How to fetch the node values from an Xml in the fastest manner ?

As Sergey Aleksandrovich Kryukov[^] mentioned it depends on file size. For small portion of data the difference measured in time of reading xml file is unnoticeable, even if you use Linq to xml[^].

Imagine, an xml structure looks like:

Root
--Level1
  |--Level2
    |--Level3
      |--Level4
        |--Level5
          |--Level6
            |--Level7
              |--Level8

You want to get nodes (data) from node at Level8, so you can achieve that using query like this:

XDocument xdoc = XDocument.Load("fullfilename.xml");
var result = xdoc.Descendants("Level8")
    .Descendants()
    .Select(a=>a);

For further information, please see:
LINQ to XML[^]
LINQ to XML Overview[^]
Basic Queries (LINQ to XML)[^]

node.SelectNodes("some XPath here");
This is fastest way to select node without looping concept.