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You know this review[^]?
Let's think the unthinkable, let's do the undoable, let's prepare to grapple with the ineffable itself, and see if we may not eff it after all. Douglas Adams, "Dirk Gently's Holistic Detective Agency"
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Nice article, thanks. I guess I'm not the only one who's had trouble with Jam then. Unfortunately I hate and am hopeless with make as well which is really disabling me from doing proper cross platform development. I guess I'm going to have to spend some time with a hefty make tutorial and write my own front end...Hmm XML to make using a recursive decent parser ... Visual Studio solution to platform indpendent XML using XSLT ... Visual Studio AddIn to export ... GCC build for MinGW ... next time I've got a spare month
Nothing is exactly what it seems but everything with seems can be unpicked.
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Wow! You have given a lot of stuff to read/know about, thanks dude!
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hi
i have a application when i click the close button(X) , it must goes to the tray but it should be running ...
(i did a project when i click minimize button(_) it goes to tray . it is perfectly working)
k.guru moorthy
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Have you tried to handle the WM_CLOSE event and write your code to send your application to tray there?
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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Hi,
I have a modal dialog with two edit boxes, one of them read-only, and a button. I want to transfer the integer written into the first to the second when the button is pressed.
I have added variables(int iVar, iCalcValue) to the edit-boxes and an event handler to the button, but I don't know where and how to write the data update code so the value is shown on the screen.
Sorry for such a silly question, I'll get better after some time
Thanks
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Call UpdateData(true) before you read value from the control and update the member variable. Call UpdateData(false) before you update the control on the screen to reflect the value of the member variable.
UpdateData(true);
m_edit2 = m_edit1;
UpdateData(false);
Remember that UpdateData() will update the state of every other control and member in your dialog as well.
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
modified on Tuesday, February 12, 2008 4:49 AM
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In the button event handler, call
(1) UpdateData(TRUE);
to assign to the variable iVar the (numeric value corrensponding to) edit box text.
Then set:
(2) iCalcValue = iVar;
and, finally, call
(3) UpdateData(FALSE);
to set the edit box text according to iCalcValue .
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
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Thanks guys, I really appreciate it.
I'll come back with something more difficult next time
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Hi guys can any one tell me whether there is an inbuild function that converts hexa value to decimal.
I have used sscanf(charVar,"%X",intVar) when I do this the output is same as that of input (i.e., same hexa value). can any one help?
Regards,
lgatcodeproject
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lgatcodeproject wrote: converts hexa value to decimal.
That doesn't really make sense to me. A value is a value, it's only a representation of that value that can be decimal or hexadecimal. In your sample, you have a string that contains a hexadecimal representation of a number and you store that value in the intVar. But at this time, it is a value, and not a representation anymore. There is no output possible of your intVar (if you look at it from your debugger, the debugger will show you a representation of the number, which you can change without affecting the value).
I would have guessed that you want to convert a string that contains a hexa representation to a string that contains a decimal representation but your code snippet contradicts that.
So, what are you trying to do exactly ?
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Hello,
Consider this situation, I need to iterate 'iLength' number of values for a business logic. 'iLength' is a value represented in hexa. In a while loop, to perform a boundary check I am using this 'iLength' value.
while(++iPosition<= iLength)
My assumption is that this boudary check requires the value to be an integer is not so? If not clarify?
Assuming my assumption is true how do I represent a hexa value in decimal?
eg. if 'iLength' = 2b, I need 'iLength' to contain 43? How ?
Kindly clarify. Thanks for your quick response.
Regards,
lgatcodeproject
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lgatcodeproject wrote: eg. if 'iLength' = 2b, I need 'iLength' to contain 43? How ?
You have to do nothing, supposing iLength is declared as an integer variable.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
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If iLength is an integer (which I suppose), it IS a number. iLenght contains your value and it has nothing to do with "2b" or "43" because these are only representations of your number. You have to make the difference between the value itself (which not hexa, decimal or whatever, it is just a value) and how you want to represent it (which is only used if you want to print the value in a string).
