hello!
I have created a custom control, build it and added its reference in my main application...
Control apears in tool box! When i drag it on my main form (at design time)its ok but when i want to create it dynamically like: Dim myc as new
i could not find name of my custom control to create it on run!

Any clue, How can i access it dynamically?
Thanks in advance

colgateas900197

Re: my Custom control cannot be created dynamically

Duncan Edwards Jones7-Sep-07 3:32

Duncan Edwards Jones

7-Sep-07 3:32

If its in a different namespace or assembly than teh code referencing it then do you have an imports statement for that?

'--8<------------------------
Ex Datis:
Duncan Jones
Merrion Computing Ltd

Re: my Custom control cannot be created dynamically

BooleanTrue7-Sep-07 3:36

BooleanTrue

7-Sep-07 3:36

Oh no! That was the problem!!!!
It works! Thankyou...
God bless you my friend!

colgateas900197

Combobox problem

Xerox47-Sep-07 1:05

Xerox4

7-Sep-07 1:05

I have a problem. I have stored data in the database of particular locations. These locations have Ids .I want to use a combobox to retrieve the names of the Locatios(Towns-Selects only those in database )but save the id in the persons table. Any way to go round this?

plural7-Sep-07 1:25

plural

7-Sep-07 1:25

create relations bxn the tables and normalize your database to make it easy otherwise.

try this code but correct the syntax

select the names from locations where id=(select id from persons)

( the only the ID will be in the combobox)

make the syntax correct.

am still a novice so hope sam1 else helps u too.

phatkin

Xerox47-Sep-07 1:38

Xerox4

7-Sep-07 1:38

I have 2 tables
Town(townId,TownName)
Persons_table(Id,Name,TownId)
I would like to use a combobox to display the TownName but the save the TownId in the Persons_table(use to use by the User)

Tom Deketelaere7-Sep-07 2:22

Tom Deketelaere

7-Sep-07 2:22

make a class clsTowns with 2 variables: iid and sname
make 2 public property's in that class id and name
override tostring in the class:
public overrides tostring
return sname

then in the form get all the records from db put each record in a variable of you'r class
and add the class variable to the combobox
dim t as new clstowns
t.id=db.id
t.town=db.town
cbo.items.add(t)

then when you're user selects a item in the combobox the selecteditem contains you're variable of the type clstowns

dim t as clstowns = cbo.selecteditem

and the id can then be extracted from you clstowns variable
dim id as integer = t.id

then you can write it to the db in the persons table

this is only 1 way to do what you want there are other and perhaps better ways

hope this helps

If my help was helpfull let me know, if not let me know why.

The only way we learn is by making mistaks.