C / C++ / MFC

Re: How to view anonymous namespace variables' values in debugger?

4-Nov-02 12:19

Assuming that func can see the value, try setting a local variable to equal anon inside func, and then view it's value. I doubt you can see into the namespace directly, if 'anon' does not work. I would have expected it to, if the namespace is in scope where you are looking.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

Tim Finer4-Nov-02 12:27

Tim Finer

4-Nov-02 12:27

I've done that before, but it's a real drag to have to do everywhere I'd like to look at a variable's value. Since the debugger can examine _all_ of the symbols in a module, it ought to be able to "see" anonymous variables. WinDbg can see it, but only by wildcarding everything.

Re: How to view anonymous namespace variables' values in debugger?

Christian Graus4-Nov-02 12:35

Re: How to view anonymous namespace variables' values in debugger?

4-Nov-02 12:35

I agree - your example is obviously contrived to show the problem and the real code is probably more painful than that to do this to. I don't know what the solution is, and if you find one, I'd love to hear it.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

jbarton5-Nov-02 5:04

jbarton

5-Nov-02 5:04

Hi Tim,

While I have not used this with variables in anonymous namespaces, you should be able to setup a watch variable by using the address of the variable.

If you setup a breakpoint at a place that uses the variable, you can open the Disassembly window and find the address of the variable. I tried a sample program which did "cout << anon << endl;", and the disassembly showed:

mov eax,['anonymous namespace'::anon (00476dc0)]

The 00476dc0 is the address of the anon variable for my program. When you run this, it most likely will be a different address.

Once you have the address of the variable, you can setup a watch for it as follows:

* (int *) 0x476dc0

Substitute the address that you get for the 0x476dc0.

This tells the debugger to treat the address as a pointer to int, and then dereferences it. If you want, you can use:

(int *) 0x476dc0

You then get a plus sign which you need to expand to get to the value. For a single value, this isn't useful, but if you have an array, it can be very useful. For instance, if you had the following:

namespace
{
int array[5] = {5,4,3,2,1};
}

Once you find the address of the array in the debugger, you can display the array in a watch window as follows:

((int *) 0x476dc0),5

Again, replace address with the one found in the debugger. This will put a + next to the expression which will expand to 5 elements when clicked.

Best regards,
John

Re: How to view anonymous namespace variables' values in debugger?

Tim Finer5-Nov-02 7:08

Tim Finer

5-Nov-02 7:08

Thanks so much for your help! I had totally overlooked using the disassembly window! I was also able to cast a pointer to a structure too:

*(SaveParams*)(0x007b1280)

Again, thanks!

Best Regards,
Tim

Re: How to view anonymous namespace variables' values in debugger?

dshatilov15-Sep-16 0:29

dshatilov

15-Sep-16 0:29

In WinDBG:

>dt myapp!*anon

You will see somethin like that:

>myapp!?A0x423ba21e::anon

For search address for global variable, you should type:

x myapp!*anon*

You will see:

016255aa myapp!?A0x423ba21e::anon = [address]

Next, type:

>dt myapp!?A0x423ba21e::anon [address]

Note:
anon will optimized in release build

Re: How to view anonymous namespace variables' values in debugger?

Richard Deeming15-Sep-16 7:10

Richard Deeming

15-Sep-16 7:10

Well done - you're only 14 years late! D'Oh! | :doh:

How long did it take you to read 7712 pages of this forum?

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: How to view anonymous namespace variables' values in debugger?

dshatilov15-Sep-16 7:56

dshatilov

15-Sep-16 7:56

it's just help for other Smile | :)

Please Help!!

Autunmsky4-Nov-02 11:38

4-Nov-02 11:38

I'm working on this program and it has me stumped!!! Any help would be grateful. I'm trying to have the computer tell me if it is a triangle or not....if it is a triangle it has to tell me if it is an equil., isosoceles, or scalene. If it is not a triangle then I need to have my else statement. For some reason I just can't get it perfect. Thanks again!!