Do you understand the difference ?
lgatcodeproject wrote: 'iLength' is a value represented in hexa
That doesn't make sense: iLenght is an integer and that's it. An integer is never represented. If you look at it from your debugger, that's because your debugger is configured to display a representation of it in hexa, but you can change the representation to decimal without affecting the value at all.
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Hi,
I understand the difference between a value and its representation. I need clarification on this, "a value means the same in what ever way it is represented am I right? then what is the real need to represent an value in different ways?"
Regards,
lgatcodeproject
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Because a representation maybe convenient in a particular context. For instance, hexadecimal one uses exactly two digits to represent all of the values of byte (to display byte values with decimal representation you may need three digits, but a large part of decimal three-digits-numbers cannot fit in a byte ); binary representation maybe opportune whenever you need to display a bit mask, and so on..
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
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If intVar is an int, then it's not decimal, binary, hexadecimal.
You can display intVar in your debugger in hex if you show
intVar,x
or decimal using
intVar
Try right clicking on the watch window and de-select the "show hex" option. Beyond that, I don't understand your problem.
Iain.
Iain Clarke appearing in spite of being begged not to by CPallini.
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you have to pass the address of the int variable to sscanf , for instance:
int i;
sscanf("1F","%X", &i);
sets i=31; .
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
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Dear all
I have one visual C++ 6.00 MFC dll project.
It contains both C and C++ files.
Every time I open the project and make it clean and ther rebuild all it,
following errors occures.
Linking...
mfcs42d.lib(dllmodul.obj) : error LNK2005: _DllMain@12 already defined in MSVCRTD.lib(dllmain.obj)
mfcs42d.lib(dllmodul.obj) : warning LNK4006: _DllMain@12 already defined in MSVCRTD.lib(dllmain.obj); second definition ignored
Creating library Debug/ecpdll.lib and object Debug/ecpdll.exp
Debug/ecpdll.dll : fatal error LNK1169: one or more multiply defined symbols found
Error executing link.exe.
Creating browse info file...
ecpdll.dll - 2 error(s), 1 warning(s)
When I delete the C file and the header file of it and then re add them to the project this error removes but this style is not good.
May u please help me.
Regards
Tappe
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Solution ->[^]
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
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hi try this
in project settings, select using MFC dlls in one of the combo boxes.
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Hi all,
I would like to know whether it is possible to create a vector with more than one level range. For example, lets say you have two sets of integers and you want to populate a vector , how would one do it?
The code piece below shows four ints with value 100, but what if one wanted two sets of four ints with a value of 100.
vector<int> second (4,100);
Level 0 Level 1
0 0
1 1
2 2
3 4
...
Many thanks in advance
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's
Programm3r
My Blog: ^_^
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what about vector of vector ?
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow Never mind - my own stupidity is the source of every "problem" - Mixture
cheers,
Alok Gupta
VC Forum Q&A :- I/ IV
Support CRY- Child Relief and You/codeProject$$>
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Thank you for the reply ... May I ask for a very short example else thanks for the help.
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's
Programm3r
My Blog: ^_^
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Would this be an example of such occurance, if so does the following structure perform the same function, if not how can I change the vector to perform the same function:
struct C
{
string coid;
string actualCoid;
}COID[100];
#include <iostream>
#include <vector>
using namespace std;
main()
{
vector< vector<int> > vI2Matrix(3, vector<int>(2,0));
vI2Matrix[0][0] = 0;
vI2Matrix[0][1] = 1;
vI2Matrix[1][0] = 10;
vI2Matrix[1][1] = 11;
vI2Matrix[2][0] = 20;
vI2Matrix[2][1] = 21;
cout << "Loop by index:" << endl;
int ii, jj;
for(ii=0; ii < 3; ii++)
{
for(jj=0; jj < 2; jj++)
{
cout << vI2Matrix[ii][jj] << endl;
}
}
}
Thanks in advance
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's
Programm3r
My Blog: ^_^
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