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Hi,
would anyknow how to insert line breaks in a Crich edit control I don't know if it matters that its rich edit as opposed to edit
I only have vertical scrolling (up or down) ES_AUTOVSCROLL as the dialog style
and in the streamin call basck function I insert carriage return line feed at the end of the line "/r/n" and display the text following in a new line
thanks
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Do you also have ES_MULTILINE added?
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> If it doesn't matter, it's antimatter.<
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Yourwelcome.
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> If it doesn't matter, it's antimatter.<
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hello
I have installed boost 1.47.0 library on my system and I have a strange problem. If I try to serialize more then 25 objects, the serialization (save()) apparently works but the deserialization (load()) does not work anymore and it gives me the following error:
Unhandled exception at 0x7c812afb in Boost_tests.exe: Microsoft C++ exception: boost::archive::archive_exception at memory location 0x0012e5ec..
this error is raised when the last object (say the 26th object, if the number of objects is higher then 25) is being deserialized.
here is the code:
#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>
#include <boost/serialization/string.hpp>
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
using namespace std;
#define COUNT 26
class person;
vector<person> v;
class person
{
public:
string _name;
int _age;
person (string name="Liviu", int age=40):_name(name),_age(age){};
friend class boost::serialization::access;
template <typename Archive>
void serialize(Archive & ar, const unsigned int version)
{
ar & _name;
ar & _age;
}
};
void save()
{
ofstream file("archiv.cst");
boost::archive::binary_oarchive oa(file);
for (int i=1; i<=COUNT; i++)
{
oa<<person("John",i);
}
file.close();
};
void load()
{
ifstream file("archiv.cst");
boost::archive::binary_iarchive ia(file);
for (int i=1; i<=COUNT; i++)
{
person p;
ia>>p;
v.push_back(p);
}
file.close();
};
int main()
{
int i;
cin>>i;
while (i!=2)
{
if (i==0) save();
if (i==1) load();
cin>>i;
}
}
Can you help me please? Is something wrong with the library?
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Put your code inside a try{}catch{} block, and check which exception is being thrown.
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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the exception cannot be caught with a try - catch block
i already told you what the exception is
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How else can you catch it? I would suggest that you try the boost website to see what you need to do.
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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boost site sucks
they have no forum
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Did you look here[^]?
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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dliviu wrote: for (int i=1; i<=COUNT; i++)
{
person p;
ia>>p;
v.push_back(p);
// cout << p._name<<" " <<p._age<<endl;
}
When you do this... you're loading a stack variable into a dynamic heap object. The stack variable falls out of scope at the end of the execution of each for loop iteration. This isn't necessarily the problem causing the crash you're seeing, but it's definitely a problem.
Correction: vector::push_back() does make a copy and not just keep the pointer.
modified 2-May-12 11:32am.
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I don't see any problem here. p is an object which when it is inserted in v it is copied.
Anyway, this is not the problem. Boost library site sucks, and i have no solution to my strange problem.
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I had to look at the implementation of vector.. you're correct, it is copied. As far as the boost site sucking, well, that's something you have to live with when using third party libraries. You can always make your own serialization class and you won't have support issues (although it'll take you some time to do it).
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Hi,Why GetClipBoardOwner always returns 0 ,
When using GetClipBoardOwner with any other MS office for example the result will be the real Clipboard Owner , but when using it with acrobat reader i don't get any result .
Please can some one explains me this ?
many thanks
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See the documentation[^] for the valid responses from this function.
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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yes , i know but why just with Acrobat reader i don't get the GetClipBoardOwner ?
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What does GetLastError() tell you?
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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GetLastError() gives me 0 as result only with acrobat reader
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Sorry, no idea. If it does not give any useful information one can only guess that Acrobat is doing something different.
Binding 100,000 items to a list box can be just silly regardless of what pattern you are following. Jeremy Likness
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Yes that's why i opened this thread , this just with acrobat reader ! really strange
I hope someone will help me in this issue
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randydom wrote: ...but when using it with acrobat reader i don't get any result .
What exactly do you mean by this?
Just because the clipboard contains data does not also mean it is owned.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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Hi,
I have following C code and I am trying to measure time used by CPU.
timespec time1, time2, temp_time;
clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &time1);
long cpu_sum = 0;
for (i = 0; i < nelements; i++) {
cpu_sum += array[i];
}
clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &time2);
int borrow = 0;
long n = time2.tv_nsec - time1.tv_nsec;
if (n < 0) {
n += 1000000000L;
borrow = 1;
}
temp_time.tv_nsec = n;
temp_time.tv_sec = time2.tv_sec - time1.tv_sec - borrow;
printf(calculated sum: %d using CPU in %lld.%.9ld seconds \n",taskid, cpu_sum, (long long)temp_time.tv_sec, (long)temp_time.tv_nsec);
Just wondering how can i get time in milliseconds?
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It's pretty simple, really. One second is 1000 milliseconds. One millisecond is a million nanoseconds. So
millisecs = secs * 1000 + nanosecs / 1000000 What's so hard about that, given you already have the seconds and nanos?
Peter
Software rusts. Simon Stephenson, ca 1994.
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Thanks for reply. I am not sure whether my timing calculations mentioned above are correct?
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