#include <iostream>
#include <cmath>
#include <string>
#include <cstdlib>

using namespace std;

const string EQUIL = "equilateral";
const string ISOS = "isosceles";
const string SCALE = "scalene";

void DisplayOpeningScreen();
void Print6BlankLines();

int main()

{
int side1;
int side2;
int side3;
int halfper;
int area;
string equil;
string isos;
string scal;

// Display an opening screen and explain the program to the user

DisplayOpeningScreen();

// Have the user input 3 values representing the sides of a triangle

cout << "\nEnter first side of triangle: ";
cin >> side1;
cout << "Enter second side of triangle: ";
cin >> side2;
cout << "Enter thrid side of triangle: ";
cin >> side3;

if ((side1 + side2) > side3 && (side2 + side3) > side1 && (side1 + side3) > side2)

{ cout << "\n\nThe three lengths can form a triangle.\n\n";

if ((side1 == side2) && (side2 == side3) && (side1 == side3))

equil = EQUIL;
cout << "This triangle is an " << equil << endl << endl;

else if ((side1 == side2) || (side2 == side3) || (side1 == side3))

isos = ISOS;
cout << "This triangle is an " << isos << endl << endl;

else;

scal = SCALE;
cout << "This triangle is an " << scal << endl << endl;
}

else
{
cout << "\n\nThe three lengths can not form a triangle.\n\n";
}

return 0;

}

//********************************************************************************************************************************************

void DisplayOpeningScreen()
// Purpose: Explains the program to the user

{

cout << "\n Welcome to the \"Triangle Program\"\n";

Print6BlankLines();

cout << " You will be asked to enter 3 integer values to represent the sides of a triangle.\n";
cout << " A message will be printed stating whether or not the 3 lengths can form a triangle.\n";
cout << " For valid triangles, a messge corresponding to the triangle's type will be printes.\n";
cout << " Finally, the area of the triangle using Hero's formula which is:\n\n";
cout << " area = squareroot (s)(s - a) (s - b) (s - c)\n";

Print6BlankLines();

// Pause and then clear the screen
system("pause");
system("cls");

}

//********************************************************************************************************************************************

void Print6BlankLines()
// Purpose: Prints 6 blank lines on the output screen

{

cout << "\n\n\n\n\n\n";

}

I know I haven't used the area and the halfper yet....I need to figure out this part first!!! Thanks everyone!!

Eek! | :eek:

Autumn

Christian Graus4-Nov-02 11:50

4-Nov-02 11:50

In order to make your include files visible, you need to check the 'display message as is' checkbox under the message as you type it.

Your problem is that your if/else statements are not scoped.

If I were to run this:

int i = 1;

if (i==0)
cout << "it's zero ";
cout << "I wish it was one ";

cout << "it's one";

the result will be

"I wish it was one it's one".

Python scopes things in blocks, C++ does it with the curly brackets. Unless you do this:

int i = 1;

if (i==0)
{
cout << "it's zero ";
cout << "I wish it was one ";
}

cout << "it's one";

the language will automatically only make the first line after the if statement conditional on the statement above it.

In this case, it's kind of pointless making the type a variable and then outputting the type directly, you should instead just print the value in the variable after deciding what sort of triangle it is.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

Gary Kirkham4-Nov-02 11:48

Gary Kirkham

4-Nov-02 11:48

Try this

if ((side1 == side2) && (side2 == side3) && (side1 == side3))
{
equil = EQUIL;
cout << "This triangle is an " << equil << endl << endl;
}
else if ((side1 == side2) || (side2 == side3) || (side1 == side3))
{
isos = ISOS;
cout << "This triangle is an " << isos << endl << endl;
}
else;
{
scal = SCALE;
cout << "This triangle is an " << scal << endl << endl;
}

Gary Kirkham

A working Program is one that has only unobserved bugs

Autunmsky4-Nov-02 11:55

4-Nov-02 11:55

Gary....thanks for your help.....this would work expect for my else statement at the end state that the triangle is false. I need to find a way to have the three different kinds of triangle be with if it is a triangle statement. I only want to prove if it is a triangle and what kind. If it's not a triangle then have my else statement stating it.

Sorry about this problem I'm having!!!

Autumn Smile | :)

Christian Graus4-Nov-02 12:22

4-Nov-02 12:22

You need two nested if statements, the first to establish if it's a triangle, the second to establish what sort. You should also output the type of triangle once, based on the variable you set.

