|
Didn't quite answer my question, but thanks anyways.
|
|
|
|
|
Object.Equals tests for Equality i.e. the two objects have the same values. Take a look at the example code on the MSDN Page for a demo.
Object.ReferenceEquals tests if they are in fact the same object i.e. it is the same pointer.
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
|
|
|
|
|
I figured it out, I stepped through the code and learned that the static Object.Equals(object a, object b) called in the operator overload actually makes a call to the virtual instance-level Equals(object obj) , so the static ReferenceEquals has to be used to test for instance equality. Though by default the static Object.Equals(object a, object b) will do the same thing as the static ReferenceEquals , unless you override the instance-level Equals method, because the default instance-level Equals method tests for instance equality.
modified on Thursday, October 29, 2009 2:48 PM
|
|
|
|
|
hi every one
how can record video from desktop?
Thanks a lot
|
|
|
|
|
behzadcp wrote: how can record video from desktop?
Wow, you have a Surface?
Seriously, you are likely to get a quicker answer if you google/bing/yahoo for c# video capture.
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
|
|
|
|
|
|
Printscreen is no video µ
Just an image
|
|
|
|
|
_Madmatt wrote: Printscreen is no video
Really? I had no idea! Thanks for the HUGE tip!
Maybe, just maybe I was being sarcastic as the OP left no information allowing others to help him, how he wanted to capture a video, using his own software or interfacing with third party software, what format, anything of the sort! Way to go!
|
|
|
|
|
EliottA wrote: Maybe, just maybe I was being sarcastic as the OP left no information allowing others to help him, how he wanted to capture a video, using his own software or interfacing with third party software, what format, anything of the sort! Way to go!
Yes indeed, the question is very clear...
EliottA wrote: Really? I had no idea!
He had no idea, maybe he's testing it right now? :p
|
|
|
|
|
Original Post wrote:
hi every one
how can record video from desktop?
Thanks a lot
Yes, extremely clear. I'm sure he is fast on his way to 'record video desktop'.
Stop being a tool.
|
|
|
|
|
EliottA wrote: Stop being a tool.
You mean "stop being a fool"?
Maybe he isn't in a hurry for an answer?
|
|
|
|
|
No, I meant steop being a tool.
|
|
|
|
|
Do I hear sarcasm? Lol, however the answer to the question willn't come. Maybe we could stop spamming all around here.
|
|
|
|
|
|
Tell me why? Why should I be a "tool"?
|
|
|
|
|
You're a tool because all you're doing is attempting to aggravate me while spamming the boards.
You're a tool.
|
|
|
|
|
I'm spamming the boards? Look around! It's you who said I' a tool, it's you who said "use printscreen" while that's totally wrong... You're such a ****** ***
|
|
|
|
|
Click Here[^] if you want to record using some software
Click Here[^] if you want to make such software using c#
|
|
|
|
|
hi there,
i have recently posted a Question asking how to send and recieve raw ethernet packets (bits on the wire) to the dialup (or any kind of modem) Modem's Connection, i have searched a lot and found and downloaded a Library Called SharpPcap (managed code for WinPcap) that can exactly do what i want, but only over Lan Connection and when i was trying to send packets over Dialup connection it fails,
someone answers me and tell me to send packets using SerialPort class, since Modems are connected to the computer using serial ports(like COM1 or COM2)
now suppose that my dial up modem is connected to the internet and is at port COM1, i'll wrote something like this:
<br />
SerialPort sp = new SerialPort("COM1",9600);<br />
sp.DtrEnable = true;<br />
sp.DataReceived += new SerialDataReceivedEventHandler(sp_DataReceived);<br />
sp.Open();
sp.Write(....My Packet);<br />
as i specify it throws me an exception, since this port is Opened now and is owned by a process, and as long as ports(such as COM1) can only be used by one and only one process, i can not do any thing...
is there another way or something else, i've searched for 2 or more weeks ...
|
|
|
|
|
AT COMMAND LIST[^]
Have you considered to send AT command to modum to dial specific number
|
|
|
|
|
i didn't ask what to send to modem, i have asked how to communicate when the port is opened by another process and i want to open() it and send AT Commands!??
|
|
|
|
|
I Doubt it is even possible. This is probably driver related
|
|
|
|
|
spiritboy wrote: Throws an exception Here
What exception is it throwing?
spiritboy wrote: since this port is Opened now
No it is not opened, it threw an exception.
spiritboy wrote: and is owned by a process
Do you mean to say the some other program has the serial port open already and you want to use both of your programs for the same serial port at the same time? I am not so sure that you can share a serial port.
Why is common sense not common?
Never argue with an idiot. They will drag you down to their level where they are an expert.
Sometimes it takes a lot of work to be lazy
Individuality is fine, as long as we do it together - F. Burns
Help humanity, join the CodeProject grid computing team here
|
|
|
|
|
the Exception is IOExceptio and telling : "The process cannot access the port 'COM1' because it is being used by another process."
the reason is that my modem is already connected to the internet (so is under used by another process), and i want to send packets to it.
when the modem is not connected i can successfully Open the port.
to make it more clear, i do not have another program that opened this port!
|
|
|
|
|
spiritboy wrote: my modem is already connected to the internet
spiritboy wrote: another program that opened this port
What you are saying contradicts yourself. If the port is opened by another process then by definition something else opened the port. You cannot open an already opened port. If as you say your program has the port open, why don't you just start sending packets to it?
In other words, you are trying to open a port you already have open when there is no need to open it again.
Why is common sense not common?
Never argue with an idiot. They will drag you down to their level where they are an expert.
Sometimes it takes a lot of work to be lazy
Individuality is fine, as long as we do it together - F. Burns
Help humanity, join the CodeProject grid computing team here
|
|
|
|