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I need to deploy my web site to somewhere else so must know the path of phibro(my website folder name) folder. if i do hard code then it will create problem.. so please let me know if any other way to do it..
Thanks
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I am not familiar with java web sites, but I would assume that there is some property in Tomcat that will give you the correct location.
Use the best guess
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I want simple example code in web service then related websites for studies.
By
R.Ganesh Babu
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If you type that into a google search, you will find all kinds of example code and references.
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Ok, But I want, if you know best websites, you send to me.
Thanks & Regards,
R.Ganesh Babu
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What have you tried and where are you stuck? "in java" is not much of a description of a problem....
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I used JPanel leftPanel = new JPanel(new GridBagLayout); to contain "JScrollPane, JRadioButton, JCheckBox" (Like this image).
When I click on "Open..." button to add more picture, the JScrollPane will use "m_arrListImageFilePaths" to auto update its items. Controls in "JLeftPane" is still right their position. But when I click on application's "Maximum" button - the controls is repainted, "Normal" button is lay down "JScrollPane" (Like this video). Please help me solve above problem.
By the way, I attached my project which is helpful in your solving.
Thanks all !!!!!
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How to create last 10 recently opened files list using java in netbeans?
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Try some of these links[^]. Basically, it looks like you have to write the code yourself.
Use the best guess
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i want my program run in swing gui and yield can displayed in jtable.
Everybody,plese help me.
import java.io.*;
public class wile {
public static void main(String[]args){
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String cthdata=("Contoh Data");
String nomber=null;
try{
System.out.print("masukan jumlah:");
nomber=br.readLine();
}
catch(IOException ioe){
System.out.println("gagal");
}
int intnumber;
intnumber=Integer.parseInt(nomber);
System.out.println("No\tIsi");
int no=1;
while(no<=intnumber){
System.out.println(no+"\t"+cthdata);
no=no+1;
}
}
}
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You should study this tutorial[^] about swing and its controls.
Use the best guess
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I'm working with Oracle database. I use PHP for my web service and Android as the client which will send blob data to Oracle DB. I use this code
Bitmap imageUpload = BitmapFactory.decodeFile(picturePath);
ByteArrayOutputStream baos = new ByteArrayOutputStream();
imageUpload.compress(Bitmap.CompressFormat.JPEG, 60, baos);
byte[] image_data = baos.toByteArray();
String converted_image = Base64.encodeBytes(image_data);
to decode and send it as base64 encoding, then send it to the web service with this code
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("TITLE", title));
nameValuePairs.add(new BasicNameValuePair("IMAGES", converted_image));
json = jsonParser.makeHttpRequest(url, "POST", nameValuePairs);
This is my PHP code to insert to oracle db
if(isset($_POST["TITLE"]) && isset($_POST["IMAGES"]))
{
$title = $_POST["TITLE"];
$image = $_POST["IMAGES"];
$gambar = file_get_contents($image);
$query = "INSERT INTO images (TITLE, IMAGES) VALUES (:TITLE, EMPTY_BLOB()) RETURNING IMAGES INTO :IMAGES";
$parse = oci_parse($connect, $query);
$lob_a = oci_new_descriptor($connect, OCI_D_LOB);
oci_bind_by_name($parse, ":TITLE", $title);
oci_bind_by_name($parse, ":IMAGES", $lob_a, -1, OCI_B_BLOB);
oci_execute($parse, OCI_DEFAULT);
if($lob_a->save($gambar))
{
oci_commit($connect);
$lob_a->free();
}
else
{
oci_rollback($connect);
}
}
The PHP code successfully insert the query to the oracle db, but when I see the record the blob does not show anything because the length of the blob is 0. I will appreciate any help. Thank you.
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Raditya Kurnianto wrote: I use PHP for my web service
This is Java forum.
Raditya Kurnianto wrote: PHP code successfully insert the query to the oracle db
Based on the code you posted I see nothing that suggests that you would know that.
As a guess, given I know nothing about php, I will note that I don't see anything at all that suggests that you actually put data in the blob. You created it, you saved it, but you didn't put any data in it.
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I want some details about java Scanners.
-Toywarrior
modified 21-Nov-20 21:01pm.
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This is a programming forum; you need Google. Or, you need to explain in better detail what problem you are trying to solve.
Use the best guess
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How to Send Mail From Application to Other Email such as Gmail,Yahoo using VB 6.0
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Appears to be your first post,
This is a java forum... Post question about VB in the appropriate forum[^], knowledgeable folks will be able to help.
