i got result but error method is call instead of success using ajax posting url

Question

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i have used this code for posting url and got the result but error method is call instead of Success.
can you please help me?

PHP

$.ajax({
      type: 'GET',
      url: SendUrl,
      data: 'Message+=',
      success: function (resp) {
          alert(resp);
      },
      error: function (e) {
          alert('Error: ' + e);
      }

  });

Posted 16-Jul-15 20:05pm

Jigs IT

Updated 16-Jul-15 20:12pm

Wendelius

v2

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Comments

F-ES Sitecore 17-Jul-15 3:13am

Use the browser's dev tools (f12) to look at the network traffic when you make the call, that might help you see what is happening and will show any errors that might be thrown.

Mohibur Rashid 17-Jul-15 3:27am

Your data is wrong. Try to get more detailed error.

Jigs IT 17-Jul-15 4:50am

so what actually i put in data ?

Mohibur Rashid 17-Jul-15 4:57am

Formatted URI; as example Message=I am Jigs ; the formatted URI would be
data:'Message=I%20am%20Jigs'

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ZurdoDev · Answer 1 · 2015-07-17T03:45:00

Solution 1

See http://api.jquery.com/jQuery.ajax/[^] for the proper error function. Your error function can accept these parameters:

JavaScript

error: function(jqXHR jqXHR, String textStatus, String errorThrown)

Then analyze jqXHR.responseText. That will give you the error.

Posted 17-Jul-15 3:45am

ZurdoDev