Re: getting binary resources - C# Discussion Boards

Show some specific region of form

1-Apr-04 5:31

In addition to what Mazdak said about using the SqlCommand.Parameters dictionary to refer to parameters by name, it is faster and far better to save the params as variables when you add them and use those variables to refer to them later. No lookups in the Parameters dictionary are needed, then.

See the example[^] I wrote just yesterday.

Microsoft MVP, Visual C#
My Articles

TreeView copy

Ata Özçelik1-Apr-04 2:19

Ata Özçelik

1-Apr-04 2:19

Hi there ,
I have a question about the treeview control in .NET.
In my first form I create nodes dynamically.
In my second form I want to show the tree exactly like in the first form.
When I try to pass the treeview like this :

Form2 frm2 = new Form2();
frm2.treeView1 = this.treeView1;

I can see the nodes (when debugging and using quickwatch) of the new tree which are the same of the form1's tree.
The problem is that I cannot display them. Anyone to help me pls?

Re: TreeView copy

Dave Kreskowiak1-Apr-04 3:32

Dave Kreskowiak

1-Apr-04 3:32

Your passing a reference to the first Treeview control, your not copying it. In fact, you CAN'T copy a Treeview control. The Nodes property of the Treeview is read only, so your are limited to recursively walking through the Nodes tree on your first Treeview and using the second Treeview's Add method to add the Nodes to the second tree.

RageInTheMachine9532

Itanium1-Apr-04 0:42

Itanium

1-Apr-04 0:42

Hi All!!!
I want to show only the shape of my form which i specify e.g. i would liek to draw a form like triagle or in circle or any opolygon. How would i do that rest of the form becomes transparent and only this portion is shown?

Thanx in advance Smile | :)

sorry for my bad English.

Re: Show some specific region of form

Dave Kreskowiak1-Apr-04 2:23

Dave Kreskowiak

1-Apr-04 2:23

You can start by reading up on non-rectangular forms here[^].

RageInTheMachine9532

getting binary resources

mhmoud rawas31-Mar-04 23:49

mhmoud rawas

31-Mar-04 23:49

i have the following code, this code will fetch me the http text only without the pictures so how can i get the pictures

<br />
WebProxy proxyObject = new WebProxy();<br />
<br />
// Disable Proxy use when the host is local i.e. without periods.<br />
proxyObject.BypassProxyOnLocal = true;<br />
// Now actually take over the global with our new settings, all new requests<br />
// use this proxy info<br />
GlobalProxySelection.Select = proxyObject;<br />
WebRequest req = WebRequest.Create(url);<br />
WebResponse result = req.GetResponse();<br />
Stream ReceiveStream = result.GetResponseStream( ) ;<br />
//Encoding encode = System.Text.Encoding.GetEncoding("utf-8");<br />
StreamReader sr = new StreamReader( ReceiveStream ) ;<br />
//Console.WriteLine("\r\nResponse stream received");<br />
Char[] read = new Char[256];<br />
int count = sr.Read( read, 0, 256 );<br />
//Response.WriteLine("HTML...\r\n");<br />
while ( count > 0 ) <br />
{<br />
	String str = new String(read, 0, count);<br />
	Response.Write(str);<br />
	count = sr.Read(read, 0, 256);<br />
}<br />

Mhmoud Rawas
------------
Software Eng.

Re: getting binary resources

Heath Stewart1-Apr-04 5:28

1-Apr-04 5:28

Use regular expressions or complex string comparisons (obviously, the former is recommended) to find all supported attributes for linked content, such as SRC and HREF (in a LINK element, not an A element). If a BASE is in the header, be sure to resolve the URLs with that, otherwise use the current directory of the HTML document. Combine the absolute and relative paths (the Uri constructor does a good job of this, so see the Uri class documentation) and then download the content.

FYI, it may be much easier to read this into an IHTMLDocument2 and use MSHTML to save it for you, since it intrinsically knows all the linked content. See Reusing MSHTML[^] for more information. Experience with COM will be helpful.

Microsoft MVP, Visual C#
My Articles

Object Properties

David Thaba31-Mar-04 22:01

David Thaba

31-Mar-04 22:01

How do you show properties of an object in a object collection editor,
eg. Panels collection???

Re: Object Properties

Dave Kreskowiak1-Apr-04 2:31

Dave Kreskowiak

1-Apr-04 2:31

You'll have to ellaborate a little on this...

Are you talking about DesignTime or RunTime?

Are you looking at extending the VS.NET Environment to include your own custom property UI Editor?

