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I don't quite get your requirement. Can you explain?
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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I am sorry for being ambiguous.
I want to show 10 numbers to user and corresponsing to each number, I need a string from user.
For this, I am using a list control inside a dialog box and in first column, 1-10 numbers will be placed in 10 rows and in second column, user will enter text corresponding to each number.
Then I need to store all this data.
My problems are - If I use list control, then the sub items(second column) does not appear to editable.
Second, I am wondering whether xml is the right way to store this data or do I have other options?
I expect the number of items to grow.
Thanks for any inputs.
the fruits of your success will be in direct ratio to the honesty and sincerity of your own efforts in keeping your own records, doing your own thinking and, reaching your own conclusions.
..surviving in autumn..in love with spring..
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For in-place editing, Steen Krogsgaard has given you the idea.
theCPkid wrote: Second, I am wondering whether xml is the right way to store this data or do I have other options?
Well, that totally depends on your choice. You can put it in the registry as well. If it is in an XML or inf file, it becomes easily portable (if such a thing is desired).
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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Instead of using a list control, use a list-view control with LVS_EDITLABELS style set. See MSDN List-view control or LVS_EDITLABELS for details.
Cheers
Steen.
"Are you gonna check your makeup when you're done whining?" John Simmons, 05/31/2006
"Of course, the next day it automatically updates, and your quick'n'dirty patches cause the new binaries to segfault all over your linoleum. If only you'd had the source..." Shog, 10/18/2006
"One day I realized that sadness is just another word for not enough coffee" Wally, 10/18/2006
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I want to write C++ executable (console application), which will prompt the user to enter user name and password. The problem I am facing is when the user enter his/her password it is visible, so how to hide the password entry. Which means user can enter the password but it should not be displayed in the console.
Can any once help to achieve this? (That is hiding the password entry when it prompts for pw)
Thanks,
Nandu
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In a console application, how are you obtaining the password from user? Use getch() to get the character and then do not display that character on screen or display '*' instead.
I did not exactly get your question. 
the fruits of your success will be in direct ratio to the honesty and sincerity of your own efforts in keeping your own records, doing your own thinking and, reaching your own conclusions.
..surviving in autumn..in love with spring..
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Can you show us your code?
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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Below is the code
#include <iostream>
#include <fstream>
#include <string>
#include <conio.h>
using namespace std;
string XOR(string value,string key)
{
string retval(value);
short unsigned int klen=key.length();
short unsigned int vlen=value.length();
short unsigned int k=0;
short unsigned int v=0;
for(v;v<vlen;v++)
{
retval[v]=value[v]^key[k];
k=(++k<klen?k );
}
return retval;
}
/******************************************************************************/
/* Here's a Test Program */
/******************************************************************************/
int main()
{
//string value("just for fun");
string key = "TERADATA";
string username;
string password;
string cnfpassword;
ofstream myfile;
cout<<"Enter user name::";
cin>>username;
cout<<"Enter Password\n";
cout<<"NOTE:\n"<<"1) Password can be alphanumeric or numeric or alphabets\n"
<<"2) Blank spaces not allowed\n"<<"::";
cin>>password;
cout<<"Confirm Password::";
cin>>cnfpassword;
if (password.compare(cnfpassword) != 0)
{
cout<<"Sorry Password dose not match....try again"<<"\n";
return 1;
}
else
{
password=XOR(password,key);
}
cout<<"Encrypted Password ::"<<"\n";
cout<<password<<"\n\n";
myfile.open("Test_SSOpw.txt", ios::out);
if( !myfile )
cout<<"Error opening file";
else
{
myfile.write("#USERNAME#", 10);
myfile.write(username.c_str(), username.length());
myfile <<'\n';
myfile <<"#PASSWORD#"<<password;
myfile.close();
cout<<"Functional SSO password encryption success!!"<<'\n';
}
password=XOR(password,"TERADATA");
cout<<"Decrypted Password ::"<<password<<"\n";
getch();
return 0;
}
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Below is the code
#include <iostream>
#include <fstream>
#include <string>
#include <conio.h>
using namespace std;
string XOR(string value,string key)
{
string retval(value);
