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Why not just provide the link to original content instead of copying and pasting it here?
50-50-90 rule: Anytime I have a 50-50 chance of getting something right, there's a 90% probability I'll get it wrong...!!
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its in my computer buddy in my txt file if you want thn i'll send it to you........and i am using it in my app....
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bhavnvyas wrote: if you want thn i'll send it to you
No thanks.
Exactly same thing is right here[^]. As soon as I read "So, the steps are" it struck that I have seen it somewhere. Hence the reply.
50-50-90 rule: Anytime I have a 50-50 chance of getting something right, there's a 90% probability I'll get it wrong...!!
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thank you very much.......
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Encrypt with any encryption, Encode in base64 string and then pass to the querystring using UrlEncode.
Remember base64 is essential.
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If you are just trying to make it not so obvious to the end user the ID that you are passing, then how about passing the data in a session variable ? It is not totally secure, but real easy to implement.
I don't believe in "over engineering" a solution. Keep things simple.
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Hi,you can try
string.ToBase64String() and string.FromBase64String
modified 27-May-14 5:11am.
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hii m using file upload control and am trying to upload image to my local folder(homeimg).
i have written code:
if (FileUpload1.HasFile)
{
FileUpload1.SaveAs("~\\homeimg\\" + FileUpload1.FileName);
Label1.Text = "File Uploaded: " + FileUpload1.FileName ;
}
else
{
Label1.Text = "No File Uploaded.";
}
it gives error and ask for root directory.as soon as give the path along with root directory the file gets uploaded.
Tell me how can i upload file to my local folder without using root directory.
thanks
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Use Server.MapPath ex.
FileUpload1.SaveAs(Server.MapPath("~\\homeimg\\" + FileUpload1.FileName))
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If you are using asp fileupload control then use this code..
tmpfile = Path.GetFileName(fbrwse.PostedFile.FileName);
iSubPath = Server.MapPath("..\\Documents\\");
if (!Directory.Exists(iSubPath))
{
Directory.CreateDirectory(iSubPath);
}
iSubPath1 = Server.MapPath("..\\Documents\\")+ "\\" + tmpfile;
fbrwse.PostedFile.SaveAs(iSubPath1);
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thnks both logic works...
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Hi,
Is there some way by which a web application design view should remain the same even if the resolution of the screen is changed?
Please reply
Thanks
Shankbond
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use control width in percentage..
<td style="width: 15%">
<asp:Label ID="lblunat="server" Width="100%" text="Document Status: "></asp:Label>
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treeview_SelectedNodeChanged event is not firing for the click of same node second time
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That's Correct. Because you are not changing the node selection, you are just clicking it again.
Try treeview_TreeNodeExpanded and treeview_TreeNodeCollapsed instead.
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Hi all,
i created web page in ASP.NET. and trying to run it in local host. am using IE 8.0 browser . am unable to see my Menuitems instead i found only blank area. can any one pls tell me....
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Did you checked with IE Compatible Mode or any other browser ? Are all CSS are placed properly ?
Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.
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Yes Abhijit i checked in IE 6.0 an Mozilla its working fine. But not in IE 8.0 pls tell me
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There is browser competibility button jus next to refresh button in ie 8 just click it and change your browser view..
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If you r using table in your's application. Then check the vacant cells delete them. Actually Firefox not focus over blank cells on ur page but IE do so.
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Refer this Link To know solution
http://forums.asp.net/t/1431373.aspx[^]
Sundeep Ganiga
When the only tool you have is a hammer, everything looks like a nail.
Come Forth Yourself to Click "Good Answer" for any expected solution.
Let us Support our C Project Programmers who provide solutions here.
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I am creating a button, a textbox and a label control, when a linkbutton is clicked. I have assigned an event handler to the button, but when the button is clicked nothing happens and even the previous controls created, disappear
<br />
protected void LinkButton2_Click(object sender, EventArgs e)<br />
{<br />
<br />
TableRow row = new TableRow();<br />
TableCell cell1 = new TableCell();<br />
txt = new TextBox();<br />
txt.Rows = 2;<br />
txt.Height = 40;<br />
txt.Width = 200;<br />
cell1.Controls.Add(txt);<br />
row.Controls.Add(cell1);<br />
<br />
btn = new Button();<br />
btn.Text = "Submit";<br />
btn.Click += new EventHandler(btn_Click);<br />
TableCell cell2 = new TableCell();<br />
cell2.Controls.Add(btn);<br />
row.Controls.Add(cell2);<br />
<br />
lbl1 = new Label();<br />
lbl1.Text = "Your Comments";<br />
TableCell cell3 = new TableCell();<br />
cell3.Controls.Add(lbl1);<br />
row.Controls.Add(cell3);<br />
Table1.Controls.Add(row);<br />
<br />
<br />
}<br />
void btn_Click(object sender, EventArgs e)<br />
{<br />
<br />
<br />
<br />
}<br />
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You need to create all dynamic control before page_Load, best to create them on Page_PreInit . Other wise the control will not able to maintain viewstate and postback data. As LoadPostBack and LoadViewState Fired before Page_Load.
Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.
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When recreating the controls in Page_PreInit, the line
<br />
Table1.Controls.Add(row);<br />
gives an error.
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