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Hi,
as d@nish said you could use System.Data.OleDb but for faster and easier work you should use some 3rd party component like GemBox spreadsheet component
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I got the solution
http://www.codeproject.com/KB/dotnet/ExportToExcel.aspx?
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hi all friends.i want to give 70-526 certification.for that i need some tutorials & question,dumps.so pls send me dumps to animashniit@gmail.com.
pls add subject your mail when u send the file to me.
animash
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Hi,
This is probably a good a starting place as any [^]
Hope that helps.
Alan.
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Try here: Preparation guide for 70-526[^]
Plus, unless you REALLY like spam, don't post your email address...
No trees were harmed in the sending of this message; however, a significant number of electrons were slightly inconvenienced.
This message is made of fully recyclable Zeros and Ones
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You know, any company worth working for, knows these things are useless and can quickly tell in interviews between programmers and people who got a certification by reading dumps
Christian Graus
Driven to the arms of OSX by Vista.
"! i don't exactly like or do programming and it only gives me a headache." - spotted in VB forums.
I can do things with my brain that I can't even google. I can flex the front part of my brain instantly anytime I want. It can be exhausting and it even causes me vision problems for some reason. - CaptainSeeSharp
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Christian, I saw a number of your sayings against certification, as Raja collected them in his answer:
Certification on .Net Web/Windows application[^].
I want to say I could not agree more. This is wasteful, useless, but perhaps it's only useful as a little easy revenue generator for Microsoft. And a way of detection of lousy companies, those requiring or encouraging certifications for job candidates. And this is no so harmless, this is a kind of erosion of the idea of real education.
But my point is simpler than that. I think we should not answer all those questions on certifications posted on the Q&A forum, for example. We should focus more on computer science and software development. And certifications in no more than bureaucracy built around development.
—SASergey A Kryukov
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hi all friends.i want to give 70-526 certification.for that i need some tutorials & question,dumps.so pls send me dumps to animashniit@gmail.com.
pls add subject your mail when u send the file to me.
animash
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Hi guys.
I have some data and I'm going to generate a Graph with Crystal Report !
Could you guide me, how I can accomplish it ?
Thanks a lot.
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Good Day!
I just have a problem that I would want to be addressed. This is with regards to using multiple webBrowser controls. As you can see, when I use multiple webBrowser controls, they tend to hang the application for a while.
I think this is a threading issue, but I am new to multithreading as well so I am looking for an easier way to fix this if possible. If not, please guide me on how I can fix this, so the webBrowser controls wont hang the application since it is important in my application to let the users manipulate the form while the webBrowser controls are running. Any ideas?
Any help will be greatly appreciated, thanx!
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hi there
im trying to connect to usb port with c#
i'm using the usb_lib
but i can't find my device (a simple D.O.K).
i try to loop the device_index from 0-1000
but i allways get the same strDevicePath seems to be the default one.
but i dont get the strDevicePath of the D.O.K
can anyone help???
thanks.
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My question boundaries in primitive data types, not object.
What is the differentation between Convert.ToInt32() and (int) casting ?
For example;
double test = 5.2;
int var1 = (int)test;
int var2 = Convert.ToInt32(test);
I know if I test variable initialize to 5.5
var1 = 5
var2 = 6
Another difference here?
Thanks...
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Yes there is. If you box the double value, then Convert would work but casting will not. This happens as (int) directly tries to convert test to int without unboxing.
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Convert.ToInt32 (and related int convertions) convert with banker's rounding whenever the argument is of type Decimal, float, or double. (i.e. if the input is between two integers, it returns the even integer.)
The (int) cast will only truncate - ie throw away the fractional part.
In addition, (int) will only work on numeric types while Convert.ToInt32 is overloaded to work with a wide range of data types.
No trees were harmed in the sending of this message; however, a significant number of electrons were slightly inconvenienced.
This message is made of fully recyclable Zeros and Ones
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Person is my class, it contains just get and set property.
What is the diffirentation between following;
Stack stack = new Stack();
Stack<Person> stack = new Stack<Person>();
Already Stack get object type. Why I use <person>
Thanks...
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Hi,
since .NET 2.0 we have "generics", so collections can be typed, making it unnecessary to cast when something is gotten from a collection.
When you used to do int a0=(int)myList[0]; (where myList is an old ArrayList), you now can do int a0=myList[0]; where myList is a List<int>. That is easier, safer and faster.
Luc Pattyn [Forum Guidelines] [My Articles]
The quality and detail of your question reflects on the effectiveness of the help you are likely to get.
Show formatted code inside PRE tags, and give clear symptoms when describing a problem.
modified on Sunday, July 5, 2009 7:32 AM
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Sorry, I cant understand your example, both of theme same. My question related about stack and generic stack.
Best Regards...
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typo fixed, sorry.
Luc Pattyn [Forum Guidelines] [My Articles]
The quality and detail of your question reflects on the effectiveness of the help you are likely to get.
Show formatted code inside PRE tags, and give clear symptoms when describing a problem.
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To add to what Luc says, it also makes it harder to use the list badly. With the earlier Stack, you could happily say:
Stack li = new Stack();
li.Push(42);
li.Push("Hello");
without complaint.
with the generic lists if you try the same thing:
Stack<int> li = new Stack<int>();
li.Push(42);
li.Push("Hello");
the compiler will complain that you can't add a string to the stack.
No trees were harmed in the sending of this message; however, a significant number of electrons were slightly inconvenienced.
This message is made of fully recyclable Zeros and Ones
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Hi, I am writing a background application witch you can drop in the autostart of Windows. The application has to work fully in background and should not show the form at startup.
Question: If I write "this.Hide();" just behind the automatically created codeline "InitializeComponent();" in the main form, but the program anyway shows the form!
It looks, like "Application.Run(new MainForm());" shows the form again, but I can't do anything against!?
MainForm.cs:
public MainForm() {
InitializeComponent();
this.Hide();
}
program.cs
static void Main() {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
-> Application.Run(new MainForm());
}
Thanks for every help.
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Hi Javango,
I've also had this problem. And have found an alternative way of 'hiding' the form. By using:
this.Visible = false;
And to show the Form again, use:
this.Visible = true;
Hope this helps.
Regards,
Jase.
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Hi, thanks for your answer. I tried with "this.Visible" but unfortunatly this doesn't helps. As I think, this is exactly the same as you use the method.
Anyway, if the method run() is overwriting the Visible property (as i think) it would be hided and showed again.?
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Javango wrote: run() is overwriting the Visible property (as i think)
Okay, so where did you paste the
this.Visible = false; code? It should be placed inside the Form1_Load event if you want to hide the form at startup, like so:
private void Form1_Load(object sender, EventArgs e)
{
this.Visible = false;
}
If that's how you've used the code and it doesn't work then maybe you could try replacing:
this.Visible = false;
with this:
Form.ActiveForm.Visible = false;
OR;
If you believe that the run() method is overwriting the Visible property then maybe you could try hiding the Form once it's been shown. You can do this by creating a Form1_Shown event handler and using the same code provided above.
Hope this helps.
Jase.
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Hi, ok the setting in Form1_Load() didn't work too, but i solved it now with the Shown event (although I don't like workarounds like this):
private void MainForm_Shown(object sender, EventArgs e) {
if (!started) this.Hide();
started = true;
}
Thank's for your answers.
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