short unsigned int klen=key.length();
short unsigned int vlen=value.length();
short unsigned int k=0;
short unsigned int v=0;
for(v;v<vlen;v++)
{
retval[v]=value[v]^key[k];
k=(++k<klen?k);
}
return retval;
}
/******************************************************************************/
/* Here's a Test Program */
/******************************************************************************/
int main()
{
//string value("just for fun");
string key = "TERADATA";
string username;
string password;
string cnfpassword;
ofstream myfile;
cout<<"Enter user name::";
cin>>username;
cout<<"Enter Password\n";
cout<<"NOTE:\n"<<"1) Password can be alphanumeric or numeric or alphabets\n"
<<"2) Blank spaces not allowed\n"<<"::";
cin>>password;
cout<<"Confirm Password::";
cin>>cnfpassword;
if (password.compare(cnfpassword) != 0)
{
cout<<"Sorry Password dose not match....try again"<<"\n";
return 1;
}
else
{
password=XOR(password,key);
}
cout<<"Encrypted Password ::"<<"\n";
cout<<password<<"\n\n";
myfile.open("Test_SSOpw.txt", ios::out);
if( !myfile )
cout<<"Error opening file";
else
{
myfile.write("#USERNAME#", 10);
myfile.write(username.c_str(), username.length());
myfile <<'\n';
myfile <<"#PASSWORD#"<<password;
myfile.close();
cout<<"Functional SSO password encryption success!!"<<'\n';
}
password=XOR(password,"TERADATA");
cout<<"Decrypted Password ::"<<password<<"\n";
getch();
return 0;
}
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Nandu_77b wrote: cin>>cnfpassword;
Use getc() in a while loop to get the password characters and display an asterisk with cout for each character.
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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I have tried with the below code, but I am getting some junk value in password.
int i = 0;
char ch;
char password[20];
do
{
ch = getch();
cerr<<"*";
password[i++] = ch;
}
while(ch != '\r');
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This works for me:
std::string str;
char c;
cout<<"Please enter password:";
while(true)
{
c = _getch();
if(c == 32 || c == 13 || c == 27)
break;
else
{
str += c;
std::cout<<"*";
}
}
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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Hi,
I am writing some character bytes in to File using
fprintf(fp,"%c",data);
if data is 26 then while reading it is read as -1,
if other than 26 it is able to read correctly.
What will be the problem?
Any idea?
Regards,
Sunil Kumar
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how is data populated ?
also, how do you read the file back ?
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Hi,
I read using
int c=getc(fp);
until I read the complete bytes.
Regards,
Sunil Kumar
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sunilkumar.d wrote: Hi,
I read using
int c=getc(fp);
until I read the complete bytes.
thanks. and then i ask back my second question, which was :
how do you read back the file ?
just a guess. wouldn't it work better if you write (with fprintf() using the %d parameter rather than %c (as you're handling an int and not a char) ?
also, doesn't fscanf() work better than getc() ?
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Well, good luck Tox. 
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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I did nt try that way.
Actually the code is already written.Now I am maintaining it.
So I did nt change it.
Regards,
Sunil Kumar
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please make tries and use your debugger...if you don't make tries, how can you tell what's wrong !
man, if you're on a maintenance team, it your every day job. you should already be able to have such reflex
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Could this be related with ASCII value? 26 corresponds to substitute, so as toxcct says you would be having some problem with the way you read from the file.
Somethings seem HARD to do, until we know how to do them.
 _AnShUmAn_
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Hi , thanks for the answer.
I am reading like
int c;
for(i=0;i<10;i++)
{
c=getc(fp)
char [i]=c;
}
If the charater is 26 then c will contain -1.
Regards,
Sunil Kumar
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sunilkumar.d wrote: int c;
for(i=0;i<10;i++)
{
c=getc(fp)
char [i]=c;
}
Are you sure this is the code? It won't even compile.
Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
Codeproject.com: Visual C++ MVP
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Sorry sir,
I just typed in correctly.
Regards,
Sunil Kumar
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Hi,
How is the File Opened? If you are looking for bytes it should be "rb", "r+b" etc, the 'b' must be there. What was ascii 26 again? I think it was 'Substitute' Anyway, fgets and fputs may try to put an interpretation to ascii 26 when encountered in text mode. In binary mode is should pass straight trough.
Hope this is helpfull,
Regards,
Bram van Kampen
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