|
I found the following as a source of help towards the solution:
public class ImageConverter : IValueConverter
{
public object Convert(object value, System.Type targetType, object parameter, System.Globalization.CultureInfo culture)
{
return new BitmapImage(new Uri((string)value, UriKind.RelativeOrAbsolute));
}
public object ConvertBack(object value, System.Type targetType, object parameter, System.Globalization.CultureInfo culture)
{
throw new System.NotImplementedException();
}
}
The path to the image is Images\File.bmp. I tried changing the formatting of the string to create a proper Uri, but the image STILL does not appear in the cell 
I found a solution which helped in better creating the path to be in the proper form of a Uri. What follows IS the solution:
public class ImageConverter : IValueConverter
{
public static BitmapImage CreateBMImage(string path)
{
BitmapImage bi = new BitmapImage();
try
{
bi.BeginInit();
bi.CacheOption = BitmapCacheOption.OnDemand;
Uri baseUri = new Uri(Application.ResourceAssembly.Location);
bi.UriSource = new Uri(baseUri, path);
bi.EndInit();
}
catch
{
return null;
}
return bi;
}
public static Image CreateImage(string path)
{
Image img = new Image();
img.Source = CreateBMImage(path);
return img;
}
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
try
{
return CreateBMImage((string)value);
}
catch
{
return new BitmapImage();
}
}
public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new System.NotImplementedException();
}
}
modified 23-Jul-12 10:34am.
|
|
|
|
|
The subject is somewhat of a misnomer, I have a category combobox that governs what defects are available, but that is it. The category information should not be saved. Easier to show than say:
Here is the relevant ViewModel:
public Category SelectedCategory
{
get { return _selectedCategory; }
set
{
if (value == null) return;
_selectedCategory = value;
OnPropertyChanged("SelectedCategory");
LoadDefects(_selectedCategory.id);
}
}
And the View:
<ComboBox
Grid.Row="2"
Grid.Column="1"
ItemsSource="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type UserControl}},Path=DataContext.AllCategories}"
DisplayMemberPath="name"
SelectedValuePath="id"
SelectedValue="{Binding SelectedItem.Defect.categoryId}"
SelectedItem="{Binding SelectedCategory}" />
<ComboBox
Grid.Row="3"
Grid.Column="1"
ItemsSource="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type UserControl}},Path=DataContext.AllDefects}"
DisplayMemberPath="name"
SelectedValuePath="id"
SelectedValue="{Binding SelectedItem.defectId}"/>
What is happening is that instead of just saving the SelectedItem (Observation class not shown) it is changing SelectedItem.Defect.CategoryId, which I don't want. I only want SelectedItem to be saved. Save routine is pretty simple:
ViewModel:
private void Save()
{
_con.SaveChanges();
}
Thoughts?
Cheers, --EA
|
|
|
|
|
I think you're confusing how the various ComboBox properties work:
DisplayMemberPath = Choose how to display the item, equivalent to making an ItemTemplate with a TextBlock that binds to said path.
SelectedValuePath = Use with the SelectedValue property when the items in the list aren't the same as the property you're binding to. For example, the items in your list may have a Name and an ID, so you set the SelectedValuePath to "ID" and bind SelectedValue to the "SelectedID" property of your model.
SelectedValue = See previous
SelectedItem = Use this when the items in your list are the actual items in your model. Do not combine it with SelectedValue or SelectedValuePath.
|
|
|
|
|
I am certainly confused about the various properties and what combination to use them in. I understand what you have written, though.
Ideally, I would just have SelectedCategory drive that combobox as I need the INotifyProperyChanged to work to populate the defect list. But I also need that combobox to have an initial value based on the currently selected item.
So how do I accomplish this? I need the selected value to be SelectedItem.Defect.CategoryId, but I also need to notify my viewmodel when particular property is changed. Which one needs to be removed and how do I still accomplish what I need?
|
|
|
|
|
Well, let's look at your particular case...