Regrads,
Amitosh
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I'm making a program in which I want to process two methods at the same time.
I want to receive a file and then process it,,,when I'm processing my program should be able to receive another file.
I'm getting a problem,,I'm receiving a file and controlling it but when I'm getting file again its not receiving because,,My program is working in a sequence.
How can I make it to work parallel?
Thanks!
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I have a class which compares a set of times (using JodaTime Lib) to find the closest one to now:
public class TimeComparitor {
private List<LocalTime> targetTimes;
public TimeComparitor() {
targetTimes = new ArrayList<LocalTime>();
}
public void addTargetTime(LocalTime target) {
targetTimes.add(target);
}
public LocalTime getClosestFutureTarget(DateTime now) {
LocalTime result = null;
long resultOffset = Long.MAX_VALUE;
ArrayList<String> bigger = new ArrayList<String>();
for (LocalTime target : targetTimes) {
DateTime todayTarget = target.toDateTimeToday();
long differenceMillis = todayTarget.getMillis() - now.getMillis();
if (differenceMillis > 0 && differenceMillis < resultOffset) {
resultOffset = differenceMillis;
result = target;
}
}
return result;
}
As you see I could catch the closest time by getClosestFutureTarget method, But I not only want the closest one, but also an ordered list of all Times greater than now.
The question is: First, how to save them in a list? Should it be through getClosestFutureTarget ?
Second, to sort the list from closest to farthest I'm told to use something like this:
public class LocalTime implements Comparable<LocalTime> {
...
public int compareTo(LocalTime o){
}
} and then using Collections.sort . But not sure how to adapt it to my code.Just define this class in the same file for Previous class? Or creat a new class file? What should be inside class and where to call Collections.sort .
Thanks in advance
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Hello Gandhali,
The suggestion you got for sorting is partially right. The LocalTime class in JodaTime library implements the necessary compareTo method and hence no need to have a separate Comparable class. To sort your List of LocalTime objects all you have to do is to call the sort method of Collections class with a list of LocalTime objects.
In order to find all time values greater than now you can use code similar to one shown below.
int cntr = 0;
LocalTime curTime = new LocalTime();
Collections.sort(targetTimes);
for (LocalTime target : targetTimes) {
if (target.compareTo(curTime) >= 0) break;
cntr++;
}
List<LocalTime> ret = targetTimes.subList(cntr, targetTimes.size() - 1);
Regards,
Prasad P. Khandekar
Knowledge exists, man only discovers it.
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I am writing test code that prints an encrypted string to an underlying ByteArrayOutputStream, then code to decrypt the bytes from that stream into another string. Here is my code:
byte[] keyBytes, ivBytes;
final SecretKey key = new SecretKeySpec(keyBytes, "AES");
final IvParameterSpec iv = new IvParameterSpec(ivBytes);
final Cipher encrypt = Cipher.getInstance("AES/CBC/PKCS5Padding");
final Cipher decrypt = Cipher.getInstance("AES/CBC/PKCS5Padding");
encrypt.init(Cipher.ENCRYPT_MODE, key, iv);
decrypt.init(Cipher.DECRYPT_MODE, key, iv);
final ByteArrayOutputStream outBytes = new ByteArrayOutputStream();
final CipherOutputStream out = new CipherOutputStream(outBytes, encrypt);
out.write("This is a test, of course.".getBytes());
out.close();
final byte[] encryptedBytes = outBytes.toByteArray();
final ByteArrayInputStream inBytes = new ByteArrayInputStream(encryptedBytes);
final CipherInputStream in = new CipherInputStream(inBytes, decrypt);
final byte[] result = new byte[100];
final int byteCount = in.read(result);
System.out.print('"');
System.out.print(new String(result, 0, byteCount));
System.out.println('"');
For the above code, I expected the output to be "This is a test, of course.". However, I am getting the string, "This is a test, " (the final block is not being read). If I continue calling in.read(), I am able to get the remaining bytes out of the input stream, one byte at a time. This indicates (I think) that CipherInputStream is not simply catching and ignoring an invalid padding exception, which is what a few other posts I have found mentioned might be happening.
When I run the above code, the following two properties hold:
1. encryptedBytes.length == 32,
2. new String(decrypt.doFinal(encryptedBytes)) creates a string with the expected value
My question is, how in the heck to I get the CipherInputStream to read these bytes, without reading them one at a time? Is this expected behavior?
Sounds like somebody's got a case of the Mondays
-Jeff
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