You should also put using std::cout; and using std::cin; instead of using namespace std; - there is no point having namespaces if you're just going to negate them in one fell swoop.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

C^hris L^osinger4-Nov-02 12:23

C^hris L^osinger

4-Nov-02 12:23

Christian Graus wrote:
there is no point having namespaces if you're just going to negate them in one fell swoop.

maybe you should take up the "using" keyword with the C++ standard body. Wink | ;)

-c

“losinger is a colorizing text edit control”
-- googlism

Smaller Animals Software

Christian Graus4-Nov-02 12:33

4-Nov-02 12:33

Chris Losinger wrote:
maybe you should take up the "using" keyword with the C++ standard body.

According to Stroustrup, using an entire namespace is useful if it is within a limited scope, and has other application ( I forget the rest, and don't have a copy at work ), but should generally be avoided in favour of the syntax I suggested.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

C^hris L^osinger4-Nov-02 15:01

C^hris L^osinger

4-Nov-02 15:01

Christian Graus wrote:
According to Stroustrup

yeah yeah. the same guy who decided that "static" needed yet another meaning. Smile | :)

-c

“losinger is a colorizing text edit control”
-- googlism

Smaller Animals Software

Christian Graus4-Nov-02 15:17

4-Nov-02 15:17

Now you're just trying to wind me up......

I agree with him in principle that new keywords should be created sparingly, but a lot of mistakes get made in the pursuit of noble goals.

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

C^hris L^osinger4-Nov-02 17:29

C^hris L^osinger

4-Nov-02 17:29

Christian Graus wrote:
Now you're just trying to wind me up

never.

Christian Graus wrote:
but a lot of mistakes get made in the pursuit of noble goals

oh, i agree.

-c

“losinger is a colorizing text edit control”
-- googlism

Smaller Animals Software

Autunmsky4-Nov-02 12:57

4-Nov-02 12:57

Thank you for all of your help....I think I'm just having a hard time understanding how to write it out in C++. My code still isn't working.....boy this is just a pain in the tush. Thanks for all of your help.....I guess I'll just keep on sinking on this program. Keep smiling...and remember today is today....don't drag it to the next.

Frown | :(

Autumn

Christian Graus4-Nov-02 13:12

4-Nov-02 13:12

#include < iostream >
#include < string >

using std::cout;
using std::cin;
using std::endl;
using std::string;


const string EQUIL = "equilateral";
const string ISOS = "isosceles";
const string SCALE = "scalene";


void DisplayOpeningScreen();
void Print6BlankLines();

int main()

{
   int side1 = 0;
   int side2 = 0;
   int side3 = 0;
   int halfper = 0;
   int area = 0;
   string sType;


// Display an opening screen and explain the program to the user

DisplayOpeningScreen();


// Have the user input 3 values representing the sides of a triangle

cout << "\nEnter first side of triangle: ";
cin >> side1;
cout << "Enter second side of triangle: ";
cin >> side2;
cout << "Enter thrid side of triangle: ";
cin >> side3;


if ((side1 + side2) > side3 && (side2 + side3) > side1 && (side1 + side3) > side2)
{ 

  cout << "\n\nThe three lengths can form a triangle.\n\n";

  if ((side1 == side2) && (side2 == side3) && (side1 == side3))
       sType= EQUIL;
   else if ((side1 == side2) || (side2 == side3) || (side1 == side3))
       sType = ISOS;
   else;
       sType = SCALE;

   cout << "This triangle is an " << sType << " triangle.  \r\n\r\n";

}
else
{
   cout << "\n\nThe three lengths can not form a triangle.\n\n";
}

Assuming the maths is all right ( I don't know ), this should work fine. Note I do not call endl over and over ( it does a flush as well and can be expensive ), I initialise my numeric variables, and I use only the bits of std that I need.

return 0;

}

Christian

No offense, but I don't really want to encourage the creation of another VB developer. - Larry Antram 22 Oct 2002

Hey, at least Logo had, at it's inception, a mechanical turtle. VB has always lacked even that... - Shog9 04-09-2002

During last 10 years, with invention of VB and similar programming environments, every ill-educated moron became able to develop software. - Alex E. - 12-Sept-2002

Autunmsky4-Nov-02 14:29