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Owww nasty word procs hehe!
2+2=5 for very large amounts of 2
(always loved that one hehe!)
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I thought Kate was a well behaved plaintext editor? Meh, I've used Komodo Edit which can handle such odd things as Shift-JIS if I want it to...
----
Morgan Gangwere
Lead programmer, Unknown Software
"Pinky, are you thinking what im thinking?"
"I Dunno brain, how many licks DOES it take to get to the tootsie roll center of a tootsie pop?"
"You want me to calculate that? or should we take over the world?"
"ooh! OooooOOOooH! lets find out!"
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How Can I Make Array Of String Move V. Or H.?
Just Like The Sub-news In TV
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For a web application, you want that to happen on the client side, hence not driven by PHP, which is a server side language. Consider using JavaScript. Go to a web page that does it, and look at its source.
Luc Pattyn [Forum Guidelines] [My Articles]
The quality and detail of your question reflects on the effectiveness of the help you are likely to get.
Show formatted code inside PRE tags, and give clear symptoms when describing a problem.
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Some common js code
<script>
var marqueeWidth='950';
var marqueeHeight='18px';
var pauseMarquee=true;
var fontFamily = 'arial,sans-serif';
var marqueeSpeed=1;
var speedTwo=marqueeSpeed;
var textSpan, marquee;
var fontSize = parseInt(marqueeHeight) - 6;
function marquee(){
var content = document.getElementById('scroller').getAttribute('content');
if (document.getElementById){
var scrollit = '<div style="position:relative; margin:auto; width:'+marqueeWidth+'px;height:'+marqueeHeight+';overflow:hidden;color:#FFFFFF;"';
if (pauseMarquee) scrollit += ' onmouseover="speedTwo=0" onmouseout="speedTwo=marqueeSpeed"';
scrollit +='><div id="marquee" style="position:absolute;left:0px;top:0px;font-family:'+fontFamily+';font-size:'+fontSize+'px;white-space:nowrap;"><\/div><\/div>';
document.getElementById('scroller').innerHTML = scrollit;
marquee = document.getElementById("marquee");
marquee.style.left=(parseInt(marqueeWidth))+"px";
marquee.innerHTML='<span id="text">'+content+'<\/span>';
textSpan = document.getElementById("text").offsetWidth;
setInterval("scrollscroller()",17);
}
}
function scrollscroller(){
marquee.style.left = (parseInt(marquee.style.left)>(-10 - textSpan)) ?parseInt(marquee.style.left)-speedTwo+"px" : parseInt(marqueeWidth)+4+"px";
}
window.onload=marquee;
</script>
use with:
<div id="scroller" content="scrollling text"></div>
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Hey dudes. I have got a problem. I was working on a simple student_course registeration for a week and @ last I lost it by some virus called "dulla" .... i cant recover it. the day after twommorrow is the final day.I also had other projects to submit to my cusotmers. So please if any body can give me a code or a resource . I know it is too lazy to do like this . but this one is my last and best choice
Thank you.
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i am a under grad. student.
i have just started working on unix.
i want to know that what all projects can be made in unix
simple n feasible
please reply if anyone has any suggestions
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Well what do you mean?
You can make any project with UNIX/Linux just like you can with any other operating system
If everything was not true, would it be not true that everything is not true? So by saying everything is not true, you are automatically denying that everything is not true. Im so confused...
FreeDOS
- An open source modern
MS-DOS/PC-DOS replacement.
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I need help with how i can insert values from a checkbox and dropdown menu into mysql database and also display these values on a page using php.
here is what i have
<form action="view.php" method="post" enctype="multipart/form-data">
<table width="421" border="1" align="center" cellpadding="0" cellspacing="0">
<tr>
<td colspan="2"><div align="center"><strong>Student BioData</strong></div></td>
</tr>
<tr>
<td width="82">Name</td>
<td width="215"><input name="name" type="text" id="name" size="40" /></td>
</tr>
<tr>
<td>Class</td>
<td><select name="class" id="class">
<option selected="selected"></option>
<option value="class">jss1</option>
<option value="class">jss2</option>
<option value="class">jss3</option>
</select>
</td>
</tr>
<tr>
<td>Age</td>
<td><input type="text" name="age" id="age" /></td>
</tr>
<tr>
<td>ClassTeacher</td>
<td><input type="text" name="teacher" id="teacher" /></td>
</tr>
<tr>
<td>Checked Values</td>
<td>Tall
<input type="checkbox" name="checked[]" id="tall" />
Short
<input type="checkbox" name="checked[]" id="short" />
Fat
<input type="checkbox" name="checked[]" id="fat" />
Thin
<input type="checkbox" name="checked[]" id="thin" /></td>
</tr>
<tr>
<td> </td>
<td> </td>
</tr>
</table>
</form>
<p>
<table width="220" height="138" border="1" cellpadding="0" cellspacing="0">
<tr>
<td colspan="2" valign="top"> </td>
</tr>
</table>
<p>
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There are several tutorials available to help you with this. Here is one.[^]. More Tutorials.[^]
Broken down into sections; you should read this[^] and this[^] with regards to the POST variables. Then have a read of this[^] tutorial for inserting into a MySql database.