Since your model property seems to match the item in the list (Correct me if I'm wrong), you don't need to worry about the SelectedValue/Path properties. So take those out of your first combo, and that one should work just fine.
As for the second one, you want its ItemsSource to change based on the SelectedCategory, right? Whatever your LoadDefects function is modifying, that's what you want the second combo's ItemsSource to bind to.
You should also have a SelectedDefect property (Or something of the sort), that the second combobox should bind to in its SelectedItem property. The LoadDefects function can set the SelectedDefect to an initial guess when it updates the collection.
So in your case, I don't think you really need SelectedValue/Path at all.
|
|
|
|
|
You were right, did not need all of those properties. I see your point about the SelectedDefect, but it is ok to leave it blank when the user changes the category as I am relying on IDataErrorInfo to ensure that the user does not leave it blank.
This was the final product (For now):
public Observation SelectedItem
{
get { return _selectedItem; }
set
{
if (_selectedItem == value)
return;
_selectedItem = value;
_selectedCategory = _con.Categories.Where(c => c.id == value.Defect.categoryId).FirstOrDefault();
OnPropertyChanged("SelectedItem");
OnPropertyChanged("SelectedCategory");
LoadDefects(_selectedCategory.id);
}
}
public Category SelectedCategory
{
get { return _selectedCategory; }
set
{
if (value == null) return;
_selectedCategory = value;
OnPropertyChanged("SelectedCategory");
LoadDefects(_selectedCategory.id);
}
View:
public Observation SelectedItem
{
get { return _selectedItem; }
set
{
if (_selectedItem == value)
return;
_selectedItem = value;
_selectedCategory = _con.Categories.Where(c => c.id == value.Defect.categoryId).FirstOrDefault();
OnPropertyChanged("SelectedItem");
OnPropertyChanged("SelectedCategory");
LoadDefects(_selectedCategory.id);
}
}
public Category SelectedCategory
{
get { return _selectedCategory; }
set
{
if (value == null) return;
_selectedCategory = value;
OnPropertyChanged("SelectedCategory");
LoadDefects(_selectedCategory.id);
}
Maybe I should change the _selectedCategory to derive from my AllCategories observable collection instead. Either way, this works. Thank you.
Cheers, --EA
|
|
|
|
|
Glad to help 
|
|
|
|
|
I created the following button style. I want to set the image's opacity to 50% when the button is disabled. I have the Image.Style code in there, but how do I bind the IsEnabled to the button? See my comment in line.
<Style TargetType="{x:Type controls:FlatButton}"
x:Key="FlatButtonStyle">
<Setter Property="Height" Value="35"/>
<Setter Property="Width" Value="80"/>
<Setter Property="Margin" Value="2"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type controls:FlatButton}">
<Border x:Name="TheBorder"
Background="Transparent"
BorderBrush="#6F6F6F"
BorderThickness="0"
CornerRadius="2">
<StackPanel Orientation="Horizontal">
<Image Source="{TemplateBinding ImageSource}"
Grid.Row="0"
Grid.Column="0"
Width="16"
Height="16"
Margin="3,0,2,0"
HorizontalAlignment="Center"
VerticalAlignment="Center"
Stretch="Fill">
<Image.Style>
<Style TargetType="Image">
<Style.Triggers>
<!--How do I bind to the IsEnabled property on the button?-->
<Trigger Property="IsEnabled" Value="False">
<Setter Property="Opacity" Value="0.5" />
</Trigger>
</Style.Triggers>
</Style>
</Image.Style>
</Image>
<TextBlock Text="{TemplateBinding Caption}"
Grid.Row="0"
Grid.Column="1"
HorizontalAlignment="Center"
VerticalAlignment="Center"
Margin="10"
Foreground="#5D5D9D"
FontSize="12"
TextWrapping="WrapWithOverflow"/>
</StackPanel>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver"
Value="True">
<Setter TargetName="TheBorder"
Property="BorderThickness"
Value=".5">
</Setter>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
If it's not broken, fix it until it is
|
|
|
|
|
You just need to add another trigger in the Buttons triggers like so:-
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="TheBorder" Property="BorderThickness" Value=".5"></Setter>
</Trigger>
<Trigger Property="IsEnabled" Value="False">
<Setter TargetName="img" Property="Opacity" Value="50" />
</Trigger>
</ControlTemplate.Triggers>
That assumes that the image control in the style is given a name "img".