RageInTheMachine9532

save datagrid

bertcox31-Mar-04 20:42

31-Mar-04 20:42

How come this doesn't work? He doesn't save the data you edit in the datagrid Confused | :confused:

Thx in advance!

private void comboBox1_SelectedIndexChanged(object sender, System.EventArgs e)
{ //get the node out of the xml-file
string pad = "//school[@naam='" + comboBox1.SelectedItem.ToString() + "']";
XmlDocument xml = new XmlDocument();
xml.Load(@"c:\nodes.xml");
XmlNodeList contactNodes = xml.SelectNodes(pad);
string box = contactNodes.Item(0).OuterXml;
//write the node to a new file so it can be loaded into a dataset
xml.LoadXml(box);
XmlTextWriter xmltw = new XmlTextWriter(@"c:\testnodes.xml",new UTF8Encoding(false));
xml.WriteTo(xmltw);
xmltw.Close();

DataSet ds = new DataSet();
ds.ReadXml(@"c:\testnodes.xml");
dataGrid1.DataSource = ds;
dataGrid1.DataMember = "school";
}

private void button1_Click(object sender, System.EventArgs e)
{
ds.WriteXml(@"c:\testnodes.xml");
}

rull31-Mar-04 21:46

rull

31-Mar-04 21:46

Call dataGrid1.DataBind() function after setting DataSource property.

bertcox31-Mar-04 21:54

31-Mar-04 21:54

it sais that function doesn't exist

'System.Windows.Forms.DataGrid' does not contain a definition for 'DataBind'

DataBindings is in the list but i don't know how to use that

anyway thx for your answer

rull31-Mar-04 22:20

rull

31-Mar-04 22:20

Sorry DataBind is for Asp.Net datagrid

DataSet ds = new DataSet();
ds.ReadXml(@"c:\testnodes.xml");
dataGrid1.SetDataBinding(ds, "school");

You can find it here

bertcox31-Mar-04 22:42

31-Mar-04 22:42

thx! i tried it but it still doesn't save the data in the datagrid Unsure | :~

rull31-Mar-04 22:57

rull

31-Mar-04 22:57

In your code you always write testnodes.xml file getting info from nodes.xml on comboBox1_SelectedIndexChanged. So you read data from one file, select, and than write to another file?(button1_Click).

bertcox31-Mar-04 23:14

Customizing .NET TreeNode

31-Mar-04 23:14

yes that's right,
later on i will take the node from testnodes.xml en place it back into nodes.xml

Prasad Anand31-Mar-04 17:14

Prasad Anand

31-Mar-04 17:14

Hello,

I have a question of customizing the tree node of .NET FrameWork.
How can I add a picture box to treenode towards right side of the
treenode text.
Bye.

Re: Customizing .NET TreeNode

Heath Stewart31-Mar-04 17:38

31-Mar-04 17:38

This is an incredibly difficult task because the TreeView is responsible for drawing the entire surface, not like pieces of it like a ListView. Like other controls, the TreeView encapsulates its common controls equivalent, namely the Tree-View. This class was not designed with owner drawing in mind.

Many attempts have been made to owner draw the tree, but none are very good at all. You're much better off using a third-party control like that from http://www.infragistics.com[^] (UltraWinTree). We use it for our products and it's very extensible with a drawing model that's easy to extend.

Microsoft MVP, Visual C#
My Articles

MessageBox

DucLinh31-Mar-04 15:41

DucLinh

31-Mar-04 15:41

I want to know how to change the font, or size of MessageBox.
Help me please.
Thanks in advance.

Mr Duc Linh Nguyen

Re: MessageBox

Heath Stewart31-Mar-04 17:40

How to set splitter position

31-Mar-04 17:40

You can't, not without changing the system font. It encapsulates native calls, namely the MessageBox native API.

If you want a different look, create your own Form and make it work similarly if you like.

Microsoft MVP, Visual C#
My Articles

yu-yu31-Mar-04 14:48

yu-yu

31-Mar-04 14:48

Hello,

Now I develop a dialog included splitter control.
After moving splitter control, I regist splitter location
in registry. In this case, I get location using splitter_moving event(SplitterEventArgs).
And I restart this dialog.
I set location. The following is setting code.
this.splitter1.Location = new Point(x,y);

But I couldn't.

I think this solution is no problem.
If you have some ideas, please tell me.

regards,

yu-yu

Re: How to set splitter position

Heath Stewart31-Mar-04 17:45