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Hello,
There is no other way apart from this to draw rectangles. However, the only problem was the
calculation part which was working only when you draw from lefttop to right bottom. However,
while doing vice versa, the height and width was getting negative values.
Try this piece of code in MouseUp event()
private void Form1_MouseUp(object sender, MouseEventArgs mouseEv)
{
textBox2.Text = Convert.ToString(mouseEv.Location);
Graphics graphics = this.CreateGraphics();
Rectangle rectangle;
if (mouseEv.Y > mouseDownY)
{
height = mouseEv.Y - mouseDownY;
}
else
height = mouseDownY - mouseEv.Y;
if (mouseEv.X < mouseDownX)
{
width = mouseDownX - mouseEv.X;
rectangle = new Rectangle(mouseEv.X, mouseEv.Y, width, height);
}
else
{
width = mouseEv.X - mouseDownX;
rectangle = new Rectangle(mouseDownX, mouseDownY, width, height);
}
graphics.DrawRectangle(Pens.Red, rectangle);
}
I believe this should resolve your issue.
Regards,
Allen
Allen Smith
ComponentOne LLC
www.componentone.com
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Almost there.
You must draw a positive distance starting from the smallest value, both for X and width, and for Y and height.
It may be different though in both dimensions, your code assumes it is the same for both.
You really should introduce new variables for Xmin and Ymin.
I typically like to add a method DrawRectangle that hides these limitations,
so it accepts all value combinations for X1,Y1 and X2,Y2
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Hey
I have this project now:
http://peecee.dk/upload/download/123403
It allmost works, the preview thing just doesnt work properly
Could you guys take a look at it?
Because I cant seem to find a soloution
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Hi All,
I am developing simple chat application in c#.I want display animated gif in richtextbox with readonly.When Richtextbox is Readonly it's not Displaying Image.If anyone know which control is using yahoo for diaplaying message in Yahoo Messanger.Thanks In Advance.
SHINOJ K
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This is the piece of code
Random rnd = new Random();
Random rnd2 = new Random();
for (int i = 0; i < 5; i++)
{
myIntegerCollection.Add(i);
myEmployeeCollection.Add(new Employee(100 + i,rnd.Next(50),("name"+ rnd2.Next(50))));
}
both the Random instances rnd and rnd2 are generating the same numbers over and over again, and I dont understand why.
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Use the Next method on your Random instances.
Dave
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Thats what I have done Dave.
rnd.Next(50)
rnd2.Next(50)
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They are both created at the same time, so the seed is the same. Create them with different seeds.
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Even this does not help
Random rnd = new Random();
Random rnd2 = new Random();
int newNo = 0;
for (int i = 0; i < 5; i++)
{
newNo = rnd2.Next(50);
myIntegerCollection.Add(i);
myEmployeeCollection.Add(new Employee(100 + i,rnd.Next(50),("name" + newNo)));
}
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You clearly did not listen to what I said. Now go through the docs and look for seed, and the constructor for the Random class.
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Hey guys why does everyone act so pricy and rude. If I have to go through all that then why the hell do we have this forum. Now tell me how do I plant this seed of yours.
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This[^] 2 page article explains why you're getting the same forboth and the solution is on page 2.
humayunlalzad wrote: why does everyone act so pricy and rude. If I have to go through all that then why the hell do we have this forum.
Because this forum isn't meant to be a substitute for searching MSDN or exploring the internet. It's here to help when those have failed, otherwise it'd be a load of pointless and unstructured repetition.
Dave
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You are wrong Dave. If I have to search, I can even find God. Forums are for sharing your knowledge, so that the other person, does not go through time consuming searches.
Instead of going through all these advices you should do what erfi did, be a lil more specific about the answer.
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humayunlalzad wrote: You are wrong Dave.
Actually, Dave is right.
Forums are for helping out when you when the documentation isn't sufficient or you don't know where to look in the documentation. It is not a replacement for using a search engine or reading documentation however much you might want it to be.
You got an answer which gave you enough information to read the documentation. When you read the documentation you will get a lot of other information along with the answer which will give you greater understanding of that area.
Now, take some time to calm down and understand what you are being told and think about why you are being told that. People here want to help. But, we are only prepared to help those who help themselves. It took me a while to understand that, and once I did it started to open up so many doors to me.
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Thanx Colin. I was wrong. And I have understood that.
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leppie I am sorry for being rude. I should have followed your clue. But I guess I was feeling lazy.
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No problem
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I guess I should read the whole thread before jumping and stirring things up again after they've been sorted for 4 hours.
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either do what Leppie suggests above or just use one Random and call rnd.Next(50) in place of rnd2.Next(50) so you only need the one seed.
Dave
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you can change the seeds
just use the overloaded random construction function
like this :
Random rand1 = new Random(1);
Random rand2 = new Random(2);
Console.WriteLine(rand1.Next(50));
Console.WriteLine(rand2.Next(50));
output is :
12
38
sometimes 0 can be 1
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I think you need to adjust your attitude towards how forums are used. No forum is a "I'm too lazy, you should give me the answer" area. If you can't find something through searching and doing the hardwork for yourself, then you can come to a forum and ask others for their help. If you are using the Random function, the assumption is that you at least read how to use it in the first place instead of copying the functionality from another source. If you're given a clue as to what to look for, you should go and look that up and read up on it.
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Thanx hammer, that sounds reasonable. I will do that next time.
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You need to give the random number generator a different seed value each time you run the code.
"The clue train passed his station without stopping." - John Simmons / outlaw programmer
"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon
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