Equation not working?

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Hey!

I got 3 variables:
$avegagrpsalj (this has a value of 22,20)
$avegagrpinkop (this has a value of 22,76)
$avegagrpskop (this should get a value of -2,46 after the following equation):

--------------------------(22,2)--------------(22,76)-----------(22,2)
$avegagrpskop = (($avegagrpsalj - $avegagrpinkop)/$avegagrpinkop)*100;

If I do it on my calculator:

((22,2-22,76)/22,76)*100= -2,46

I know the variables avegagrpsalj & avegagrpinkop have the right values because I do this at the end:

PHP

echo $avegagrpsalj;
echo "<br>";
echo $avegagrpinkop;
echo "<br>";
echo $avegagrpskop;

This keeps showing the value of $avegagrpskop to -3,34 instead of -2,46. I can't figure out why? :S

Posted 7-Oct-15 11:44am

Member 12039355

Updated 7-Oct-15 11:46am

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CHill60 7-Oct-15 18:41pm

only thing I can suggest is to break the calculation down even further e.g.
$a = $avegagrpsalj - $avegagrpinkop
$b = &a / $avegagrpinkop
$c = $b / 100
See which bit goes wrong

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Sergey Alexandrovich Kryukov · Answer 1 · 2015-10-07T13:24:00

Here is why: you are way too sloppy, sorry.
Look, you only imagined that $avegagrpinkop is 22.76 and $avegagrpinkop is 22.2. It cannot be so, because this is exactly one variable. Probably you assign to $avegagrpinkop something, and then something else.

Look, you did not even show the fragment of your code. Besides, your picture with "---(22,2)..." contradicts your description and an expression below, take a look.

Believe me, it's disgusting to answer such "questions". All you need it some attention and patience. Also, the way you name variables plays destructive role. And in decent languages where the variables are required to be declared, such things simply cannot happen.

—SA