Hope this helps
When I was a coder, we worked on algorithms. Today, we memorize APIs for countless libraries — those libraries have the algorithms - Eric Allman
|
|
|
|
|
hello all.
I need a tip for good coding. I'm in my first stemps in WPF and i have a srollviewer with button inside that work nice. Now i need to provide another collection of button or another scrollviewer. i mean, the rest of the project dont change, only the scrollviewer.
what is the best way for that?
i hope i explained the issue.
Thanks.
|
|
|
|
|
I am afraid your question is not very clear. Could you try and expand it to make it clearer on what you would like to do.
When I was a coder, we worked on algorithms. Today, we memorize APIs for countless libraries — those libraries have the algorithms - Eric Allman
|
|
|
|
|
sorry. i will try again.
i have a finished project when i have a scrollviewer with a collection of button inside.
now i want to create the option to open another collection of button in the same project, replacing the old one if the option was select.
in the .cs side i think i can do easly, but maybe, there is a xaml good coding option.
|
|
|
|
|
Create 2 button collections/containers, bind the visibility property to the option control so only 1 is visible based on the user selection.
Never underestimate the power of human stupidity
RAH
|
|
|
|
|
I'm totally agree with Mycroft Holmes. Don't forget to create a Converter for Visibility Enumeration.
Regards.
Christian Amado
MCITP | MCTS | MOS | MTA
DCE 0★ 1★ 2★ 3★ 4★ 5★
Bronze level MVA
Olimpia ☆ ★★★
|
|
|
|
|
Why? If the property you use to control the visibility is a boolean there is a built in BooleanToVisibilityConverter.
|
|
|
|
|
Pete O'Hanlon wrote: built in BooleanToVisibilityConverter.
What, where, I have one I use in my utils but I didn't know there was a built in one (Silverlight). I also have various NOT converters
Never underestimate the power of human stupidity
RAH
|
|
|
|
|
I'm not sure about Silverlight (I mainly stick with WPF), but in WPF 4 you can find details of it here[^]. Most people who worked with pre WPF4 have their own implementation of this control - MS was informed that there should be a default version.
|
|
|
|
|
Hi there. In Silverlight you must apply a converter to Visibility enumeration. Remember that Visibility property is an enumeration not a Boolean =)
Christian Amado
MCITP | MCTS | MOS | MTA
DCE 0★ 1★ 2★ 3★ 4★ 5★
Bronze level MVA
Olimpia ☆ ★★★
|
|
|
|
|
Go back to the start of the thread. The OP stated he was using WPF.
|
|
|
|
|
Ups. Sorry for that.
Regards
Christian Amado
MCITP | MCTS | MOS | MTA
DCE 0★ 1★ 2★ 3★ 4★ 5★
Bronze level MVA
Olimpia ☆ ★★★
|
|
|
|
|
No problem. It's an easy mistake to make. 
|
|
|
|
|
Hi,
How can i open secondpage in silverlight on click event of button.
Thanks & Regards
Form :-
Vikash Yadav
Mob : 9210907172
|
|
|
|
|
Hi!
Imports System.Windows.Browser
HtmlPage.Window.Navigate(New Uri("http://zzz-server/zzz/Employees.aspx"), "_blank", "")
|
|
|
|
|
Do some research into navigation (assuming you do not just want an HTML page) here are the results of a search [^]in this forum, plenty of rich pickings in there.
Never underestimate the power of human stupidity
RAH
|
|
|
|
|
You can use Microsoft Prism[^] where your main screen is divided into regions.
Views (xamls) can then be removed and added to these regions.
Removing and adding views gives an effect of navigating across the application.
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
