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Hi sakthii,
In addition to what the other members said you can remove the call to memset completely. You can do this to initialize your array to zero:
PHB_ENTRY myEntry[50] = {0};
Best Wishes,
-David Delaune
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sakthii wrote: Problem no: #3: I see 13 is getting updated in myEntry[1].resevered1 variable...
Even though you are not assigning anything to it?
sakthii wrote: can some one help me out on this strange problem?!
How are you verifying the values?
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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Thanks to all, memset problem is solved, i could see the structure is set with 0.
sakthii wrote:
Problem no: #3: I see 13 is getting updated in myEntry[1].resevered1 variable...
Even though you are not assigning anything to it?
No. it happens when I am assigning the value to other parameter like myEntry[1].length= 4
How are you verifying the values?
verifying using step by step debugging, I am using Visual Studio 8.
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sakthii wrote: verifying using step by step debugging, I am using Visual Studio 8.
And how do you verify the values ? Are you looking at the variables directly (within the watch window for instance) or are you looking up at the raw memory because you know where your member are located in memory ?
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I am using watch window.
I created new project (windows console application) and added the file to it and same code is working!!!
I think some problem with the Windows Forms Aplication. problem with IDE ?!
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Problem#2 & 3 seems to be occur because of memory-overusage that leads memory corruption at some un-imagined places, I have observed this kind of behavior mostly with mobile technologies. I suggest you to use heap-allocation instead of stack-allocation or try to reduce the array size.
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Do anyone know how to convert a vector to a list in Visual C++?
I tried casting, it does not work for me.
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Are you talking about a std::vector and a std::list ?
Don't think there is a direct conversion, you will need to copy from one to the other.
This signature was proudly tested on animals.
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Yes : std::vector to std::list
What is the best method to copy the data? Can you give an example?
Thanks.
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It's not MFC, but something like:
vector<int> vec;
vector<int>::iterator it;
list<int> l;
for (it = vec.begin(); it != vec.end(); it++)
l.push_back(*it);
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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I forget to mention it's two different data types see code below:
std::list<rdlresource*> TempRes;
TempRes.clear;
std::vector<rdltemporaryresource*>::iterator it;
for (it = TempResList.begin(); it != TempResList.end(); it++)
TempRes.push_back(*it);
Thanks the help on this.
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Well I guess it did not compile fully earlier, I am still getting the compiler error message below when I tried to copied the data from a vector to a list.
ompiling...
FSSCHED.CPP
c:\program files\ilps\code\fstool\fssched.cpp(1165) : error C2664: 'push_back' : cannot convert parameter 1 from 'class RDLTemporaryResource *' to 'class RDLResource *const & '
Reason: cannot convert from 'class RDLTemporaryResource *' to 'class RDLResource *const '
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
Error executing cl.exe.
fstool.dll - 1 error(s), 0 warning(s)
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That's because your list is for RDLResource* objects while your iterator for that list is for RDLTemporaryResource* objects.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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Right. So I am having problems transferring the data from the vector to the list.
How do I work around doing that in my case? I tied casting, it compiled but the application crashes at runtime.
Thanks.
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Anderson Jogie wrote: How do I work around doing that in my case?
That's impossible to tell since I know nothing of either of those two classes. For example, how would you copy a vector of Automobile objects to a list of Animal objects?
Anderson Jogie wrote: I tied casting, it compiled but the application crashes at runtime.
That would not work unless the two classes had a "is a" relationship.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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DavidCrow wrote: That would not work unless the two classes had a "is a" relationship.
Reading that it occurred to me that a more casual (possibly less informed) reader might look at that, pause, and then have their head explode.
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I agree.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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I'm not an STL expert, but after a quick google (bing did not give valid answers in the first few pages), here are a couple of solutions (adapt to your particular situation)
std::copy (v.begin (), v.end (), std::back_inserter (l))
or
std::list<int> l(v.begin(), v.end());
or ...
This signature was proudly tested on animals.
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So you binged it, but it bonged out?
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Just so you know, std::vector and std::list have nothing to do with MFC. They are part of STL or Standard Template Library and are cross platform.
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Hello,
I am porting a Dialog based application that I used Lcc-Win32 to develop over to Visual C++.
How to I get the handle of my Dialog box?
Thanks in advance for your help.
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jonsey29847 wrote: How to I get the handle of my Dialog box?
For what purpose?
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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That question confuses me. What am I missing Dave? Just curious.
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led mike wrote: That question confuses me.
Mine or the OP's?
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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