If at first you don't succeed, you're not Chuck Norris.
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hhtp://abc.com/12?ud=504132
..........<? echo $_GET['ud'] ?>........;
I want to do like this
$us=<? echo $_GET['ud'] ?>;
if($us==504132)
{
$us='Hi';
}else
{
$us='Bye';
}
$echo 'I want to say you:'<? echo $_GET['us'] ?>;
But it is not working what to do now ?
<code></code><pre></pre>
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udch wrote: $us=<? echo $_GET['ud'] ?>;
Why are you opening new PHP tags when you are already in some? <? $us = <? ... It's just not necessary.
Check if ud is set, otherwise it is 0 .
$us = isset($_GET['ud']) ? $_GET['ud'] : 0 ;
udch wrote: $echo 'I want to say you:'<? echo $_GET['us'] ?>;
$echo is just wrong; echo is not a variable but a language construct. Read the documentation[^] to learn more. And again with the opening of more PHP tags.
echo '$ud = ' . $us;
If at first you don't succeed, you're not Chuck Norris.
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I am getting value from an url Like http://abc.com/data.php?ud=567878 Now i am passing this value to an iframe of HTML exmple:-
<Body>
<Html>
<iframe frameborder=0 src="http://www.es.com/ifr?url=http://anc.com/wow.xml&amp;up_k1=<? echo $_GET['ud'] ?>&up_interval=60&amp;synd=open&amp;w=362&amp;h=350&amp;" width=284 height=120 scrolling="no"></iframe>
</Body>
</Html>
I have to write value like up_k1=567878 and it can not take value from any variable.
My problem is and i want to do is checking value like
if($ud==567878)
{
$ud='love all humans';
}
and then write it in iframe like
up_k1=love all humans
Now tell me brother can i do this ?
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Please engage your brain.
<? echo $ud ?> instead of <? echo $_GET['ud'] ?>
If at first you don't succeed, you're not Chuck Norris.
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Thank you very much for all your help code is working good now.Thanks again my brother.
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I'm just starting out with PHP development and would like to know what the best IDE is for windows is. I'm currently used to working in visual studio.
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Personally I use Notepad++[^] although I have used PHPEclipse[^] on occasion. I've heard good things about Aptana[^]. If you want to spend money then you can use Dreamweaver, but it's not the best environment.
If at first you don't succeed, you're not Chuck Norris.
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Thanks, I'll try Notepad++ I also have Dreamweaver and will try that too.
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Sounds promising I’ll check it out.
Thanks
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Check this code. Should it work in php?
$handle = opendir($SourceURL);
if ( !$handle )
{
closedir($handle);
return FALSE;
}
Thanks,
Parth
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This suggestion sounds silly but Im posting it anyway. Dont you want an If/Else control instead of just an If. And also can you be more specific on whats going wrong?
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This was in the PHP documentation[^].
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
...
closedir($dh);
}
}
If at first you don't succeed, you're not Chuck Norris.
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I didnt want to post this because I know its gotta be something trivial but Ive been troubleshooting this for well over 2 hours and have gotten nowhere.
<br />
$imagename = "sig.jpeg";<br />
$im = @imagecreatefromjpeg($imgname);<br />
<br />
if(!$im)<br />
{<br />
header('Content-type: image/jpeg');<br />
imagejpeg($im);<br />
}
It prints out "Content-type: image/jpeg" so I know that $im didnt fail (if statement tests for this)
But at line "imagejpeg($im);" I get the following error:
Warning imagejpeg(): supplied argument is not a valid Image resource
Does anyone have any idea why this is happening?
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