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Hai venkatesh,
Thanks for ur reply,No in my database it is only a number.
Is there any javascript or for number type do i need to do some changes for properties.
Plz help me out.
Second problem solved.
kissy
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Kissy16 wrote: Also how to remove the history of a textbox values??
Like if i insert more than two records,textbox is giving the previous data for that textbox for the next time.I dont want to show the already entered data.
Which property i need to set??
Just set the autocomplete property to off.
You can directly code it on the HTML. For example:
<INPUT TYPE="text" AUTOCOMPLETE="off">
Or on the ASP.NET, you can set the TextBox property of AutoCompleteType to AutoCompleteType.None in your code.
best regards,
Eriawan
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i have a dropdownlist.On form load it is being populated.Now the thing is i want to set it's selected index = -1.but it shows index = 0 .how i should make the selected index = -1
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Try,
DropDownListControl.SelectedIndex = -1
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it is not allowing to make the index = -1
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Yep... Its not allowing.
To overcome this, the only solution is inserting an item at the index 0 and set the SelectedIndex to 0.
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i have to insert a static value , if there exists one or more values the add new item can be placed at last position.what it ? i am not having any item, i am invoking a funciton on selection change , if it is having no value , add new will come at index 0 , i will than , unable to call the funciton on selected index change
Hope u got my problem.
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Sonia Gupta wrote: if it is having no value , add new will come at index 0
If dropdown is having only one value, it won't post back on change. Why don't you add a (Choose any item) to index 0 and (Add new) to index 1, which solves the problem.
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i am populating the dropdownist from database as well.if i add the string choose the item before updating the dropdownlist , it excludes this item from the list and fill the dropdownlist with items from the database.
now at last , after updating the control with the database , i am inserting two new static items at Runtime.
1.choose the item
2.add new.
now the problem is , i want to put the item choose the item at the top of the control and add new at the rear of the control.
how i should do it?
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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DropDownList.Items.Insert(0,"(Choose items)");
DropDownList.Items.Insert(DropDownList.Items.Count-1,"(Add new)"); Have you purchased a book ?
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U the best Book.Thanks It is working.
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Sonia Gupta wrote: t shows index = 0
Every control ,which has DataSource method,has starting index 0.
So how can you select index -1?
Sonia Gupta wrote: i should make the selected index = -1
You can not but you can give value -1 to ListItem of dropdownlist and check what you want.
bEst Regard
pAthan
please don't forget to vote on the post that helped you.
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if understood what u want my suggestion is:-
save the result comming form the database in DataTable (dt)
then make for loop to insert the values
but the first item let be
ListItem li1=new ListItem ("Select...","-1");
and add it into ur dropdownlist.then add the item u want to.
if u bond the List u cant add the item with the value "-1"
tegards
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i made a profile page in my application and now i want that user can load his picture with all other information
please help me out how do i store / load picture in database along with all other information of the user
waiting for replies as soon as possible
regards 2 all
kanza
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Is google[^] not working there in Pakistan ?
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hi
In my asp.net applicaton i populate my dropdown list using ajax.
its displaying the values.but the problem is after select the value the values in dropdown list are disapper.
here i am taking data from a new form by open that form using ajax .
plz help me to solve this problem asap
regards
venkat
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venky456 wrote: In my asp.net applicaton i populate my dropdown list using ajax.
venky456 wrote: but the problem is after select the value the values in dropdown list are disapper.
I think, you have enabled AutoPostback property. As you populated the DropDownList using AJAX, it difficult to maintain the ViewState after the Page postbacks.
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post your code
please don't forget to vote on the post that helped you.
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Hi,
Friends help me..when i am uploading a file i want to check the file extension...how will i get the file extension..pls give me a help..
regards
alex.
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assume your file upload control is FileUpload1
if (FileUpload1.HasFile)
string fileExtension = System.IO.Path.GetExtension(FileUpload1.PostedFile.FileName)
Hope it helps
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Hi Guffa , Navaneeth,
I posted this query earlier.But not getting , how to overcome the problem .
i have a java script funciton and a button server control in aspx page, which i am invoking at the form closing.Now the problem is , the same function is executing on button click as well as on the form closing button.
i was told by Guffa in this link and in this link
by setting the variable in onclick of the button, and check the value of the variable in the abc function.
My question is how i should declare the global variable , and how i should check it's value in the funciton
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Sonia Gupta wrote: Hi Guffa , Navaneeth,
Please don't address the question to specific member(s). This might prevent others replying to your pos. As Guffa said in his post, you can declare a variable inside a script and outside a function. This will be treated as public variable. See the example below
<script language='JavaScript'>
<!--
var Submitted = false;
function window_onbeforeunload(e) {
if (!Submitted) {
return(confirm("Are you sure to exit"));
}
}
</script> When any button is clicked, make this Submitted=true, which will avoid displaying the message.
Hope it helps
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<body OnBeforeUnload = "window_onbeforeunload();">
this is the event on body tag , in besides to ur code.still occuring the message , on button click as well as on the form closing
Soniagupta1@yahoo.co.in
Yahoo Messenger Id = soniagupta1
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Sonia Gupta wrote: on button click
Show me your button click JS code
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